Why this if else condition is not working properly? - php

Question

I am using if else condition with foreach loop to check and insert new tags.
but both the conditions(if and alse) are being applied at the same time irrespective of wether the mysql found id is equal or not equal to the foreach posted ID. Plz help
$new_tags = $_POST['new_tags']; //forget the mysl security for the time being
foreach ($new_tags as $fnew_tags)
{
$sqlq = mysqli_query($db3->connection, "select * from o4_tags limit 1");
while($rowq = mysqli_fetch_array($sqlq)) {
$id = $rowq['id'];
if($id == $fnew_tags) { //if ID of the tag is matched then do not insert the new tags but only add the user refrence to that ID
mysqli_query($db3->connection, "insert into user_interests(uid,tag_name,exp_tags) values('$session->userid','$fnew_tags','1')");
}
else
{ //if ID of the tag is not matched then insert the new tags as well as add the user refrence to that ID
$r = mysqli_query($db3->connection, "insert into o4_tags(tag_name,ug_tags,exp_tags) values('$fnew_tags','1','1')");
$mid_ne = mysqli_insert_id($db3->connection);
mysqli_query($db3->connection, "insert into user_interests(uid,tag_name,exp_tags) values('$session->userid','$mid_ne','1')");
}
}
}

Answer 1

i think you are inserting
$r = mysqli_query($db3->connection, "insert into o4_tags(tag_name,ug_tags,exp_tags)
values('$fnew_tags','1','1')");$mid_ne = mysqli_insert_id($db3->connection);
and then you are using while($rowq = mysqli_fetch_array($sqlq))
which now has records you just inserted therefore your if is executed

Answer 2

I'm pretty sure the select query below will always return the same record.
$sqlq = mysqli_query($db3->connection, "select * from o4_tags limit 1");
I think most of the time it will goes to the else, which execute the 2 insert.
Shouldn't you write the query like below?
select * from o4_tags where id = $fnew_tags limit 1