Ignored if-statement - php

Question

this is only my second question so please be gentle, I am new to PHP.
I have written a statement that queries a database, then checks a file to see if the relevant is present before creating a div to put the image into. The problem is that the output creates divs for rows that have no images.
$query = "SELECT vehicle_make_logo FROM vehicle_makes";
$result = mysql_query($query);
if(!$result) die ("Database access failed: " . mysql_error());
$rows = mysql_num_rows($result);
for ($j = 0; $j < $rows; ++$j)
{
$row = mysql_fetch_row($result);
$image = 'images/vehicleBrands/'.$row[0];
if(file_exists($image)){
echo '<div class="component"><img class="icons" src="images/vehicleBrands/'.$row[0].'"></div>';
}
}
I have tried adding an empty else-statement, but that didn't do anything.
Any help would be greatly appreciated.

Answer 1

Another possibility for what is happening is that your DB table has rows in there which haven an empty field for verhicle_make_logo, at which point your if statement is checking if that folder exists, which it obviously does. If you are certain this is not the case ignore the below, if it is then this might be a solution.
<?php
$query = "SELECT vehicle_make_logo FROM vehicle_makes";
$result = mysql_query($query);
if(!$result) die ("Database access failed: " . mysql_error());
$rows = mysql_num_rows($result);
for ($j = 0; $j < $rows; ++$j)
{
$row = mysql_fetch_row($result);
$image = 'images/vehicleBrands/'.$row[0];
if(!empty($row[0]) && file_exists($image)){
echo '<div class="component"><img class="icons" src="images/vehicleBrands/'.$row[0].'"></div>';
}
}

Answer 2

A browser can never overwrite PHP code because it never sees the PHP code. A browser will only render exactly what the PHP code passes to it. In the case where IE creates extra div tags, it could be that your HTML is malformed and IE tries to normalise it and creates extra divs in the process to close off some open tags that you may have overlooked.
Try copying the view-source code of the page and run it through a HTML validator to see.

Answer 3

Do not ever think for a minute that, Whatever kind of Browser you are using can actaully influence the way how PHP behaves. Because, it Can not! It may seem that way to you, because sometimes, the HTML tags/codes... outputted/echo'ed by your PHP script may be rendered in a different way, according to the browser type you are using, specially by IE, because it sucks. Now, to get back to your code, try this
<?php
$query = "SELECT vehicle_make_logo FROM vehicle_makes";
$result = mysql_query($query) or die(mysql_error());
if(mysql_num_rows($rows) > 0) {
for($j=0; $j < count($rows); ++$j){
$row = mysql_fetch_row($result);
$image = 'images/vehicleBrands/'.$row[0];
if(file_exists($image)){
echo '<div class="component">
<img class="icons" src="images/vehicleBrands/'.$row[0].'"></div>';
}
}
}else {echo 'No record found';}