I am trying to use Object Oriented code to display users (management) in a database, The variables are loaded with the right info for connection, My DB code is
/* Code to Connect to the Database */
$mysqli = new mysqli($host, $username, $password);
if($mysqli->connect_errno){
echo "Failed to connect to the Database: " . $mysql->connect_error;
}
and the code i'm using to display the users is
$query = ("SELECT m_username, m_email, m_fname, m_sname, m_mccode, m_mobile FROM management");
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf ($row["m_username"], $row["m_email"], $row["m_fname"], $row["m_sname"], $row["m_mccode"], $row["m_mobile"]);
}
/* Frees the result set */
$result->close();
/* Close the Connection */
$mysqli->close();
}
When I go to the page that has this code, I get nothing displayed and there is users in the DB.
You haven't provided database name, so database not selected. Change mysqli_connect() arguments:
$db = 'mydbname';
$mysqli = new mysqli($host, $username, $password, $db);
Also, you may try to add MySQL debug messages, while testing your scripts:
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf ($row["m_username"], $row["m_email"], $row["m_fname"], $row["m_sname"], $row["m_mccode"], $row["m_mobile"]);
}
/* Frees the result set */
$result->close();
} else {
/* Show error message */
echo $mysqli->error;
}
/* Close the Connection */
$mysqli->close();
Related
I'm transitioning from MYSQL to MYSQLI and I am in need of assistance with putting MYSQLI into separate / distinct functions.
From all the "tutorials" i have located on the web, they all have everyrything in one big long code, and not distinct / separate functions that my main scripts can call.
Eg :-
Connect to MYSQLI
Do SELECT
Exit MYSQLI
what i'm after is :-
MYSQLI.PHP
<?
function connect_mysqli()
{
$con=mysqli_connect("localhost","wrong_user","my_password","my_db");
// Check connection
if (!$con)
{
die("Connection error: " . mysqli_connect_errno();
}
// Return the connection back to where i called it ??
}
function do_query ($sql)
{
$row = $con->query("$sql")->fetch_array();
return $row;
}
function close_mysqli()
{
$mysqli->close();
}
?>
in my script i want to call :-
another.php
<?
include_once("MYSQLI.PHP");
connect_mysqli();
....
do some SELECT
do some UPDATE
close_mysqli();
?>
So far, from the error codes I am receiving, the "connection" to mysqli is not being passed to/from my other script(s)
Has anyone got a working / tested example of mysqli using functions (not just half the code) - but a working example of simple SELECT
Once i get that far, i can do the rest.
fix your include file to
/**
* #return mysqli
*/
function connect_mysqli()
{
$con = mysqli_connect("localhost","wrong_user","my_password","my_db");
// Check connection
if (!$con)
{
die("Connection error: " . mysqli_connect_errno());
}
return $con;
}
function do_query ($con, $sql)
{
$row = $con->query("$sql");
if($row) {
return $row->fetch_array();
}
return null;
}
function close_mysqli($con)
{
$con->close();
}
now you can run a script like this
include_once("MYSQLI.PHP");
$connection = connect_mysqli();
if(null !== $connection) {
print_r(do_query($connection, "SELECT * FROM yourTable"));
close_mysqli($connection);
}
but for correct handling create a connection interface and a implementation for mysqli like this
interface myConnectionClass {
function connect();
....
}
and a mysqli implementation
class myMysqlIConnection implements myConnectionClass {
function connect() {
//do more... save connection etc...
return true; //sucess
}
}
Example Demos
Scroll down there are a lot of exmaples...
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
/* Create table doesn't return a resultset */
if ($mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City") === TRUE) {
printf("Table myCity successfully created.\n");
}
/* Select queries return a resultset */
if ($result = $mysqli->query("SELECT Name FROM City LIMIT 10")) {
printf("Select returned %d rows.\n", $result->num_rows);
/* free result set */
$result->close();
}
/* If we have to retrieve large amount of data we use MYSQLI_USE_RESULT */
if ($result = $mysqli->query("SELECT * FROM City", MYSQLI_USE_RESULT)) {
/* Note, that we can't execute any functions which interact with the
server until result set was closed. All calls will return an
'out of sync' error */
if (!$mysqli->query("SET #a:='this will not work'")) {
printf("Error: %s\n", $mysqli->error);
}
$result->close();
}
$mysqli->close();
?>
I want to create a php script using prepared statements to query a table in my database and return the results in json format. I have a table of doctors and i want to return the doctors of a given speciality. I have a version of the script that doesn't use prepared statements that works fine. But when i use prepared statements my script doesn't work.
Non - prepared statements version:
<?php
// include database constants
require_once("../config/config.php");
// create db connection
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$mysqli->set_charset("utf8");
$speciality = $_POST['speciality'];
$query = "SELECT * FROM `doctors` WHERE speciality='$speciality'";
$result = $mysqli->query($query) or die("Error executing the query");
while($row = $result->fetch_assoc()) {
$output[]= $row;
}
print(json_encode($output));
$mysqli->close();
?>
prepared statements version:
<?php
// include database constants
require_once("../config/config.php");
// create db connection
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$mysqli->set_charset("utf8");
$speciality = $_POST['speciality'];
$query = "SELECT * FROM `doctors` WHERE speciality=?";
if ($stmt = $mysqli -> prepare($query)){
$stmt -> bind_param("s", $speciality);
$stmt -> execute();
$result = $stmt -> get_result();
while($row = $result -> fetch_assoc()) {
$output[]= $row;
}
print(json_encode($output));
$stmt -> close();
} else {
echo $mysqli->error;
echo "no entry found";
}
$mysqli->close();
?>
What am i doing wrong? I don't get a mysqli error which means that the problem is after the execution of the query but i just don't know what it is.
Edit: What i mean by saying it doens't work is that i don't get anything back. The html body of the page after the execution is completely empty. On the other hand if i use the other script i posted (without prepared statements) i get the expected result.
UPDATED:
Use this:
/* bind result variables */
$stmt->bind_result($col1,$col2,$col3,$col4);
/* fetch values */
while ($stmt->fetch()) {
$output[]=array($col1,$col2,$col3,$col4);
}
Instead. Hope it helps.
anyone please give reason of putting downvote.
ini_set('display_errors',1);
error_reporting(E_ALL);
and then look at HTML body again. Most likely get_result is not supported but I hate to guess.
Make sure your version of PHP is compatible with the method
http://php.net/manual/pt_BR/mysqli-stmt.get-result.php
To get data as associative array you can do as follow:
$stmt->bind_result($col1, $col2);
$rows = [];
while ($stmt->fetch()) {
$rows[]=array("col1"=>$col1, "col2"=>$col2);
}
i want to execute a more then 3 queries in a single statement.
is is possible?
i need to insert the values into the table
select entire table
count the users.
is it possible to do all these in a single statement.
Thanks
You can use more than 3 queries only in mysqli using mysqli_multi_query(), but mysql doesn't support it.
Example code :
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "SELECT CURRENT_USER();";
$query .= "SELECT Name FROM City ORDER BY ID LIMIT 20, 5";
/* execute multi query */
if ($mysqli->multi_query($query)) {
do {
/* store first result set */
if ($result = $mysqli->store_result()) {
while ($row = $result->fetch_row()) {
printf("%s\n", $row[0]);
}
$result->free();
}
/* print divider */
if ($mysqli->more_results()) {
printf("-----------------\n");
}
} while ($mysqli->next_result());
}
/* close connection */
$mysqli->close();
?>
Change it accordingly. It shows multiquery in action using mysqli.
I have a database in which I have a main form that list all personnel using this code
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("datatest", $con);
$result = mysql_query("SELECT * FROM Personnel");
echo "<TABLE BORDER=2>";
echo"<TR><TD><B>Name</B><TD><B>Number</B><TD><B>View</B><TD></TR>";
while ($myrow = mysql_fetch_array($result))
{
echo "<TR><TD>".$myrow["Surname"]." ".$myrow["First Names"]."<TD>".$myrow["Number"];
echo "<TD>View";
}
echo "</TABLE>";
?>
</HTML>
As you can note I have a link to view details of the person but when I click on the VIEW link I get the following error
Parse error: syntax error, unexpected 'EmployeeID' (T_STRING) in C:\Program Files\EasyPHP-12.1\www\my portable files\dss4\childdetails.php on line 6
The childdetails.php has the following code
<HTML>
<?php
$db = mysql_connect("localhost", "root", "");
mysql_select_db("datatest",$db);
$result = mysql_query("SELECT * FROM children;
WHERE "EmployeeID="["$EmployeeID"],$db);
$myrow = mysql_fetch_array($result);
echo "Child Name: ".$myrow["ChildName"];
echo "<br>Mother: ".$myrow["Mother"];
echo "<br>Date of Birth: ".$myrow["DateOfBirth"];
?>
</HTML>
Since the first form to list the personnel works I believe the problem is in childdetails.php on line 6 as returned by the server but I simply don’t know how to fix it.
Note: a person can have more than one child as well as having more than one wife
Help please
I would say more like.
$result = mysql_query("SELECT * FROM children WHERE EmployeeID='$EmployeeID'");
// as far $EmployeeID is actualy set before running a query
//but as comment says don't use mysql better something like this
<?php
$mysqli = new mysqli('localhost', 'root', 'my_password', 'my_db');
if ($mysqli->connect_error) {
die('Connect Error (' . $mysqli->connect_errno . ') '
. $mysqli->connect_error);
}
/* create a prepared statement */
if ($stmt = $mysqli->prepare("SELECT * FROM children WHERE EmployeeID=?")) {
/* bind parameters for markers */
$stmt->bind_param("s", $EmployeeID);
/* execute query */
$stmt->execute();
/* bind result variables */
$stmt->bind_result($Employee);
/* fetch value */
$stmt->fetch();
printf($Employee);
/* close statement */
$stmt->close();
}
/* close connection */
$mysqli->close();
To begin with, your query is wrong, you're telling the sql that your script is over and that it should start executing something new. I'll show you how to do it properly here below.
Also, don't use mysql specific syntax, It's outdated and can get you into real trouble later on, especially if you decide to use sqlite or postgresql.
Also, learn to use prepared statements to avoid sql injection, you want the variables to be used as strings into a prepared query, not as a possible executing script for your sql.
Use a PDO connection, you can init one like this:
// Usage: $db = connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword);
// Pre: $dbHost is the database hostname,
// $dbName is the name of the database itself,
// $dbUsername is the username to access the database,
// $dbPassword is the password for the user of the database.
// Post: $db is an PDO connection to the database, based on the input parameters.
function connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword)
{
try
{
return new PDO("mysql:host=$dbHost;dbname=$dbName;charset=UTF-8", $dbUsername, $dbPassword);
}
catch(PDOException $PDOexception)
{
exit("<p>An error ocurred: Can't connect to database. </p><p>More preciesly: ". $PDOexception->getMessage(). "</p>");
}
}
And then init the variables:
$host = 'localhost';
$user = 'root';
$dataBaseName = 'databaseName';
$pass = '';
Now you can access your database via
$db = connectToDatabase($host , $databaseName, $user, $pass); // You can make it be a global variable if you want to access it from somewhere else.
Now you should construct a query that can be used as a prepared query, that is, it accepts prepared statements so that you prepare the query and then you execute an array of variables that are to be put executed into the query, and will avoid sql injection in the meantime:
$query = "SELECT * FROM children WHERE EmployeeID = :employeeID;"; // Construct the query, making it accept a prepared variable.
$statement = $db->prepare($query); // Prepare the query.
$statement->execute(array(':employeeID' => $EmployeeID)); // Here you insert the variable, by executing it 'into' the prepared query.
$statement->setFetchMode(PDO::FETCH_ASSOC); // Set the fetch mode.
while ($row = $statement->fetch())
{
$ChildName = $row['ChildName'];
$Mother = $row['Mother'];
$DateOfBirth = $row['DateOfBirth'];
echo "Child Name: $ChildName";
echo "<br />Mother: $Mother";
echo "<br />Date of Birth: $DateOfBirth";
}
You should use a similar approach to receive $EmployeeID but this should help you a lot.
By the way: remember to close your break tags with a whitespace ' ' and a forwardslash like I showed you.
You
Need
change your query something like this
<HTML>
<?php
$db = mysql_connect("localhost", "root", "");
mysql_select_db("datatest",$db);
$result = mysql_query("SELECT * FROM children WHERE EmployeeID=" . $EmployeeID, $db);
$myrow = mysql_fetch_array($result);
echo "Child Name: ".$myrow["ChildName"];
echo "<br>Mother: ".$myrow["Mother"];
echo "<br>Date of Birth: ".$myrow["DateOfBirth"];
?>
</HTML>
Can any one give
The Example php code for connecting and getting a sql stored proceedure
what do you prefer to use? Here is an example taken from php.net:
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "CALL get_items(1, #param1, #param2); ";
/* execute multi query */
if ($mysqli->multi_query($query)) {
do {
/* store first result set */
if ($result = $mysqli->store_result()) {
while ($row = $result->fetch_row()) {
printf("%s\n", $row[0]);
}
$result->free();
}
/* print divider */
if ($mysqli->more_results()) {
printf("-----------------\n");
}
} while ($mysqli->next_result());
}
/* close connection */
$mysqli->close();
remember, that you have to free the resultset, if you do not, you will get an error while executing a next query.
Before I know something about mysqli, I apply mysqli to handle sp's. Just take a look at the follwing example:
$rs = mysql_query("CALL get_items(1, #param1, #param2); ");
$rs = mysql_query("SELECT #param1, #param2" );
while($row = mysql_fetch_assoc($rs))
{
print_r($row);
}
Calling a Stored procedure with PDO