table doesnt exist - php

Question

I have created a query that loops through a group of table ID's to get a sum of their combined values. with error handling i get a "Table 'asterisk.custom_' doesn't exist" error and the query is killed obviously. but if i remove the error handling then i get an "mysql_fetch_array() expects parameter 1 to be resource" and the query completes as it should.
Thank in advance for your help.
include("currentday.php");
//---used for testing passing variables
//echo $customID[0];
//echo "<br>".$numrows;
$i = 0;
while($i<=$numrows)
{
mysql_select_db("asterisk") or die(mysql_error()); //This line determines the database to use
$query = "SELECT
vicidial_users.user,
vicidial_users.full_name,
sum(vicidial_agent_log.pause_sec) as sumPause,
sum(custom_$customID[$i].d_amt) as sumDamnt,
sum(custom_$customID[$i].up_amt) as sumUpamnt,
sum(custom_$customID[$i].md_amt) as sumMdamnt,
sum(custom_$customID[$i].s_amount) as sumSamnt,
sum(vicidial_agent_log.dispo_sec)
FROM
vicidial_agent_log
INNER JOIN
vicidial_users
ON
(vicidial_agent_log.user = vicidial_users.user)
INNER JOIN
custom_$customID[$i]
ON
(vicidial_agent_log.lead_id = custom_$customID[$i].lead_id)
WHERE
vicidial_users.user = 'tcx'
GROUP BY
vicidial_users.full_name
ORDER BY
vicidial_agent_log.event_time DESC
";
$queryResult = mysql_query($query);// or die(mysql_error());
while ($rowResult = mysql_fetch_array($queryResult))
{
$pauseResult[] = $rowResult["sumPause"];
$sumdamntResult[] = $rowResult["sumDamnt"];
$sumupamntResult[] = $rowResult["sumUpamnt"];
$summdamntResult[] = $rowResult["sumMdamnt"];
$sumsamntResult[] = $rowResult["sumSamnt"];
}
//print_r($pauseResult);
//echo $pauseResult[0];
$i++;
}
Update:
The table exist in the database:
custom_2346579543413
custom_5466546513564
they are created by the dialer software and im calling them from another query that provides me the numeric part of the table name so this query loops through the values in customID array to make the query, Thanks again
Update:
Sammitch, thank you for the suggestion, however they did not work.
Solution:
Thanks Marc, you confirmed a suspicion i had in that it was looping correctly but for some reason it was looping more times that there we keys. so i echoed $i to confirm and in fact it was it was outputting 0,1,2,3 and since i know there is only 3 keys the last one didn't return anything and so error handling caught it and killed the entire loop and why it appeared correct when error handling was turned off. The solution was actually rather simple and it was in the while loop evaluation string i had used
while($i<=$numrows)
while($i<$numrows)//this worked, the equals part of that gave it an extra loop

Answer 1

and the query completes as it should.
No, it doesn't. "mysql_fetch_array() expects parameter 1 to be resource" means "the query failed, and you didn't bother to check before calling mysql_fetch_array()".
Your problem is that variable expansion inside of a string doesn't like array indexes. You need to change:
"sum(custom_$customID[$i].d_amt) as sumDamnt,"
To:
"sum(custom_{$customID[$i]}.d_amt) as sumDamnt,"
Or:
"sum(custom_" . $customID[$i] . ".d_amt) as sumDamnt,"
For it to work properly.