How to display pg_query results in a table using PHP? - php

Question

I'm trying to display the results of my query in a neatly formatted table but I'm pretty new to PHP so I'm at a bit of a loss. Currently I have this:
$dbconn = pg_connect("host=localhost port=5432 dbname=mary");
$result = pg_query($dbconn, $selectStmt);
$resultArr = pg_fetch_all($result);
print_r($resultArr);
Assume $selectStmt = SELECT State, Name FROM perez.pop WHERE Name LIKE '%Alabama%';
When I print this, I get the following:
Array ( [0] => Array ( [state] => 1 [name] => Alabama ) )
How could I place this into a table where the columns are "state" and "name" along with one more column in which I plan to place a link to a different page?
Also, can anyone clarify how the $resultArr looks when I get multiple rows as a result of my query?
EDIT: I'd like the output to look something like this:
State | Name | Follow link
___________________________________________________
32 Alabama <some link to a php page>
2 Alabama <another link>

Answer 1

You can just loop in your array and print your table while looping, something like
$resultArr = pg_fetch_all($result);
//print_r($resultArr);
echo '<table>
<tr>
<td>State</td>
<td>Name</td>
</tr>';
foreach($resultArr as $array)
{
echo '<tr>
<td>'. $array['State'].'</td>
<td>'. $array['Name'].'</td>
</tr>';
}
echo '</table>';

Answer 2

$query = pg_query("SELECT * FROM user");
$users_arr = pg_fetch_all($query);
// render thead
$thead = '<thead>
<tr>';
foreach($users_arr[0] as $key => $value) {
$thead .= '<th>' . $key . '</th>';
}
$thead .= '</tr>
</thead>';
// render tbody
$tbody = '<tbody>';
foreach($users_arr as $key => $value) {
$tbody .= '<tr>';
foreach($value as $k => $v) {
$tbody .= '<td>' . $v . '</td>';
}
$tbody .= '</tr>';
}
$tbody .= '</tbody>';
// render table
$table = '<table>' . $thead . $tbody . '</table>';
echo $table;