I wanna pass a JavaScript variable in to php using Ajax... coz I wanna pass it onclick. I'm getting the onclick value to variable row. Help would b gratefull :) Thank You
<script type="text/javascript">
function updateTable(row) {
alert (row);
var row = (row);
}
</script>
Did u try this?
$.ajax({
url: 'do.php',
type: 'POST',
data: "userID=" + onlyID,
success: onMemberSucces,
error:onMemberError
});
function onMemberSucces(data) {
alert(data);
}
function onMemberError() {
alert("Error!!");
}
where do.php is your php file and onlyID is your javascript variable.
Is this what you were looking for?
Related
I'm trying to call a PHP page passing parameters with AJAX. I can see that the page is called, but the $_REQUEST doesn't take any parameters. If anyone can help me, I'd appreciate it. Thanks!
My AJAX is that:
<script>
$(document).ready(function(){
$('.c_x').change(function(){
var href = $(this).val();
$.ajax({
type: "POST",
url: "utils/inc_iscrizione.php",
data: 'cod_evento=' + href,
success: function (data) {
alert("data:" + data);
}
});
})
});
</script>
In the PHP Page, I have this.
if(isset($_REQUEST["cod_evento"]))
{
$search = $_REQUEST["cod_evento"];
echo "<script>alert('OK');</script>";
}
else
{
$search = "";
echo "<script>alert('FAIL');</script>";
}
Always the answer is failure. Thank you!
1- change your data format in ajax request from data:'cod_evento=' + href, to data : {code_evento:href}
2 - change your php echo from echo "alert('OK');" to echo "OK"; and same for else clause
Recommended
1 - change $_REQUEST to $_POST
2 - change alert('data:'+ data) to console.log(data)
I have some problem with passing value from javascript file to php file.
I make some calculations in JS, and after that i passing it to php.
This is a code of JS:
var price=100;// for example
$.ajax({
type: "POST",
url: "SecureRide.php",
data: { calculatedPrice: price }
});
And this is a code of PHP:
<?php
session_name("ridePrice");
session_start();
$_SESSION["calculatedPrice"]=$_POST["calculatedPrice"];
echo $_SESSION["calculatedPrice"];
?>
So what i do is a simple Ajax function that passes the value to php, very simple, but doesn't work!
When I do echo function there's nothing there.
Maybe there are another way to solve it?
Thank you very much!
Note : if you are put your ajax code in function and than call function from the "$(document).ready(function(){" then your code run perfectly
I write code in your .js file :
$(document).ready(function(){
functionName(price);
});
function functionName(price){
$.ajax({
url: 'SecureRide.php',
data:{calculatedPrice: price},
type: 'POST',
success:function(data)
{
alert(data);
},
error:function(data)
{
alert("mistake in your code");
}
})
}
And Code For PHP file for get .JS File Data
if(isset($_POST['calculatedPrice']) && !empty($_POST['calculatedPrice']))
{
$calculatedPrice1=$_POST['calculatedPrice'];
}
I have a PHP program for counting user banner clicks. My banner link is something like this:
<a href="<?=$banner_url;?>" onclick="banner_click_count('<?=$banner_id;?>')"><img src=...>
When user clicks on image, it runs banner_click_count() function with $banner_id as parameter.
function banner_click_count($ban_id)
{
$.ajax({
type: "POST",
url: 'banner_click.php',
data: {banner_id: $ban_id}
});
}
At banner_click.php, I get the banner_id with $banner_id = $_GET['banner_id']);, search the database based on it. Find the record, then add 1 to banner_count column field. After that, redirect to banner_url.
When I run the program, I get Parse error: parse error, expecting T_VARIABLE' or '$'' on line $.ajax({
Addendum: the error is cleared with all your help, but when I click on the link it redirects to banner_url directly and does not run the AJAX function.
Addendum:I put the alert("hello"); at the top of ajax function and i got it. So it goes into function
1.You need to put your javascript function under <script> tag
2.you need to pass json string as post data
3.though you are passing your data as post so you will get this data in php as $_POST not $_GET
So change your function as below
<script>
function banner_click_count(ban_id)
{
$.ajax({
type: "POST",
url: 'banner_click.php',
data: {banner_id: ban_id}
});
}
</script>
// in your php use as below
echo $_POST['banner_id']
Make sure banner_id is in quotes and that you are including JQuery in your page.
And don't forget a success/error return.
$.ajax({
type: "POST",
url: 'banner_click.php',
data: {'banner_id': $ban_id},
success: function(s) {
console.log('success' + s);
},
error: function(e) {
console.log('error' + e);
}
});
Don't we need a return false before the function ends?
I found the solution. Thanks to all.
function banner_click_count(ban_id)
{
$.post(
"banner_click.php",
{
banner_id: ban_id
});
}
This is the code that I'm using to send a variable (via GET) to another php file:
(basically, I click on a button, and then js gets the id and sends the id via ajax to the php file.
$(document).ready(function() {
$(".doClick").click(function() {
var category=$(this).attr('id');
$.ajax({
url:'aFile.php',
type:'GET',
data: $category,
success: function(data){
alert("It worked?"); // this is the response
}
});
alert($(this).attr("id"));
});
});
This is the code in my aFile.php:
The php file gets the info via $_GET[] and then assigns it to a variable and uses that variable in a function call.
<head>
<script type="text/javascript">
$(document).ready(function() {
function JS() {
//code
});
</script>
</head>
<body onload="JS()">
<?php
$category = $_GET['category'];
if (function_exists('inventory_insert')) {
echo inventory_insert('{category_name = '.$category.'}');
} else echo('warning');
?>
It's supposed to give me a response back on my main page, but nothing seems to be happening. I don't even get the alert I posted after the ajax script.
your variable is category but you're sending data: $category
You must send key/value pair to server
to receive $_GET['category'] your data sent in ajax needs to be either:
data: 'category='+category
Or
data: {category: category}
You have assigned id into category in jquery. so correct in data params.
data: {category : category},
Send it in this way to server or php file.
$(document).ready(function() {
$(".doClick").click(function() {
var category=$(this).attr('id');
$.ajax({
url:'aFile.php',
type:'GET',
data: {category : category},
success: function(data){
alert("It worked?"); // this is the response
}
});
alert($(this).attr("id"));
});
});
I've created one Ajax function like this:
function searchPlanAjax(url){
jQuery('#loader').css('display','block');
var plan = jQuery('.rad').val();
var site = url+"fbilling_details/subscription";
jQuery.ajax({
type: "POST",
url: site,
data: "plan="+plan,
//data: "business_name="+val+"&bs="+bs,
success: function(msg){
jQuery('#loader').css('display','none');
}
});
}
Which I'm calling on radio button's onclick:
<?php echo $form->text(BILLING_DETAIL.'][id_plan', array('type'=>'radio', 'value'=>$val[PLAN]['id'], 'id'=>'id_plan_'.$val[PLAN]['id'], 'class'=>'rad','onclick'=>'searchPlanAjax('."'".SITE_NAME.ROOT_FOLDER_NAME."'".')')); ?>
The Ajax call will be processed in controller of cakePHP like this:
if(!empty($_REQUEST['plan'])){
$search_plan = $this->{PLAN}->find("all",array("conditions"=>array("id=".$_REQUEST['plan'])));
$this->set('search_plan',$search_plan);
}
but I couldn't get value in $search_plan variable. thanks if anybody can help.
Look at conditions in your find query
if(!empty($_REQUEST['plan'])){
$search_plan = $this->{PLAN}->find("all",array("conditions"=>array("id" => $_REQUEST['plan'])));
$this->set('search_plan',$search_plan);
}