Trying to get property of non-object in OOP php [duplicate] - php

Question

This question already has answers here:
Call to a member function on a non-object [duplicate]
(8 answers)
Closed 9 years ago.
I just want to back my class properties so that I can use them. In my project I want to fetch all result of mysql table data and return it. Well it works well, but alter returning data the error message has come which is given below:
Trying to get property of non-object in E:\xampp\htdocs\myProject\new_27_03\login_con.php on line 26
My code ::
nonClass.php
<?php
$doc = new Dortor(); // object
$doc->result("SELECT * FROM doctor"); // function call
foreach( $doc as $doctor ) {
echo $doctor->doc_name; // error msg: Trying to get property of non-object in
//E:\xampp\htdocs\myProject\new_27_03\login_con.php on line 26
}
?>
dortor.php
<?php
class Dortor extends DatabaseObject {
public $table_name = "doctor";
public $id;
public $doc_name;
public $doc_pass;
public $doc_img; // image directory
public function result($sql="") {
$result = $database->query($sql); // run query from mysql database
$result_array = array();
while( $row = $database->fetch_array($result) ) { // this while loop return actual result
$result_array[] = $this->get_table_value($row);
}
return $result_array;
}
}
?>
databaseObject.php
<?php
class DatabaseObject {
public function get_table_value($record) {
$className = get_called_class(); // get the class name
$object = new $className; // object call
$arrayValue = array();
$i=0; // inital array position
foreach( $object as $key => $value ) {
$arrayValue[$i] = $key; // get the class's object attributes
$i++;
}
$i = 1;
foreach ($record as $key => $value) { // fetch the database result
if(array_key_exists($key, $arrayValue) ) { // check if database's column name is exist on 'arrayValue' array,
$object->$arrayValue[$i] = $value; // if exist then, store value in 'Doctor' class's object attributes
$i++;
}
}
return $object;
}
}
?>

Answer 1

Your error is probably here:
$doc = new Dortor(); // object
$docs = $doc->result("SELECT * FROM doctor"); // you forgot to assign the result
foreach ($docs as $doctor) { // was looping over $doc here, instead of the result
echo $doctor->doc_name;
}

Answer 2

It would also make sense to check the correct variable type before the foreach loop starts:
if ( is_array( $doc) )
{
foreach( $doc as $doctor )
{
// foreach code
}
}
else
{
echo '$doc is no valid object';
var_dump($doc);
}
So you can find out, that's the problem.