Converting jquery function from form submit to php array result - php

Question

I'm attempting to take the ImageResolver plugin and adapt it to work with a php array.
Stripping the code to this returns the image without a form:
$(function(){
var url = $('#url').val();
ImageResolver.resolve(url, function(image){
if (image) {
$('#result').html('<img src="' + image + '" alt="">');
} else {
$('#result').html('<h2>No image found</h2>');
}
});
});
I want to adapt it to work within a php foreach loop. results would be replaced on the next class='result' div. IE: after the page has loaded the urls from the query, the function will parse the url and return image link if one is found. I'm guessing I need to use (each) or this(), but I can't figure it out.
can someone point me in the right direction?

Answer 1

<script src="ImageResolver/URI.min.js"></script>
<script src="ImageResolver/ImageResolver.js"></script>
<?
$javascriptarray = 'var urls = [';
$counter=0;
foreach (array('http://www.apple.com/','http://github.com/','http://www.test.com/') as $url)
{
if ($counter++ > 0) $javascriptarray .= ',';
$javascriptarray .= '"'.$url.'"';
}
$javascriptarray .= '];';
?>
<script>
<?=$javascriptarray?>
//The ImageResolver will try all the resolvers one after the other
//in the order of their registration
//Resolvers that guess the image URL
ImageResolver.register(new FileExtensionResolver());
ImageResolver.register(new ImgurPageResolver());
ImageResolver.register(new NineGagResolver());
ImageResolver.register(new InstagramResolver());
//Resolvers that need extra ajax requests
ImageResolver.register(new ImgurAlbumResolver());
ImageResolver.register(new OpengraphResolver());
ImageResolver.register(new WebpageResolver());
//Some jQuery code to make the demo work
//Use a crossdomain proxy (required by some plugins)
$.ajaxPrefilter('text', function(options) {
options.url = "http://furious-stream-4406.herokuapp.com?src=" + encodeURIComponent(options.url);
});
$(function(){
var length = urls.length,
url = null;
for (var i = 0; i < length; i++) {
url = urls[i];
ImageResolver.resolve(url, function(image){
if (image) {
$('#result').append('<img src="' + image + '" alt=""><br>');
} else {
$('#result').append('<h2>No image</h2>');
//$('#result').append('<h2>No image found for ' + url + '</h2>');
}
});
}
});
</script>
Watch out cause ImageResolver.resolve() works asynchrone you can get unexpected results. Call ImageResolver.resolve() again before the previous call has finished will change url in $('#result').append('<h2>No image found for ' + url + '</h2>'); to the url of your last call by example. To prevent this you need to initialize a new Resolver in the for-loop. see: Javascript prototypes and instance creation