Storing array in a variable - php

Question

I'm trying to replace the code below
$Palette = array(
"0"=>array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100),
"1"=>array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100),
"2"=>array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100),
"3"=>array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100),
"4"=>array("R"=>176,"G"=>46,"B"=>224,"Alpha"=>100),
);
with something similar but different values for the R, G and B. I have written the code below so far as a replacement:
$x = '0';
$incrementarray = array("0"=>"A","1"=>"B","2"=>"C","3"=>"D","4"=>"E");
do
{
if ($correct == $incrementarray[$x])
{
$colour[$x] = '"'.$x.'"=>array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100),';
}
else
{
$colour[$x] = '"'.$x.'"=>array("R"=>255,"G"=>51,"B"=>51,"Alpha"=>100),';
}
$x++;
}
while ($x <= '4');
$allcolours = $colour[0].$colour[1].$colour[2].$colour[3].$colour[4];
however, when I implement it into my script using the line below , it doesn't work.
$Palette = array($allcolours);

Answer 1

$x = '0';
$incrementarray = array("0"=>"A","1"=>"B","2"=>"C","3"=>"D","4"=>"E");
do
{
if ($correct == $incrementarray[$x])
{
$Pallete[$x] = array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100);
}
else
{
$Pallete[$x] = array("R"=>255,"G"=>51,"B"=>51,"Alpha"=>100);
}
$x++;
}
while ($x <= '4');

Answer 2

there is a little excessive usage of $x.
as a matter of fact, you don't need that variable at all
$Palette = array();
$incrementarray = array("0"=>"A","1"=>"B","2"=>"C","3"=>"D","4"=>"E");
foreach ($incrementarray as $value)
{
if ($correct == $value)
{
$Palette[] = array("R"=>188,"G"=>224,"B"=>46,"Alpha"=>100);
}
else
{
$Palette[] = array("R"=>255,"G"=>51,"B"=>51,"Alpha"=>100);
}
}
you need to create array, not the PHP code to create array.