Mysqli not showing errors properly - php

Question

I am trying to learn mysqli properly I get most of the functions. One thing left to do is to have proper error reporting across all my layers. I don't understand why the following snippet of code detects an error but won't get the error number nor the error code.
function get_PID_TID_by_PK($con,$ourId)
{
$returned['errno'] ="";
$returned['error'] ="";
//mistake is over here!!!
if(!$stmt = $con->prepare("ELECT gene_name,jgi_protein_id,jgi_transcript_id FROM jgi_transid_protid_match where our_protein_id = ?"))
{
$returned['errno'] = $con->errno;
$returned['error'] = $con->error;
return $returned;
}
if(!$stmt->bind_param('s',$ourId))
{
$returned['errno'] = $stmt->errno;
$returned['error'] = $stmt->error;
return $returned;
}
if(!$stmt->execute())
{
$returned['errno'] = $stmt->errno;
$returned['error'] = $stmt->error;
return $returned;
}
$stmt->bind_result($gene_name,$jgi_protein_id,$jgi_transcript_id);
$stmt->fetch();
$fetchedArray['gene_name'] = $gene_name;
$fetchedArray['jgi_protein_id'] = $jgi_protein_id;
$fetchedArray['jgi_transcript_id'] = $jgi_transcript_id;
//Have to use this hack since query returns an object and not an array and I don't want to make everything object oriented if you don't know what I am talking about just ignore this comment
$returned['assoc'] = $fetchedArray;
return $returned;
}
The mistake is obvious and on the 6th line I wrote ELECT instead of SELECT the program is getting inside that block but the errno and error are null. What am I doing wrong.This code works perfectly fine if I don't break it on purpose.

Answer 1

Are you sure the IF statement is correct?
if(!$stmt = $con->prepare("ELECT gene_name,jgi_protein_id,jgi_transcript_id FROM jgi_transid_protid_match where our_protein_id = ?"))
{
$returned['errno'] = $con->errno;
$returned['error'] = $con->error;
return $returned;
}
Should be
if(($stmt = $con->prepare("ELECT gene_name,jgi_protein_id,jgi_transcript_id FROM jgi_transid_protid_match where our_protein_id = ?")) === FALSE)
{
$returned['errno'] = $con->errno;
$returned['error'] = $con->error;
return $returned;
}
Or split the assignment
$stmt = $con->prepare("ELECT gene_name,jgi_protein_id,jgi_transcript_id FROM jgi_transid_protid_match where our_protein_id = ?");
if($stmt === FALSE)
{
$returned['errno'] = $con->errno;
$returned['error'] = $con->error;
return $returned;
}

Answer 2

I am trying to learn mysqli properly
That's the only mistake you made.
With PDO your code would be... three lines long. And it will report all the errors properly
function get_PID_TID_by_PK($con,$ourId)
{
$stmt = $con->prepare("ELECT gene_name,jgi_protein_id,jgi_transcript_id FROM jgi_transid_protid_match where our_protein_id = ?");
$stmt->execute(array($ourId));
return $stmt->fetch();
}

Answer 3

In the end I decided to go with using http://www.php.net/manual/en/function.set-error-handler.php . I will redesign my code a bit and let the php error handler take care of all the errors and I will make a custom one for my database errors that are happening.