video file name doesn't load correctly - php

Question

I'm new to PHP. Everything else works on my site okay but I seem to have an issue with this particular piece of code. The $efn is my file name, and I need to retrieve it from a MySQL database but this code doesn't seem to work. It works in a normal video container but not when using the if statement.
Any ideas how to fix this?
<?php
$video_container = substr($efn, -3);
if ($video_container == 'mp4') {
echo '<video preload="auto" width="640" height="264" poster="../images/<?php echo $thumb ?>" controls="controls" autoPlay="false">
<source src="<?php echo $efn ?>" type="video/mp4">
</video>';
}
else {
echo '<video height="620" width="480" controls>
<source src="<?php echo $efn ?>" type ="video/avi" />
</video>';
}
?>

Answer 1

You have syntax problem when printing the string. Replace the <?php echo $fn ?> section by ' . $efn . '
Like this:
$video_container = substr($efn, -3);
if ($video_container == 'mp4') {
echo '<video preload="auto" width="640" height="264" poster="../images/<?php echo $thumb ?>" controls="controls" autoPlay="false">
<source src="' . urlencode($efn) . '" type="video/mp4">
</video>';
}
else {
echo '<video height="620" width="480" controls>
<source src="' . urlencode($efn) . '" type ="video/avi" />
</video>';
}