Nivo Slider dose not load the Ajax response from PHP file - php

I'm trying import images to HTML using PHP, but NivoSlider not loaded that.
I looked for the cause of the problem.
I am printing a alert message of response and the right.
Here is the HTML and AJAX query:
<div id="workcontent" class="pcontent" style="display:none;">
<div class="slider-wrapper theme-default">
<div id="slider" class="nivoSlider">
</div>
</div>
<script>
$(document).ready(function() {
var wl = $('#worklist div');
wl.on('click', function(){
var name = $(this).attr('id');
console.log(name);
$.ajax({
url: 'read.php',
type: 'POST',
data: { data : name }
}).done(function (response) {
$('#slider').prepend(response);
alert(response);
});
});
});
</script>
<div id="back"></div>
<div id="backcontainer">
<div id="back">
Back
</div>
</div><!--End backcontainer-->
</div><!--End content-->
And here is the other jQuery:
<script>
$(document).ready(function() {
$('#slider').nivoSlider(function(){alert('OK');});
});
</script>
This alert don't show! ):
Finally, here is the PHP code:
<?php
if (isset($_POST["data"])){
if ($_POST["data"] == "") {
echo "data ures";
} else {
$data = $_POST["data"];
$fname = "content/".$data."/*.*";
$files = glob($fname);
for ($i=0; $i<count($files); $i++)
{
$num = $files[$i];
echo '<img src="'.$num.'" data-thumb="'.$num.'">';
}
}
} else {
echo "nem jott data";
}
?>
Sorry for my bad english

NivoSlider doesn't take a function as an argument.
Also .nivoSlider() is probably called before the AJAX call returns it's response.
A better solution would be:
$(document).ready(function() {
$.ajax({
url: 'read.php',
type: 'POST',
data: { data : name }
}).done(function (response) {
$('#slider').prepend(response).nivoSlider( {} );
});
});
Now you can be fairly sure #slider contains the images from the response body so NivoSlider can act on them.

Related

how to built ajax tabs in wordpress?

I try to display the departments in my website as tabs, when click one tab it will display the data related to this department according to department_id.
I try this code Execute php function only when clicked (wordpress) but I need the tabs number to be dynamic.
<div class="tabs">
<ul>
<?php
$arr1=array(2,3,5,10,22,25,27,28,29,30);
$arr2=array("dep1","dep2","dep3","dep4",
"dep5","dep6","dep7","dep8","dep9","dep10");
for($i=0;$i<10;$i++){?>
<li><a href="#tab" id="<?php echo $arr1[$i]; ?>"><?php echo
$arr2[$i];?>
</a></li>
<?php } ?>
</ul>
</div>
<div id="tab" class="section">
</div>
functions.php:
<?php
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id=$_GET[id];
/** Here I print data according to $dept_id **/
die();
}
?>
script.js:
jQuery(document).ready(function() {
jQuery('.tabs a').click(function(e) {
e.preventDefault();
var tab_id = jQuery(this).attr('id');
console.log(tab_id);
jQuery.ajax({
type: "GET",
url: "wp-admin/admin-ajax.php",
dataType: 'html',
data: ({ action: 'tabsfunction', id: tab_id}),
success: function(data){
jQuery('#tab').html(data);
},
error: function(data)
{
alert("Error!");
return false;
} });}); });
it dose not work, it displays data only for one tab.
console.log(tab_id) ----> it display the id for the first tab clicked
and did not change when click another tab.
You need to echo the output from the tabsfunction and also add the die() at end of the function like below :
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id=$_GET[id];
/** Here display data according to $dept_id **/
echo 'output';
die();
}
Hope it helps.
can you please correct your tab list code.
<div class="tabs">
<ul>
<?php
$arr1 = array(2,3,5,10,22,25,27,28,29,30);
$arr2 = array("dep1","dep2","dep3","dep4","dep5","dep6","dep7","dep8","dep9","dep10");
for($i=0;$i<10;$i++)
{
?>
<li><?php echo $arr2[$i];?></li>
<?php
}
?>
</ul>
</div>
<?php for($i=0;$i<10;$i++)
{
?>
<div id="tab<?php echo $arr1[$i]; ?>" class="section">
</div>
<?php
}
?>
Also return proper response on ajax request.
<?php
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id = $_GET[id];
echo $dept_id; // this just dispay requsted id as tab content here you can add your logic for dynamic content based on id
die();
}
?>
And your script js look like this
jQuery(document).ready(function() {
jQuery('.tabs a').click(function(e) {
e.preventDefault();
var tab_id = jQuery(this).attr('id');
console.log(tab_id);
jQuery.ajax({
type: "GET",
url: "wp-admin/admin-ajax.php",
dataType: 'html',
data: ({ action: 'tabsfunction', id: tab_id}),
success: function(data){
jQuery('#tab'+tab_id).html(data);
},
error: function(data)
{
alert("Error!");
return false;
} });}); });

I am using laravel5.5 Ajax paging. When I click on page second, It will output data in JSON format

I'm using laravel5.5 Ajax paging. I am the HTML part assembled in the controller. When I clicked on page second, I jumped to this method. How to make the compiled HTML code continue to display on the page?
After clicking on the second page, a string of JSON data is returned. This is a problem. How can we make the data on the second page continue to display in the original page?
PHP
//Screen video, playback volume and key points.
public function accept(Request $ request){
$id=$_GET['id'];
$summer=$_GET['key'];
$name=DB::table('vd_category')->where('address',$summer)->value('name');
if($id=='1'){
$video=DB::table('vd_video_'.$summer)->orderBy('state','desc')->paginate(25);
}else if($id=='2'){
$video=DB::table('vd_video_'.$summer)->orderBy('thumbs','desc')-
>paginate(25);
}
$data='';
foreach($video as $list){
$data.='<div class="col-md-1-5 col-sm-4 col-xs-6" style="padding:0
5px;"><div class="movie-item">';
$data.="<a style='position:relative;display:block;' title='$list-
>video_name' target='_blank' href='details?id=$list->id&key =$summer'>";
$data.="<img alt='$list->video_name' title='$list->video_name'
src=\"uploads/$list->image_address\" height=\"230px\" width='100%'>";
$data.="<button class='bdtag'></button>";
$data.="</a>";
$data.="<div class=\"meta\"><div
style=\"width:100%;overflow:hidden;height:20px;\">";
$data.="<a href='/details?id='$list->id'&key='$summer'
target='_blank' title='$list->video_name' class=\"movie-name\">$list-
>video_name</a>";
$data.="<span class=\"otherinfo\"> 5.0分</span></div><div
class=\"otherinfo\">类型:$name</div></div></div></div>";
}
$datav['1']=$data;
$datav['2']="<div>"."{$video->appends(['id' =>
$id,'key'=>$summer,'name'=>'page'])->links()}"."</div>";
return json_encode($datav);
}
HTML
<div id="data">
#foreach($video as $list)
<div class="col-md-1-5 col-sm-4 col-xs-6" style="padding:0 5px;">
<div class="movie-item">
<a style="position:relative;display:block;" title="{{$list-
>video_name}}" target="_blank" href="/details?id={{$list->id}}&key=
{{$status}}">
<img alt="{{$list->video_name}}" title="{{$list-
>video_name}}" src="{{asset('uploads')}}/{{$list->image_address}}"
height="230"
width="100%">
<button class="bdtag"></button>
</a>
<div class="meta">
<div style="width:100%;overflow:hidden;height:20px;"><a
href="/details?id={{$list->id}}&key={{$status}}" target="_blank" title="
{{$list-
>video_name}}" class="movie-name">{{$list->video_name}}</a><span
class="otherinfo"> 5.0分</span></div>
<div class="otherinfo">类型:{{$namme}}</div>
</div>
</div>
</div>
#endforeach
</div>
</div>
</div>
<div id="datav" style="background:#FFF;padding-left:15px;">
{{$video->appends(['id' => $page,'name'=>'page'])->links()}}
</div>
JavaScript
<select name="" required id="where_id" style="float: right;padding-
left:10px;border-left:8px;width: 90px;height: 30px;">
<option value="">Click screening</option>
<option value="1">Sort by play volume</option>
<option value="2">Ranking by points</option>
</select>
<input type="hidden" id="summer" value="{{$status}}">
<script type="text/javascript">
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$("#where_id").change(function () {
var id=$("#where_id").val();
var summer=$("#summer").val();
$.ajax({
type:"get",
url:"accept",
dataType:'json',
data:{id:id,key:summer},
success:function (event){
$("#data").html(event[1]);
$("#datav").html(event[2]);
}
});
});
</script>
It has been solved.js has been modified.
That is, the parameters carried by the URL through the Ajax request to the
back-end again, and then the back-end returned JSON data inserted into the
specified location again, probably this is the solution, my English is not
very good, please forgive me.
<script type="text/javascript">
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$("#where_id").change(function () {
fun();
});
function fun() {
var id=$("#where_id").val();
var summer=$("#summer").val();
$.ajax({
type:"get",
url:"accept",
dataType:'json',
data:{id:id,key:summer},
success:function (event){
$("#data").html(event[1]);
$("#datav").html(event[2]);
pagedata();
}
});
}
function pagedata(){
$(".page-item a").click(function (){
var href=this.href;
this.href="javascript:void(0);";
var id=getQueryVariable('page',href);
var key=getQueryVariable('key',href);
var page=getQueryVariable('page',href);
$.ajax({
type: "get",
url: "accept",
dataType: 'json',
data: {id: id, key: key,page:page},
success:function (event){
$("#data").html(event[1]);
$("#datav").html(event[2]);
pagedata();
}
})
})
}
// Intercept the parameter values carried by URL, such as page parameters
//and some custom parameters.
function getQueryVariable(name,url) {
var reg = new RegExp('(^|&)' + name + '=([^&]*)(&|$)', 'i');
var data=url.slice(url.indexOf('?'));
var r =data.substr(1).match(reg);
if (r != null) {
return unescape(r[2]);
}
return null;
}
</script>

How to get the output using ajax when the Double outputs displayed one for PHP Echo and another for Ajax request?

I successfully fetch the data from the database. The problem is that, I want to display the results using Ajax request. The results/Output which displayed twice, I mean the *first output which displayed through Ajax (#the bottom of index.php), and the Second output displayed through PHP ECHO (**#**the bottom of the page). What can I do to get a single output through Ajax without adding another file and without refreshing the page?
index.php
<head>
<script src="https://code.jquery.com/jquery-3.1.1.js"></script>
<script type="text/javascript" src="javas.js"></script>
</head>
<body>
<div id="table_content"></div>
<?php
include ("db.php");
error_reporting(~E_NOTICE);
function ShowForm($AnswerCommentId) {
echo '<form id="myForm">';
echo '<input id="user" name="user" />';
echo '<textarea id="text" name="text"></textarea>';
echo sprintf('<input id="ParentId" name="ParentId" type="hidden" value="%s"/>', ($AnswerCommentId));
echo '<button type="button" OnClick=SendComment()>Comment</button>';
echo '</form>';
}
$query="SELECT * FROM `comm` ORDER BY id ASC";
$result = mysqli_query($conn,$query);
if (isset($_REQUEST['AnswerId'])) $AnswerId = $_REQUEST['AnswerId'];
else $AnswerId = 0;
$i=0;
while ($mytablerow = mysqli_fetch_row($result)){ $mytable[$i] = $mytablerow; $i++; }
function tree($treeArray, $level, $pid = 0) {
global $AnswerId;
foreach($treeArray as $item){
if ($item[1] == $pid){
echo sprintf('<div class="CommentWithReplyDiv" style="margin-left:%spx;">',$level*60);
echo sprintf('<p>%s</p>', $item[2]);
echo sprintf('<div>%s</div>', $item[3]);
if ($level<=2) echo sprintf('Reply', $item[0]);
if ($AnswerId == $item[0]) echo sprintf('<div id="InnerDiv">%s</div>', ShowForm($AnswerId));
echo '</div><br/>';
tree($treeArray, $level+1, $item[0]); // Recursion
}
}
}
tree($mytable,0,0);
?>
Comment
<div id="MainAnswerForm" style="display:none;width:40%; margin:0 auto;"><?php ShowForm(0); ?></div>
<div id="AfterMainAnswerForm"></div>
<script>
$(document).ready(function(){
$("#Link").click(function () {
$("#InnerDiv").remove();
$("#MainAnswerForm").slideToggle("normal");
return false;
});
});
</script>
</body>
Page.php
<?php
include ("db.php");
$user = $_POST['user'];
$text = $_POST['text'];
$ParentId = $_POST['ParentId'];
$action = $_POST['action'];
if ($action=="add") $query= mysqli_query($conn,"INSERT into `comm` VALUES (NULL,'{$ParentId}','{$user}','{$text}',NOW())");
?>
Javas.js
function show_messages(){
$.ajax({
url: "index.php",
cache: false,
success: function(html){
$("#table_content").html(html);
}
});
}
function AnswerComment (id){
$.ajax({
type: "POST",
url: "index.php",
data: "AnswerId="+id,
success: function(html){
$("#table_content").html(html);
}
});
}
function SendComment (){
var user1 = $("#user").val();
var text1 = $("#text").val();
var ParentId1 = $("#ParentId").val() + "";
$.ajax({
type: "POST",
url: "page.php",
data: "user="+user1+"&text="+text1+"&ParentId="+ParentId1+"&action=add",
success: function(html){
show_messages();
}
});
return false;
}
OK I think its more simple than you think
while you're using .html() it should change all the content of your div but while you're using <div id="table_content"></div> then the <?php ?> your code will show both - one appended to the div and under it the one which echoed by php ... so instead of using
<div id="table_content"></div>
<?php ?>
just wrap the <?php ?> inside the div
<div id="table_content">
<?php ?>
</div>
Alternative way: by using jquery wrapAll() but while Id must be unique you'll need to .remove() the #table_content element first then wrap all your code inside a new #table_content div .. see the example below
$(document).ready(function(){
$('#table_content').remove();
$('.CommentWithReplyDiv').wrapAll('<div id="table_content"></div>');
});
#table_content{
margin : 50px;
background : red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="table_content"></div>
<div class="CommentWithReplyDiv">1</div>
<div class="CommentWithReplyDiv">2</div>
<div class="CommentWithReplyDiv">3</div>
<div class="CommentWithReplyDiv">4</div>

ajax a href onclick get php variable and execute php file

Before I ask this question, I have already referred to the example of this question. However, it seems doesn't work. Without using ajax, I can get my post deleted but after implement ajax, the deleteAtc.php seems to be not working.
My delete page code (delete.php)
<h4>Select an Article to Delete:</h4>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span> Delete<br />
<script type="text/javascript">
$(function(){
$('#link').click(function(){
var id = <?php echo $article['article_id']; ?>;
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id"+id+,
sucess: function() {
$('#sucess').html(data);
}
})
return false;
});
});
</script>
<div id="success"></div><br />
<?php } ?>
While my deleteAtc.php code:
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
echo "Article deleted";
}
}
?>
What I'm trying to do here is to delete the record without redirect to deleteAtc.php, it will remove out the record and replace Article Deleted
May I know where did I go wrong in ajax side?
Please refer below for updated question
Based on the answer below, here is my updated code:
delete.php
<h4>Select an Article to Delete:</h4>
<div id="message"></div>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span>
Delete<br />
<?php } ?>
script
<script type="text/javascript">
$(function(){
$('.link').click(function(){
var elem = $(this);
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+elem.attr('data-artid'),
dataType:"json",
success: function(data) {
if(data.success){
elem.hide();
$('#message').html(data.message);
}
}
});
return false;
});
});
</script>
deleteAtc.php
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
//Also try to handle false conditions or failure
echo json_encode(array('success'=>TRUE,'message'=>"Article deleted"));
}
}
?>
Somehow, if I delete two record at a time, only the first record echo the result, the second result deleted doesn't echo out the result.
Am wondering, possible to add jquery animation to .show the success message and .hide the record deleted?
First of all IDs are not meant to be duplicated, use class selector instead. Also you could make use of custom data attributes to store the id of the article.
Try
<h4>Select an Article to Delete:</h4>
<div id="message"></div>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span>
Delete<br />
<?php } ?>
Script
<script type="text/javascript">
$(function(){
$('.link').click(function(){
var elem = $(this);
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+elem.attr('data-artid'),
dataType:"json",
success: function(data) {
if(data.success){
elem.hide();
$('#message').html(data.message);
}
}
});
return false;
});
});
</script>
And in server side
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
//Also try to handle false conditions or failure
echo json_encode(array('success'=>TRUE,'message'=>"Article deleted"));
}
}
?>
The above script won't work you have to change like below. You are repeating the same identifier function again and again. Keep the jquery script out of foreach loop. You have to add the class property with the article id.
<h4>Select an Article to Delete:</h4>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span> <a href="#" id="link" class='<?php echo $article['article_id']; ?>' >Delete</a><br />
<div id="success"></div><br />
<?php } ?>
<script type="text/javascript">
$(function(){
$('#link').click(function(){
var id = $(this).prop('class');
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+id,
sucess: function() {
$('#sucess').html(data);
}
})
return false;
});
});
</script>
You create several links with id="link". ID must be unique.
You have to write
id="link<? echo $article['article_id']; ?>"
as well as
$('#link<? echo $article["article_id"]; ?>').click(function() {...})
<script language="javascript">
$(document).ready(function() {
$(".delbutton").click(function(){
var element = $(this);
var del_id = element.attr("id");
var info = 'id=' + del_id;
if(confirm("Sure you want to delete this record? There is NO undo!"))
{
$.ajax({
type: "GET",
url: "products/delete_record.php",
data: info,
cache: false,
success: function(){
setTimeout(function() {
location.reload('');
}, 1000);
}
});
$(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
.animate({ opacity: "hide" }, "slow");
}
return false;
//location.reload();
});
});
</script>

Jquery, ajax and problem with load

This is the HTML part:
div id="messages">
<div class="messages">
<?php if(isset ($unread)) { ?>
<p>You have <?php echo $unread?> unread messages.</p>
<?php } ?>
<?php if(isset ($messages)) { ?>
<?php foreach ($messages as $msg){ ?>
<div class="col_3">
<?php
if($msg['read'] == 0){ echo 'Status of message: Unreaded';}
elseif($msg['read'] == 1){echo 'Status of message: Readed';}
echo "<p>Message from: $msg[name]</p>";
echo "<p>Sender email: $msg[email]</p>";
echo "<p>Message: <br />$msg[message]</p>"; ?>
Delete message
</div>
<?php } ?>
<?php } ?><!-------- end of if $message-------->
</div><!------ end of div .messages--------->
</div><!------ end of div #messages--------->
and JQ:
$(".delete").click(function() {
var commentContainer = $(this).parent();
var id = $(this).attr("id");
var string = 'id='+ id ;
$.ajax({
url: "<?php echo site_url('messages/delete') ?>",
type: "POST",
data: string,
cache: false,
success: function(){
commentContainer.slideUp('600', function() {$(this).remove();
$('.messages').fadeOut('2000', function(){$(this).remove();
$('#messages').load("<?php echo site_url('messages/show') ?>");
});
});
}
});
return false;
});
Code is working, but when it comes to the load nothing is being shown. I did
load("<?php echo site_url('messages/show') ?>", function() {
alert('Load was performed.');
});
and there was an alert, and when I look page source I can see that the content has been changed, but it is not displayed.
When you view the source of a page that has been loaded via AJAX, it will never update. You will need to inspect the DOM in order to see what has changed.
The reason is because the content is not actually on the page and is being dynamically added to the page.

Categories