I have session variables that are posted from a form on another php page, and I can echo them by using:
<?php $_SESSION['newsletterSignup'] = $_POST['newsletterSignup'];
echo "Email = ". $_SESSION['newsletterSignup'];
?>
But I can't seem to insert these into a HTML form field:
<input type="text" name="email" id="email" size="36" "value="<?php echo $_SESSION['newsletterSignup'];?>" class="text-input" onBlur="emailval()" />
This should work...the quote before value was probably screwing it up
<input type="text" name="email" id="email" size="36" value="<?php echo $_SESSION['newsletterSignup'];?>" class="text-input" onBlur="emailval()" />
you use
<input type="text" name="email" id="email" size="36" "value="<?php echo $_SESSION['newsletterSignup'];?>" class="text-input" onBlur="emailval()" />
A " to many. Here is the fix
<input type="text" name="email" id="email" size="36" value="<?php echo $_SESSION['newsletterSignup'];?>" class="text-input" onBlur="emailval()" />
Also, did you use session_start(); ?
Related
I try send value of input to the server, but in server I receive NULL of variable front side:
<form method="POST" action="validationUploadEmployee.php" style="border:1px solid #ccc">
<div class="container">
<input type="number" placeholder="Enter ID" name="idW" value = '<?php echo "$idW"; ?>' disabled="disabled" required >
<input type="text" placeholder="Enter Full Name" name="name" value = '<?php echo "$nameE"; ?>' required>
<input type="email" placeholder="Enter Email" name="email" value='<?php echo "$emailE"; ?>
<input type="text" placeholder="Enter Password" name="psw" value='<?php echo "$passwordE"; ?>' maxlength="10" size="8" required>
<input type="text" placeholder="Repeat Password" name="psw-rpt" value='<?php echo "$passwordE"; ?>' maxlength="10" size="8" required>
<input type="number" placeholder="Enter Number Phone" name="phone" value='<?php echo "$phoneE"; ?>' required>
<input type="text" placeholder="" name="branch" value='<?php echo "$myBranch"; ?>' disabled="disabled" required>
server side I receive variable like that:
$idW=$_POST['idW'];//id worker
Thank you.
<form method="POST">
<h1>Enquiries</h1>
<span><h2 class="required">*Required</h2></span>
<div class="input-group">
<label class="sr-only">Firstname</label>
<input class="text" type="text" name="name" value="<?php print_r($username)?>" />
</div>
<label class="sr-only">Lastname</label>
<input class="text" type="text" name="Lastname" placeholder="*" required>
<label class="sr-only">Email</label>
<input class="text" type="text" name="email" placeholder="">
<label class="sr-only">Subject</label>
<input type="text" name="password" class="text" placeholder="*">
<label for="inputPassword" class="sr-only">Comment:</label>
<textarea id="text" placeholder="Write something..." required> </textarea>
<input type="submit" action="submit.php">
I need to input my $username into the firstname input field. How can I set the automatic value to be $username When a logged in user goes to send an enquiry.
<input class="text" type="text" name="name" value="<?php echo isset($username) ? $username : '' ?>" />
You need to use echo instead of print_r. Also check if the variable exists.
<input class="text" type="text" name="name" value="<?php echo !empty($username) ? $username : ''; ?>" />
Just try this
<input class="text" type="text" name="name" value="<?= $username ?>" />
Will fix it if the variable username has been initialized prior
Trying to get an edit page to work and im getting this error Incorrect parameter count in the call to native function 'SHA1'. The error is only on the SHA1. everything else works fine other then this error. Any helped is greatly appreciated. I don't want the password showing or the encryption that is to stay blank as it is an admin editing a staff members details and they dont need to know the password.
<?php
if(empty($_POST['submit'])) {
$query = "SELECT * FROM user WHERE user_id = '$_GET[id]'";
// $supplier_id = $_GET['supplier_id'];
$result = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($result);
}
else{
$update = "UPDATE user SET
title= '$_POST[inputtitle]',
first_name ='$_POST[inputfirst_name]',
middle_name = '$_POST[inputmiddle_name]',
last_name = '$_POST[inputlast_name]',
gender = '$_POST[inputgender]',
email = '$_POST[inputemail]',
pass = SHA1($_POST[inputSHA1pass]);
car_make = '$_POST[inputcar_make]'
car_model = '$_POST[inputcar_model]',
prefer_car = '$_POST[inputprefer_car]',
car_age = '$_POST[inputcar_age]',
st_no = '$_POST[inputst_no]',
st_name = '$_POST[inputst_name]',
suburb = '$_POST[inputsuburb]',
state = '$_POST[inputstate]',
country = '$_POST[inputcountry]',
postcode = '$_POST[inputpostcode]',
WHERE user_id = $_POST[user_id]";
mysqli_query($dbc, $update) or die(mysqli_error($dbc));
echo "User has been modified!";
header("Location: view_user.php");
}
?>
<form action="<?php echo $_SERVER['PHP_SELF'].htmlspecialchars($_GET[‘id’]); ?>" method="POST">
<input type="hidden" value="<?php echo $supplier = $_GET['id']; ?>" name="supplier_id">
<p>Title:
<input type="text" name="inputtitle" size="20" maxlength="30"
value="<?php echo $row["title"]; ?>"/>
</p>
<p>First Name:
<input type="text" name="inputfirst_name" size="20" maxlength="30"
value="<?php echo $row["first_name"]; ?>"/></p>
<p>Middle Name:
<input type="text" name="inputmiddle_name" size="30" maxlength="100"
value="<?php echo $row["middle_name"]; ?>"/></p>
<p>Last Name:
<input type="text" name="inputlast_name" size="20" maxlength="30"
value="<?php echo $row["last_name"]; ?>"/></p>
<p>Gender:
<input type="text" name="inputgender" size="20" maxlength="30"
value="<?php echo $row["gender"]; ?>"/></p>
<p>Email:
<input type="text" name="inputemail" size="10" maxlength="5"
value="<?php echo $row["email"]; ?>"/>
</p><br>
<p>Password:
<input type="text" name="inputSHA1pass" size="30" maxlength="40"
value="<?php if (isset($_POST['pass'])) echo $_POST['pass']; ?>"/></p>
<p>Car Make:
<input type="text" name="inputcar_make" size="20" maxlength="30"
value="<?php echo $row["car_make"]; ?>"/></p>
<p>Car Model:
<input type="text" name="inputcar_model" size="20" maxlength="30"
value="<?php echo $row["car_model"]; ?>"/></p>
<p>Prefered Car:
<input type="text" name="inputprefer_car" size="20" maxlength="30"
value="<?php echo $row["prefer_car"]; ?>"/></p>
<p>Car Age:
<input type="text" name="inputcar_age" size="20" maxlength="30"
value="<?php echo $row["car_age"]; ?>"/></p>
<p>Street Number:
<input type="text" name="inputst_no" size="20" maxlength="30"
value="<?php echo $row["st_no"]; ?>"/></p>
<p>Street Name:
<input type="text" name="inputst_name" size="20" maxlength="30"
value="<?php echo $row["st_name"]; ?>"/></p>
<p>Suburb:
<input type="text" name="inputsuburb" size="20" maxlength="30"
value="<?php echo $row["suburb"]; ?>"/></p>
<p>State:
<input type="text" name="inputstate" size="20" maxlength="30"
value="<?php echo $row["state"]; ?>"/></p>
<p>Country:
<input type="text" name="inputcountry" size="20" maxlength="30"
value="<?php echo $row["country"]; ?>"/></p>
<p>Postcode:
<input type="text" name="inputpostcode" size="20" maxlength="30"
value="<?php echo $row["postcode"]; ?>"/></p>
<p>
<input type="submit" name="submit" value="Submit"/></p>
</form>
<?php
mysqli_close($dbc);
?>
<br>
<br>
</div>
<br>
<?php
include ('../includes/footer.php');
?>
A few things:
Check that $_POST['inputSHA1pass'] is not empty
Enclose $_POST[inputSHA1pass] in quote marks and curly braces: SHA1('{$_POST[inputSHA1pass]}'). SHA1() expects a string and will error without one
Look into prepared statements. As this code stands, it is wide open to SQL injection attacks as none of your passed data is checked for validity
Change the semi-colon to a comma in the SHA1 line
Finally, once the UPDATE query has been built, capture it and try running it directly on the database server. It should give you a more meaningful error message and make debugging easier
if(isset($_POST['submit'])){
$domain=$_POST['domain'];
$fname=$_POST['fname'];
$sname=$_POST['sname'];
$tel=$_POST['tel'];
if($domain==""){
$error="<h4>Enter Domain </h4>";
}elseif($fname == ""){
$error="<h4>Enter Firstname </h4>";
}elseif($sname == "")
{
$error="<h4 >Enter Surname</h4>";
}elseif($tel=="")
{
$error="<h4 >Enter telephono no</h4>";
}
else {
$sql11=mysql_query("INSERT INTO domain VALUES('','$domain','$fname','$sname','$tel','$mobile','$email','$company','$address','$city','$country','$pcode','$tele',
'$fax','$qus','$ans')");
echo $sql;
$db->query($sql);
}
}
<div><?php echo $error; ?></div>
<form action="" method="post" name="classic_form" id="classic_form">
<div><h4>Personal details:</h4></div><div style="margin-left: 109px;">
<div>Domain</div>
<input type="text" name="domain" id="domain" value="" />
<div>First name: </div>
<input type="text" name="fname" id="fname" value="" />
<div>Surname:</div>
<input type="text" name="sname" id="sname" value="" />
<div>Telephone:</div>
<input type="text" name="tel" id="tel" value="" />
<div>Mobile:</div>
</form>
In my registration page, i used php validation. After the user submit the form if it shows validation errors it also resets all the fields. How can i resolve this problem? Without reset the fields i have to show the php validation errors. I also used in each input value. But it shows
"Notice: Undefined index: domain in D:\xampp\htdocs\deena\domainreg.php on line 82" . Please help me to resolve this problem
<input type="text" name="domain" id="domain" value="<?php echo isset($domain) ? $domain : ''; ?>" />
You have to pass all your values to php, and send back to html to feed your fields.
Its not 'resetting your fields' .. Your form is being submitted, hence the page is being reset and fields are therefore loading empty. Place the $_POST[] values in the field values upon page load:
<input type="text" name="domain" id="domain" value="<?php echo $domain ?>" />
<div>First name: </div>
<input type="text" name="fname" id="fname" value="<?php echo $fname?>" />
<div>Surname:</div>
<input type="text" name="sname" id="sname" value="<?php echo $sname?>" />
<div>Telephone:</div>
<input type="text" name="tel" id="tel" value="<?php echo $tel?>" />
Simple. Just add the variables to the input values:
<input type="text" name="domain" id="domain" value="<?php echo $domain; ?>" />
You should also protect the outputted value, against cross site scripting:
<input type="text" name="domain" id="domain" value="<?php echo htmlspecialchars($domain); ?>" />
In the value field:
<input type="text" name="domain" id="domain"
value="<?php if(isset($_POST['domain'])){echo $_POST['domain'];} ?>">
Didn't test it. But i think it should work.
In input tag add the php value as like value="" So that it will echo if the variable is posted or it will show the empty one
I want to get value from php variable to review it in textbox
what I have to write in "value":
<input type="text" name="name3" size="25" maxlength="50" value=""> name:
<input type="text"
name="name3"
size="25"
maxlength="50"
value="<?php echo htmlspecialchars($variable); ?>">
<input type="text" name="name3" size="25" maxlength="50" value="<?php echo $variable; ?>">