I have the issue that one of the pages in a TYPO3 (11.5.20) environment contains dozens of subpages, which would overly extend the HMENU displayed on the frontend. The suggestion by a colleague was to hide all the subpages in said menu and instead display them on a separate menu embedded on the page itself. This basically means we have to make the subpages hidden for only one specific menu, not for all of them, ruling out the possibility to hide the subpages for navigation by the backend.
To have this functionality not just applying to a single, statically defined page, my idea to approach this would be to register a separate page layout for pages with this requirement and somehow configure HMENU in Typoscript to ignore subpages of that given layout. What I found is the itemArrayProcFunc for processing menu arrays; what I would do is to simply return an empty array with it if said page layout applies. I am encountering two problems though:
The function I have defined seems not to get called. I am including the script like in the Typoscript snippet below, but even when deliberately throwing an exception inside, there is no feedback on it whatsover by TYPO3, with the menu displaying all pages as usual. Is that method of inclusion possibly outdated? The official TYPO3 doc dictates USER and USER_INT for registering custom functions, but I'm not exactly sure how to make this work together with itemArrayProcFunc.
Even if the function worked, I'm not sure how to retrieve the layout of the respective parent page, or if it is even possible to retrieve it at all.
I'm assuming there are some major points regarding custom functions within Typoscript I might have missed (to be fair though - TYPO3's documentation is not exactly transpicuous). Could anyone possibly give me a hint on it? Is there maybe even a more elegant way to hide menus from specific pages?
lib.ts (snippet):
includeLibs.user_menuItemArrayProcFunc = EXT:lraffb_intern/Classes/MenuItemArrayProcFunc.php
lib {
...
20 = HMENU
20 {
stdWrap {
outerWrap = <nav class="navigation">|</nav>
}
entryLevel = 0
1 = TMENU
1 {
wrap = <ul>|</ul>
NO = 1
NO {
allWrap = <li>|
wrapItemAndSub = |</li>
itemArrayProcFunc = user_menuItemArrayProcFunc->process
}
ACT < .NO
ACT {
allWrap = <li class="act">|
}
}
2 < .1
3 < .2
4 < .3
5 < .4
}
...
}
MenuItemArrayProcFunc.php:
<?php
class MenuItemArrayProcFunc {
public function process($menuArr, $conf) {
if (PAGE_LAYOUT == 'pagets__left_no_subpages') // retrieve the page layout here somehow
return [];
return $menuArr;
}
}
This basically means we have to make the subpages hidden for only one specific menu, not for all of them, ruling out the possibility to hide the subpages for navigation by the backend.
Well - actually this is the solution you are looking for but just the other way around. Set those pages to hide in menus and then use the includeNotInMenu parameter to still use them in all menus except the one you mentioned.
https://docs.typo3.org/m/typo3/reference-typoscript/main/en-us/ContentObjects/Hmenu/Index.html#includenotinmenu
Depending on a flag (that could be the page layout) you should differ the rendering of menus. That would be easy if you render your menus with FLUID as you can insert conditions in an easier way than in TypoScript.
e.g.: Depending on your condition you render the second level or skip it.
On page rendering you have all fields from pages record, including your flag. When you call the menu partial just remember to insert the flag in the arguments.
Before I made the switch to Drupal (previously just static HTML), I had a div title in my header that changed depending on what page the user was on using the following code:
ABOUT PAGE
<?php
$title = "ABOUT US</span>";
$path = $_SERVER['DOCUMENT_ROOT'];
$path .= "/includes/header.php";
include_once($path); ?>
The reason this worked, however, was because I was using static HTML... which means I had every page set to use its own Index.PHP, located at (for the About page, for example) public_HTML/about/index.php. Therefore, I could edit each page individually to my liking by editing its respective Index file...
Now, with Drupal.. instead of having so many Index.PHP files like I did before (which was messy IMO...), I want to have every page use the same page.tpl.php (with the exception of the front page, which uses page--front.tpl.php).
Can I somehow modify the above PHP code to display a different title using IF statements depending on what page the user is on?
For example... (I have no idea how to PHP code so this is just to give you experts an idea of what I would want..)
Ifpage=about, $title=About Us;
Ifpage=contact, $title=Contact Us;
Could this code all be in the same page.tpl.php?
Thank you so much!
Drupal 7 has a title field for each content type. Why don't you use that?
It shows by default and you can change it for every node.
It is this code in your template file.
<?php print render($title_prefix); ?>
<?php if ($title): ?>
<h1 class="title" id="page-title">
<?php print $title; ?>
</h1>
<?php endif; ?>
<?php print render($title_suffix); ?>
$title_prefix (array): An array containing additional output populated by modules, intended to be displayed in front of the main title tag that appears in the template.
$title: The page title, for use in the actual HTML content.
$title_suffix (array): An array containing additional output populated by modules, intended to be displayed after the main title tag that appears in the template.
See https://api.drupal.org/api/drupal/modules!system!page.tpl.php/7 for all the variables available in your page.tpl template file.
If you want to style one part different from the other you could use an extra field for it.
Or if you need to do something with the value (I wouldn't suggest this!!!).
switch ($title) {
case "About Us":
// Do something with the title
break;
case "Contact Us":
// Do something with the title
break;
case 2:
// Do something with the title
break;
}
Here's a simple approach:
Add a new field for the content type
Call it title2
Render the two fields
Use css to inline align them and add styling
Here was my solution since I am unable to position a Drupal-based title block right next to a non-Drupal based logo DIV..
I created a div called .headertitle and positioned/styled it how I want.
My header.php is an PHP include file which is called by each page and the headertitle has a PHP condition..
<?php if(empty($headertitle)) $headertitle = "ASK REAL QUESTIONS, <br><span class='white'>GET FREE ANSWERS.</span>";
echo $headertitle; ?>
That way, if no text is declared for the .headertitle, it takes the default form of "ASK REAL QUESTIONS, GET FREE ANSWERS."
...Now, I had to figure out a way to actually declare text for the .headertitle depending on what page I was on...
I did this by using a custom template for each page (node) by using this file.. "page--node--nodeid.tpl.php".
So, for my ABOUT US page, I created a tpl.php file called "Page--node--7.tpl.php".. for this page, the 7 is the nodeid which is easy to find.
Then, I added the following PHP code to declare text for the .headertitle specifically on the ABOUT US page which looks like this...
<?php $headertitle = "ABOUT<span class='white'>.US</span>"; include('includes/header.php'); ?>
DONE AND DONE.
I'll do that for each page. :)
I have the problem that I am using a theme where the navigation is simply 'scrolling' to a given part (eg. #contact) when pressed. However, I have implemented some seperate subpages that exits this scrollable page and thus renders the navigation ineffective.
My question is, how can I change the destination of my links or maybe change the menu entirely when users are on these subpages?
I should clarify that all the pages that need 'the new' navigation use a different page template called full_width.php. But since it is using an include header function I can't just replace the navigation.
Thank you for your time!
Here is simple solution based on templates.
if ( is_page_template('full_width.php') ) {
//menu for full width page
} else {
// Returns false when 'full_width.php' is not being used.
wp_nav_menu( $args );//read for args in codex to make menu you want.
}
I want to display certain text in all my posts except if it's in this one category. How do I do that? Oh yea I almost forgot I want to include the title of the post in the text. So I think I need to use echo, cat='-5', and or something?? I don't know how to form it though. Thanks!
You could use the Wordpress function in_category(). When you use it inside the loop, it returns true if the current post is a member of the category you passed it.
<?php
if ( in_category('my-category'))
{
// don't output text
} else {
// do output text
}
?>
Do you require the text to be completely locked away, or just hidden from view? If you only need it hidden from view (but accessible to anyone who chooses to pry) then you may be able to do it very quickly using css.
If you have coded your theme - or are using someone else's - that adds helpful styles into the header, you may have a lot to work with already. For example, this is a body declaration generated by the Thematic theme:
<body class="wordpress y2011 m01 d31 h12 archive category category-orthopaedics">
Say you have a chunk of content to hide:
<div class="text_to_hide">This is what gets hidden.</div>
Then you declare the CSS as:
.category-orthopaedics .text_to_hide { display: none; }
I would like to display a Drupal view without the page template that normally surrounds it - I want just the plain HTML content of the view's nodes.
This view would be included in another, non-Drupal site.
I expect to have to do this with a number of views, so a solution that lets me set these up rapidly and easily would be the best - I'd prefer not to have to create a .tpl.php file every time I need to include a view somewhere.
I was looking for a way to pull node data via ajax and came up with the following solution for Drupal 6. After implementing the changes below, if you add ajax=1 in the URL (e.g. mysite.com/node/1?ajax=1), you'll get just the content and no page layout.
in the template.php file for your theme:
function phptemplate_preprocess_page(&$vars) {
if ( isset($_GET['ajax']) && $_GET['ajax'] == 1 ) {
$vars['template_file'] = 'page-ajax';
}
}
then create page-ajax.tpl.php in your theme directory with this content:
<?php print $content; ?>
Based on the answer of Ufonion Labs I was able to completely remove all the HTML output around the page content in Drupal 7 by implementing both hook_preprocess_page and hook_preprocess_html in my themes template.php, like this:
function MY_THEME_preprocess_page(&$variables) {
if (isset($_GET['response_type']) && $_GET['response_type'] == 'embed') {
$variables['theme_hook_suggestions'][] = 'page__embed';
}
}
function MY_THEME_preprocess_html(&$variables) {
if (isset($_GET['response_type']) && $_GET['response_type'] == 'embed') {
$variables['theme_hook_suggestions'][] = 'html__embed';
}
}
Then I added two templates to my theme: html--embed.tpl.php:
<?php print $page; ?>
and page--embed.tpl.php:
<?php print render($page['content']); ?>
Now when I open a node page, such as http://example.com/node/3, I see the complete page as usual, but when I add the response_type parameter, such as http://example.com/node/3?response_type=embed, I only get the <div> with the page contents so it can be embedded in another page.
I know this question has already been answered, but I wanted to add my own solution which uses elements of Philadelphia Web Design's (PWD) answer and uses hook_theme_registry_alter, as suggested by Owen. Using this solution, you can load the template directly from a custom module.
First, I added raw.tpl.php to a newly created 'templates' folder inside my module. The contents of raw.tpl.php are identical to PWD's page-ajax.tpl.php:
<?php print $content; ?>
Next, I implemented hook_preprocess_page in my module in the same fashion as PWD (except that I modified the $_GET parameter and updated the template file reference:
function MY_MODULE_NAME_preprocess_page(&$vars) {
if ( isset($_GET['raw']) && $_GET['raw'] == 1 ) {
$vars['template_file'] = 'raw';
}
}
Finally, I implemented hook_theme_registry_alter to add my module's 'templates' directory to the theme registry (based on http://drupal.org/node/1105922#comment-4265700):
function MY_MODULE_NAME_theme_registry_alter(&$theme_registry) {
$modulepath = drupal_get_path('module','MY_MODULE_NAME');
array_unshift($theme_registry['page']['theme paths'], $modulepath.'/templates');
}
Now, when I add ?raw=1 to the view's URL path, it will use the specified template inside my module.
For others who may hit this page, if you're just working with standard callbacks (not necessarily views), this is easy. In your callback function, instead of returning the code to render within the page, use the 'print' function.
For example:
function mymodule_do_ajax($node)
{
$rval = <<<RVAL
<table>
<th>
<td>Data</td>
<td>Data</td>
<td>Data</td>
</th>
<tr>
<td>Cool</td>
<td>Cool</td>
<td>Cool</td>
</tr>
</table>
RVAL;
//return $rval; Nope! Will render via the templating engine.
print $rval; //Much better. No wrapper.
}
Cheers!
Another way to do it which I find very handy is to add a menu item with a page callback function that doesn't return a string:
Example:
/**
* Implementation of hook_menu.
*/
function test_menu(){
$items['test'] = array (
/* [...] */
'page callback' => 'test_callback',
/* [...] */
);
return $items;
}
function test_callback() {
// echo or print whatever you want
// embed views if you want
// DO NOT RETURN A STRING
return TRUE;
}
-- Update
It would be much better to use exit(); instead of return TRUE; (see comment).
Hey, here's yet another way of doing it:
1) Download and install Views Bonus Pack (http://drupal.org/project/views_bonus)
2) Create a Views display "Feed" and use style "XML" (or something you think fits your needs better).
3) If you're not satisfied with the standard XML output, you can change it by adjusting the template for the view. Check the "theme" settings to get suggestions for alternative template names for this specific view (so you'll still have the default XML output left for future use).
Good luck!
//Johan Falk, NodeOne, Sweden
Based on answer of Philadelphia Web Design (thanks) and some googling (http://drupal.org/node/957250) here is what worked for me in Drupal 7 to get chosen pages displayed without the template:
function pixture_reloaded_preprocess_page(&$vars)
{
if ( isset($_GET['vlozeno']) && $_GET['vlozeno'] == 1 ) {
$vars['theme_hook_suggestions'][] = 'page__vlozeno';
}
}
instead of phptemplate, in D7 there has to be the name_of_your_theme in the name of the function. Also, I had to put two underscores __ in the php variable with the file name, but the actual template file name needs two dashes --
content of page--vlozeno.tpl.php :
<?php print render($page['content']); ?>
The output, however, still has got a lot of wrapping and theme's CSS references. Not sure how to output totally unthemed data...
Assuming you're in Drupal 6, the easiest way to do this is to put a phptemplate_views_view_unformatted_VIEWNAME call in template.php (assumes your view is unformatted - if it's something else, a list say, use the appropriate theme function). Theme the view results in this theme call then, instead of returning the results as you normally would, print them and return NULL. This will output the HTML directly.
PS - make sure to clear your cache (at /admin/settings/performance) to see this work.
there are probably a number of ways around this, however, the "easiest" may be just setting your own custom theme, and having the page.tpl.php just be empty, or some random divs
// page.tpl.php
<div id="page"><?php print $content ?></div>
this method would basically just allow node.tpl.php to show (or any of drupal's form views, etc...) and would be an easy way to avoid modifying core, or having to alter the theme registry to avoid displaying page.tpl.php in the first place.
edit: see comments
ok i played around with views a bit, it looks like it takes over and constructs it's own "node.tpl.php" (in a sense) for display within "page.tpl.php". on first glance, my gut feeling would be to hook into theme_registry_alter().
when you're looking at a views page, you have access to piles of information here, as well as the page.tpl.php paths/files. as such i would do something like:
function modulejustforalteration_theme_registry_alter(&$variables) {
if (isset($variables['views_ui_list_views']) ) {
// not sure if that's the best index to test for "views" but i imagine it'll work
// as well as others
$variables['page']['template'] = 'override_page';
}
}
this should allow you to use a "override_page.tpl.php" template in your current theme in which you can remove anything you want (as my first answer above).
a few things:
as i said, not sure if views_ui_list_views is always available to check against, but it sounds like it should be set if we're looking at a view
you can alter the theme paths of the page array if you prefer (to change the location of where drupal will look for page.tpl.php, instead of renaming it altogether)
there doesn't appear to be any identifiers for this specific view, so this method might be an "all views will be stripped" approach. if you need to strip the page.tpl.php for a specific view only, perhaps hooking into template_preprocess_page() might be a better idea.
I like the Drupal module. BUt, here's another way.
copy page.tpl.php in your theme folder to a new file called page-VIEWNAME.tpl.php, where VIEWNAME is the machine-readible name of the view.
Then edit page-VIEWNAME.tpl.php to suit.
There is also http://drupal.org/project/pagearray which is a general solution...
Also, #Scott Evernden's solution is a cross site scripting (XSS) security hole. Don't do that. Read the documentation on drupal.org about how to Handle Text in a Secure Fashion http://drupal.org/node/28984
A simple way to display content of a special content-type you wish to display without all the stuff of the page.tpl.php:
Add the following snippet to your template.php file:
function mytheme_preprocess_page(&$vars) {
if ($vars['node'] && arg(2) != 'edit') {
$vars['template_files'][] = 'page-nodetype-'. $vars['node']->type;
}
}
Add a page-nodetype-examplecontenttype.tpl.php to your theme, like your page.tpl.php but without the stuff you don't want to display and with print $content in the body.
If I understand your question, you want to have nodes which contain all the HTML for a page, from DOCTYPE to </HTML>. What I would do is create a content type for those nodes -- "fullhtml" as its machine-readable name -- and then create a node template for it called node-fullhtml.tpl.php. You can't just dump the node's contents, as they've been HTML-sanitized. node.fullhtml.tpl.php would literally be just this:
echo htmlspecialchars_decode($content);
Then you'll need a way to override the standard page.tpl.php. I think what you could do is at the top of your page.tpl.php check the $node's content type, and bail out if it's fullhtml. Or, set a global variable in node-fullhtml.tpl.php that page.tpl.php would check for.
I'm no Drupal expert, but that's how I'd do it. I'm talking off the cuff, so watch for devils in the details.
I see you have already gone and made yourself a module, so this may no longer help, but it is fairly easy to get a view to expose an rss feed, which might be an easier way of getting at the content, especially if you want to include it on a different site.
On D7 you can use menu_execute_active_handler
$build = menu_execute_active_handler('user', FALSE);
return render($build);
jeroen's answer was what did for me after playing with it. I have a Drupal 7 site.
First of all make sure you replace MY_THEME with your theme name. Yes it is obvious but most newbies miss this.
I actually already had a function MY_THEME_preprocess_page(&$variables) {. Do not recreate the function then but add this code at the end of the function before you close it with }.
if (isset($_GET['response_type']) && $_GET['response_type'] == 'embed') {
$variables['theme_hook_suggestions'][] = 'page__embed';
}
My function used $vars not $variables, so I had to update that as well. Again obvious if you think look for it.
My first answered allowed me to only display the node when I called it up in a web browser. However the ultimate goal of this is to embed the drupal node in an 3rd party site using iframe.
Since the release of Drupal Core 7.50 iframe is by default blocked to prevent Clickjacking
To get only the node to successfully embed in a 3rd party site you also need to override the x-frame default setting. Everything started working after I added the following in template.php
function MY_THEME_page_alter($page) {
if (isset($_GET['response_type']) && $_GET['response_type'] == 'embed') {
header_remove('X-Frame-Options');
}
}