Display image when submit button is pressed - php

Question

I have a multi-page form that was created for me. All of the pages on the form have submit button that saves the data to a database, a previous button that goes to the previous page and a next button. How do I display an image when the save button (id="save") is pressed? Right now the image pops up when either one of the buttons are pressed. I am a jQuery rookie so any help is greatly appreciated. Thanks!
The jQuery
<script>
jQuery(document).ready(function($) {
$('form').submit(function (e) {
var form = this;
e.preventDefault();
setTimeout(function () {
form.submit();
}, 5000); // in milliseconds
$("<img src='/wp-content/uploads/2013/04/saving.gif'>").appendTo("#target");
});
});
</script>
The PHP
<div id="target"></div>
<input type="submit" name="status" value="Prev" />
<input type="submit" name="status" id="save" value="Save" />
<input type="submit" name="status" value="Next" />
<?php
if(!empty($_REQUEST['status']) && $_REQUEST['status'] == 'Prev'){
//save data and redirect to previous page using header();
}
if(!empty($_REQUEST['status']) && $_REQUEST['status'] == 'Next'){
//save data and redirect to next page using header();
}
if(!empty($_REQUEST['status']) && $_REQUEST['status'] == 'Save'){
//save data and do whatever you want
}
?>

Answer 1

In your code all buttons have the type submit, hence it causes the form to submit irrespective of the button you click.
make type="submit" only to that button for which you want to submit the form and show the image.

Answer 2

Demo: http://jsfiddle.net/esMn2/1/
Here's a working demo of a quick mockup, not using jQuery, but to give you an idea of how it could be done.
prev = document.getElementById('prev');
save = document.getElementById('save');
next = document.getElementById('next');
form = document.getElementById('form');
prev.addEventListener('mousedown', function(e) {
e.preventDefault();
alert('Did nothing');
});
save.addEventListener('mousedown', function(e) {
e.preventDefault();
showLoading();
});
next.addEventListener('mousedown', function(e) {
e.preventDefault();
alert('Did Nothing');
});
function showLoading() {
var load = document.createElement('img');
load.src = "http://www.henley-putnam.edu/Portals/_default/Skins/henley/images/loading.gif";
document.getElementById('target').appendChild(load);
setTimeout(function() {
form.submit();
}, 5000);
}
Using jQuery though you will support IE<9, as they know to use attachEvent and not addEventListener

Answer 3

To get the image to only show up for the Save button, just bind the event to that button, not to the form's submit event.
jsFiddle
$('#save').click(function(e) {
e.preventDefault();
var form = $(this).closest('form');
setTimeout(function () {
form.submit();
}, 5000); // in milliseconds
$("<img src='/wp-content/uploads/2013/04/saving.gif'>").appendTo("#target");
});
This way, there will be no delay on submitting the form for the prev and next buttons, and the image and delay will only show for the Save button.