I have a single profile page that I want to upload a photo on as a separate action. I have the first form submitting to the page successfully, it is when I submit the photo form that the page returns blank with an empty message.
HTML
<form method="post" action="profile.php" id="main">
<input name="txtFirstName" type="text" value="<?php echo $sFirstName; ?>">
<input type="submit" name="btnSubmit" value="Submit" />
</form>
<form method="post" action="profile.php" id="photo_upload" enctype="multipart/form-data">
<img src="<?php echo($sPath); ?>" height='100' width='100' id="imgProfile" />
<br>
<input type="file" name="fUpload" id="fUpload">
<br>
<input type="submit" name="btnUploadPhoto" value="Upload" class="cancel"/>
</form>
PHP
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
if ($_POST['btnSubmit']) {
$sFirstName = $_POST['txtFirstName'];
}
else if ($_POST['btnUploadPhoto']) {
// DO MY MOVE LOGIC
}
}
When the "btnSubmit" is called the page loads and the textbox gets the name that was entered. When the "btnUploadPhoto" is called I get this on the screen and nothing else:
{error: '', msg: '' }
How do I get the page to reload with the original form?
As you are uploading a file, you will want to check if a file has been submitted in your PHP code. Here is the code to do this:
isset($_FILES['fUpload'])
Related
I have two PHP files: index.php with a form, and data.php for further data manipulation.
Here is index.php:
<?php
session_start();
require_once("../index.conf");
$language = new Language();
$lang = $language->getLanguage(#$_POST['lang']);
?>
...
<form name="myForm" action="data.php" method="post" onsubmit="return validateForm()">
<input type="text" name="title" placeholder="e.g.: my_title" value="<?php echo isset($_POST['title']) ? $_POST['title'] : '' ?>">
...
<button class="btn_r" name="submit" type="submit">
<?php echo $lang['submit-button']; ?>
</button>
Here is data.php:
// success message
echo sprintf('
<div class="success">Good job! Your file <em>'.$file.'</em> was successfully created with this HTML content:<br>
<form name="goto_preview" method="post">
<input type="hidden" name="img_title" value="'.$title.'">
<button class="btn_l" name="reset" type="submit" name="logout" formaction="preview.php">PREVIEW RESULTS</button>
<button class="btn_r" name="submit" type="submit" name="continue" formaction="index.php">CORRECT DATA</button>
</form>
</div>',$img_name);
I try to return the user to the form, with the original values filled in if correction is needed. But the form always opens empty. What is wrong with my code?
Nothing is wrong with your code. That's just the way php forms work, you're redirecting to a new page therefore the form isn't filled out. To change that you could pass the POST arguments that you receive in the data.php and pass them back to index.php where you set them as default values (if present)
would it be possible to have a html/php template on index.php say for example (a news webpage template and then anyone can edit the title, paragraphs only, then on submit it then sends the webpage with the data stored to a paste bin like url so who ever visits that url say http://localhost/news/jjeh3bndjks they would only be able to view to content and not edit.
I would like to use something like this
<?php
if ($_POST) {
$pasteID = uniqid();
$paste = fopen("pastes/".$pasteID.".php", "w");
$contents = $_POST['pasteContents'];
fwrite($paste, $contents);
header('Location: /pastes/'.$pasteID.'.php');
}
?>
<form action="" method="POST">
<input type="text" name="pasteContents" placeholder="write here" />
<button type="submit" tabindex="0">submit</button>
</form>
but for some reason when i add another input box or try to send anymore data it fails or just gives me the last input given is there a way to send a whole page this way?
any help would be appreciated
You can use file_get_contents with the following code:
<?php
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
parse_str(file_get_contents('php://input'));
echo param1 . '<br />' . param2;
} else {
?>
<form method="post">
<input type="text" name="param1" value="param1" />
<input type="text" name="param2" value="param2" />
<input type="submit" value="submit" />
</form>
<?php } ?>
(You can test it here)
Although, I did success to use $_POST too:
<?php
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
echo $_POST['param1'] . '<br />' . $_POST['param2'];
} else {
?>
<form method="post">
<input type="text" name="param1" value="param1" />
<input type="text" name="param2" value="param2" />
<input type="submit" value="submit" />
</form>
<?php } ?>
Here
I updated the question.
Since the last code was pretty complex and even after fixing the stuff it didn't work, I executed the below simple code to check if things work. Even this code doesn't work. Whenever I click on the submit button, it again returns a 404 error.
Yes, I placed the PHP code in the body as well to check if this work but it doesn't.
<?php
if(isset($_POST['submit'])) {
echo("Done!!!!");
} else {
?>
<html>
<head>
<title>Echo results!</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
<input name="submit" type="submit" value="submit"/>
</form>
<?php
}
?>
</body>
</html>
Try giving the button_create as name of the submit button
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
if(isset($_POST['button_create'])) {
<td><input type="submit" name="button_create" id="button_create" value="Create Table!"></td>
change these lines see how you go from there
There are a couple of things wrong here, method should be POST instead of GET. The name attribute of text fields should be used when receiving the values. The submit button name should be used to check whether the button is clicked or not. See the example given below.
<?php
if (isset($_POST['submit'])) {
$ex1 = $_POST['ex1'];
$ex2 = $_POST['ex2'];
echo $ex1 . " " . $ex2;
}
?>
<form action="" method="post">
Ex1 value: <input name="ex1" type="text" />
Ex2 value: <input name="ex2" type="text" />
<input name="submit" type="submit" />
</form>
Echo results!
<?php
if(isset($_POST['submit'])) {
echo("Done!!!!");
} else {
?>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
<input name="submit" type="submit" value="submit"/>
</form>
<?php
}
?>
this is for your updated question
<form id="form" name="form" method="post" action="">
<div class="jquery-script-clear"></div>
<h1>BARCODE GENERATOR</h1>
<div id="generator"> Please fill in the code :
<input type="text" name="barcodeValue" id="barcodeValue" value="1234"><br> <br>
</div>
<div id="submit">
<input type="button" onclick="generateBarcode();" value=" Generate "> <input type="button" onclick="printDiv('print')" value="Print" />
</div>
</form>
<?php
$barcodeValue = $_POST["barcodeValue"];
$save = file_get_contents("save.txt");
$save = "$barcodeValue" . $save;
file_put_contents("save.txt", $save);
echo $save;
?>
sample picture
How to save the input data in save.txt file. When i clicked generate button the text file not showing in same folder.
The problem with your code is you have no submit button so your form was not actually posting when you pressed the button. if you look at my edits you can see I changed the button from input type="button" to type="submit". That allows for the form to submit back to the same php script.
Your script also was causing errors because you accessed $_POST["barcodeValue"] without checking if it existed. You also have to check if the save.txt exists before reading from it. If analyze my edits you can see how checking if the variables are available will help quite a bit.
<form id="form" name="form" method="post" action="">
<div class="jquery-script-clear"></div>
<h1>BARCODE GENERATOR</h1>
<div id="generator"> Please fill in the code :
<input type="text" name="barcodeValue" id="barcodeValue" value="1234"><br> <br>
</div>
<div id="submit">
<input type="submit" value=" Generate ">
</div>
</form>
<?php
if(isset($_POST["barcodeValue"]))
{
$barcodeValue = $_POST["barcodeValue"];
if(file_exists("save.txt"))
$save = file_get_contents("save.txt");
else
$save = "";
$save = $barcodeValue . $save;
file_put_contents("save.txt", $save);
echo $save;
}
?>
Let me know if you need more help
So, I have a form with two input elements: one to upload a file, and the other, a hidden input. Here it is:
<form action="upload.php" method="POST">
upload: <input enctype="multipart/form-data" name="pp" accept="image/png" type="file">
<input type="submit" value="go" />
<input type="hidden" name="eup" />
</form>
on my "upload.php" page (which is a different page), I get the undefined index error. Here's the code for that:
<?php
session_start();
if(isset($_POST["eup"])){
$fERR=false;
if(isset($_FILES["pp"])){ // undefined index error comes if this IF is removed...
$aExts = array("png");
$temp = explode(".", $_FILES["pp"]["name"]);
$tEXT = end($temp);
if ((($_FILES["pp"]["type"]=="image/x-png")
|| ($_FILES["pp"]["type"]=="image/png"))
&& ($_FILES["pp"]["size"]<300000)
&& in_array($tEXT, $aExts)){
if ($_FILES["pp"]["error"]>0){
$ppERR=true;
}
else{
// handle file upload here
}
}
else{
$fERR=true;
}
}
else{
$fERR=true;
}
if($fERR==true){
echo "ERROR";
}else{
echo "GOOD TO GO";
}
}
echo "<br />".ini_get("file_uploads");
?>
I've looked at a bunch of other posts and websites discussing this topic, but none of the solutions worked for me.
by the way, the output of that php is:
ERROR
1
<form action="upload.php" method="POST" enctype="multipart/form-data">
upload: <input name="pp" accept="image/png" type="file">
<input type="submit" value="go" />
<input type="hidden" name="eup" />
</form>