how to re-format datetime string in php? - php

Question

I receive a datetime from a plugin. I put it into a variable:
$datetime = "20130409163705";
That actually translates to yyyymmddHHmmss.
I would need to display this to the user as a transaction time but it doesn't look proper.
I would like to arrange it to be like 09/04/2013 16:37:05 or 09-apr-2013 16:37:05.
How do I go about and change the orders of the string?
As for now I could think is to use substr to separate the date and time. I'm still not sure on how to add the additional characters and rearrange the date.

Answer 1

why not use date() just like below,try this
$t = strtotime('20130409163705');
echo date('d/m/y H:i:s',$t);
and will be output
09/04/13 16:37:05

Answer 2

For PHP 5 >= 5.3.0 http://www.php.net/manual/en/datetime.createfromformat.php
$datetime = "20130409163705";
$d = DateTime::createFromFormat("YmdHis", $datetime);
echo $d->format("d/m/Y H:i:s"); // or any you want
Result:
09/04/2013 16:37:05

Answer 3

date("Y-m-d H:i:s", strtotime("2019-05-13"))

Answer 4

If you want to use substr(), you can easily add the dashes or slashes like this..
$datetime = "20130409163705";
$yyyy = substr($datetime,0,4);
$mm = substr($datetime,4,6);
$dd = substr($datetime,6,8);
$hh = substr($datetime,8,10);
$MM = substr($datetime,10,12);
$ss = substr($datetime,12,14);
$dt_formatted = $mm."/".$dd."/".$yyyy." ".$hh.":".$MM.":".$ss;
You can figure out any further formatting from that point.

Answer 5

You have different options.
Using date():
$format = date('d/m/y H:i:s', 1621371929);
echo $format;
the output is:
18/05/21 14:05:29
Using date_format():
$date = date_create(1621371929);
echo date_format($date, 'd/m/y H:i:s');
the output is:
18/05/21 14:05:29
Using DateTime::format():
$date = new DateTime('2021-05-18 14:05:29');
echo $date->format('d/m/y H:i:s');
the output is:
18/05/21 14:05:29
This article gives you an overview of these three methods, and this one is DateTime::format() in depth.

Answer 6

try this
$datetime = "20130409163705";
print_r(date_parse_from_format("Y-m-d H-i-s", $datetime));
the output:
[year] => 2013
[month] => 4
[day] => 9
[hour] => 16
[minute] => 37
[second] => 5

Answer 7

You could do it like this:
<?php
$datetime = "20130409163705";
$format = "YmdHis";
$date = date_parse_from_format ($format, $datetime);
print_r ($date);
?>
You can look at date_parse_from_format() and the accepted format values.

Answer 8

https://en.functions-online.com/date.html?command={"format":"l jS \\of F Y h:i:s A"}

Answer 9

You can use date_parse_from_format() function ...
date_parse_from_format(string $format, string $datetime): array
Example
<?php
$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));
?>
The above example will output:
Array
(
[year] => 2009
[month] => 1
[day] => 6
[hour] => 13
[minute] => 0
[second] => 0
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 0
[errors] => Array
(
)
[is_localtime] => 1
[zone_type] => 1
[zone] => 3600
[is_dst] =>
)
Check the PHP docs..you will get clear idea