This question already has answers here:
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 3 years ago.
I got the following string:
last_name, first_name
bjorge, philip
kardashian, [kghim]
mer#$##Code:menu:51587daa7030e##$#cury some more
data #$##Code:menu:515r4387daa7dsf030e##$#, freddie
im trying to replace the Codes in the middle with the function: 'codeParser' the regex is:
$PC_File = preg_replace_callback("(?=\#\$\#\#).*?(?<=\#\#\$\#)", 'codeParser', $PC_File);
but getting this error:
PHP Warning: preg_replace_callback() : Unknown modifier '.'
You need to wrap your regular expression in delimiters. It's considering () to be the delimiters right now, and the . as a modifier (which is of course invalid).
"/(?=#\\$##).*?(?<=##\\$#)/"
(I'm also pretty sure the # do not need to be escaped unless you were using them as delimiters)
EDIT: You need \\ to properly escape the $ in double-quotes.
Related
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 3 years ago.
I got this error message:
Warning: preg_match(): Unknown modifier '/' in C:\xampp\htdocs\easyblog\wp-content\themes\easyblog\inc\widget\flickr.php on line 225
Source code in here :
// Screen name or RSS in $username?
if (!preg_match("/http://api.flickr.com/services/feeds/", $username))
$url = "http://api.flickr.com/services/feeds/photos_public.gne?id=".urlencode($user_id)."&format=".$flickrformat."&lang=en-us".$tags;
else
$url = $username."&format=".$flickrformat.$tags;
Can someone help me, please!
You need to escape the forward slashes in your expression:
"/http:\/\/api.flickr.com\/services\/feeds/"
When you use / delimiter, then you must escape all / character if used inside pattern, for avoiding this you can use another delimiter such as #
"#http://api.flickr.com/services/feeds#"
However, your pattern needs escaping:
"/http:\/\/api.flickr.com\/services\/feeds/"
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 3 years ago.
I'm not very knowledgeable with regular expresions, so I don't understand why I'm getting this error.
I'm using the following code to match all the emails in the string $str and saving them in the array $match:
preg_match_all(
"/^[a-zA-Z0-9.!#$%&’*+/=?^_`{|}~-]+#[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*$/",
$str,
$match
);
Apparently there's a problem in the regex (which I got from here) because I'm getting this error:
Warning: preg_match_all() [function.preg-match-all]: Unknown modifier
'=' in C:\xampp\htdocs\project\Framework\Sanitizer.class.php on
line 38
Can someone tell me what's the problem?
Thanks
You have to escape the forward slash before that equals sign, e.g:
preg_match_all(
"/^[a-zA-Z0-9.!#$%&’*+\/=?^_`{|}~-]+#[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*$/",
$str,
$match
);
"/" is the delimiter for the whole expression, so it must be escaped in the regex itself
You need to escape many of the characters in that string with a backslash.
Some of those you want to escape is: /?^{|} .
I would have written it like this:
preg_match_all(
"/^[a-zA-Z0-9.!#$%&’*+\/=\?\^_`\{\|\}~-]+#[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*$/",
$str,
$match
);
I find this site quite useful when it comes to matching e-mail adresses:
http://www.regular-expressions.info/email.html