Facebook like button ignore URL parameters - php

Question

I'm trying to like my page but the url parameters are ignored
Here is my code:
<style type="text/css">
.float-all {
float: left;
width: 82px;
height: 30px;
overflow: hidden;
margin: 2px;
padding: 4px 2px;
}
.post-btn-share {
width: 100%;
overflow: auto;
}
<link rel="canonical" href="http://mypage.com/view_photo.php" />
</head>
<div class="post-btn-share">
<div class="addthis_toolbox addthis_default_style">
<div class="float-all">
<iframe src="http://www.facebook.com/plugins/like.php?href=http://mypage.com/view_photo.php? img=32&user=1&xx=&send=true&layout=standard&width=300&show_faces=true&action=like&colorscheme=light&font&height=80" frameborder="0" style="border:none;" scrolling="no" width="320" height="240"></iframe>
<div class="float-all">
</div>
<div class="float-all">
</div>
</div>
And view_photo code
<?php
session_start();
?>
<div class="dev-ajuste">
<?php
require_once('script/require_raiz.php');
$login = new login();
$login->log_isset();
//$login->info_user();
$janela = new Janelas('script/system/config.ini','perfil');
$janela->info_visualiza_foto($_GET['img'],$_GET['user']);
?>
</div>
<!--=======Cabeçalho e chamadas de scripts do documento=======-->
<?php include_once("head.php"); ?>
<!--=======Barra de navegação=======-->
<?php include_once("navbar.php"); ?>
<div id="janela" class="perfil"></div>
<div id="info" class="<?php echo $_GET['user'];?>"></div>
<!--=======Header=======-->
<?php include_once('box_foto.php'); ?>
<!--=======Propaganda=======-->
<?php include('addsense.php');?>
<!--=======Área dos posts=======-->
<?php include('post_area.php');?>
<!--=======Rodapé do documento=======-->
<?php include_once("footer.php"); ?>
<!--=======Seguranca de Login=======-->

Answer 1

(Turning a comment chain into a potential answer)
I really don't think you've understood. Look at the URL being used in the iframe:
http://www.facebook.com/plugins/like.php?href=http://mysite.com/view_photo.php?img=34&user=1&xx=&;send=true&;layout=standard&;width=300&;show_faces=true&;action=like&;colorscheme=light&;font&;height=80
In a URL, parameters being sent to the resource start at the ? character. But you have two ? characters. Do the parameters start at the first one or the second one? A parser has no way to know. When a & is encountered, is that separating a parameter for the outer URL (the first ?), or one being enclosed with the inner URL (the second ?)? A parser has no way to know.
The format needs to be like this:
http://someresource?parameter1&parameter2&etc
If one of those parameters is also a URL with its own parameters, that entire parameter needs to be URL-encoded so it doesn't confuse the rest of the URL for which it's being used as a parameter. Any parser has to be able to clearly identify what goes with the inner-URL and what goes with the outer-URL. It will URL-decode the inner one for you when it needs to use it.
PHP provides a function to do this. So does JavaScript. You can use whichever you'd like. All you do is pass it the string to be encoded (which would be your inner URL with whatever parameters need to go to that URL) and it will return the encoded string (which would be the parameter to send to your outer URL).
(Also, why do you have all those semi-colons? You don't separate URL parameters with semi-colons. I'm not sure where you got that idea.)

Answer 2

Go to this page and check the link of the like button which is show in the picture below:
You right click and inspect it. You see:
You see that it is urlencode'd. And the reasoning is very well explained by David :)