php count grouped values - php

Question

I have searched around and have found many solutions to my question, but I am still having one problem. I am trying to create a table that will have four images per row. This has been done. I have told the script to group by rewardid and it does that so now duplicate images do not appear (the steps to do these I have found on the site). What I am having problems with is that I m trying to put a multiplier under each image to count how many was in each group. (i.e. Lets say I have 5 medals. On my page, it only shows one medal, but I really have 5, so I would like for it to say x5 below the image.) This is what I have so far:
print "<div class='style1'><br> <br><h2>User Medals</div></h3><br />
<table width='80%' class='table' border='0' cellspacing='1'><tr bgcolor='gray'><th></th><th></th><th></th><th></th></tr>";
$result=mysql_query("SELECT * FROM awardsearned WHERE userid=$userid group by rewardid");
$count = 0;
while($res=mysql_fetch_array($result))
{
$award = $res['rewardpic'];
$award2 = $res['rewardid'];
$result2=mysql_query("SELECT awardid, count(rewardid) FROM awardsearned WHERE rewardid=$award2 AND userid=$userid");
$count2 = count($result2);
if($count==4) //three images per row
{
print "</tr>";
$count = 0;
}
if($count==0)
print "<tr>";
print "<td>";
print "<center><img src='$award' width='100' height='100'/><br />x$count2</center> ";
$count++;
print "</td>";
}
if($count>0)
print "</tr>";
print "
</table>";
Sorry if this is messed up, never posted here before. Here it is on pastebin if needed http://pastebin.com/iAyuAAzV

Answer 1

Update your query like this:
SELECT *,COUNT(rewardid) no_of_rewards
FROM awardsearned WHERE userid=$userid group by rewardid
$res['no_of_rewards'] will hold your number.
This will also eliminate the need for the second query.
These things are called "aggregate functions". More in the documentation.

Answer 2

To answer your question:
The value of $result2 would only give TRUE(1) or FALSE(0). If your query executed correctly $count2 will return 1, therefore you always get 1 in your code.
Try and change
$result2=mysql_query("SELECT awardid, count(rewardid) FROM awardsearned WHERE rewardid=$award2 AND userid=$userid");
$count2 = count($result2);
TO:
$result = mysql_query("SELECT awardid, count(rewardid) FROM awardsearned WHERE rewardid=$award2 AND userid=$userid");
$arr = mysql_fetch_array($result);
$count2 = count($arr);
This should give you the actual numbes of records from the resultset.
There are better ways of doing this (look at Bart Friederichs answer!) , like doing only SELECT and loop through resultset once. This would be for performance and for flexibility.
Also take in my consideration that mysql_query is deprecated now, and should not be used. (The preferal methods are to use PDO or mysqli instead)