strip_tags truncating JSON - php

I have a JSON Response like this:
{
"id":"2461",
"name":"GEORGIA INSTITUTE OF <leo_highlight style=border-bottom: 2px solid rgb(255, 255, 150); background-c",
"logo":"",
"address":null,
"city":null,
"state":null,
"campus_uri":"{{PATH}}2461\/"
},
....
....
When I do strip_tgs on this one, the whole JSON string is getting truncated at the name tag above. The JSON string looks like this.
{"id":"2461","name":"GEORGIA INSTITUTE OF
All below this line is gone. This is a huge JSON. But its getting truncated here.
Any ideas on what to do? I need to strip out all HTML tags.
Update:
Adding more details...
This JSON string I got is from encoding the query results array. So I get array from MySQL query and I encoded it with json_encode and trying to strip_tags on it.

$array = json_decode($json, true);
array_walk_recursive($array, function (&$val) { $val = strip_tags($val); });
$json = json_encode($json);
As simple... Decode it, walk through and encode it.

Strip out the tags after you have decoded the JSON object. You might do this in a lazy fashion (i.e. when needed) rather than go through every item an strip tags on all fields.

Related

Json string conversion to json object

I have been stuck in this issue and cant seem to fix it.. I have this JSON STRING
$unBillableArr = ["{'id' : '123','to' : '+923412268656','MsgReceivedFrom' : '03349433314', 'message':'Qwertyy ', 'recdate':'2017-11-20 19:01:49'}"];
I need to convert it into array of object or maybe just one json object.. I have tried doing
json_decode($unBilledArr , true);
It gives me null.
Already tried these solutions as well
Convert a string to JSON object php
https://jonsuh.com/blog/convert-loop-through-json-php-javascript-arrays-objects/
I must be doing something wrong.. cant seem to figure out what..
P.s : This is the response i am getting and i can not do anything about the response.
You are trying to decode an array, either specify the specific item within the array, or make it a string.
For instance:
$unBillableArr = '{"id":"123", "to":"+923412268656", "MsgReceivedFrom":"03349433314", "message":"Qwertyy", "recdate":"2017-11-20 19:01:49"}';
$json = json_decode($unBillableArr, true);
// Or
$unBillableArr = ['{"id":"123", "to":"+923412268656", "MsgReceivedFrom":"03349433314", "message":"Qwertyy", "recdate":"2017-11-20 19:01:49"}'];
$json = json_decode($unBillableArr[0], true);
However, given the string you are receiving does not contain valid JSON and you are unable to control what you receive, I have prepared the following that will replace the single quotes in your JSON, and decode each item into an array:
$unBillableArr = ["{'id' : '123','to' : '+923412268656','MsgReceivedFrom' : '03349433314', 'message':'Qwertyy ', 'recdate':'2017-11-20 19:01:49'}"];
// Loop through each JSON string
$jsonObjects = []; // Change this name...
foreach ($unBillableArr as $jsonString) {
$jsonObjects[] = json_decode(str_replace("'", '"', $jsonString), true);
}
print_r($jsonObjects); // Proof it works
Please bear in mind that I would consider this to be a dirty fix. To fix this properly, you should go back to the source and ensure that the JSON they are returning to you is valid.

Formatting JSON formatted text file in PHP

So I got a HTML page with a button. When I click the button, a separate javascript file sends a GET request to my PHP file, expecting a JSON object in return. My PHP reads a JSON formatted text file and should convert it into a JSONObject and echo it out for my javascipt. I had some code working before, but it doesn't seem to do it anymore since I changed to a Ajax aproach instead of having everything in the same file. This is my code:
readLog.php
<?php
class test{
function clean($string){
return json_decode(rtrim(trim($string),','),true);
}
function getLog(){
header('Content-Type: application/json');
$logLines = file('../../../home/shares/flower_hum/humid.log');
$entries = array_map("clean",$logLines);
$finalOutput = ['log' => $entries];
echo json_encode($logLines);
}
}
?>
My humid.log file looks like this:
{"date":"26/09/2016", "time":"22:40:46","temp":"16.0", "humidity":"71.0" }
{"date":"26/09/2016", "time":"23:10:47","temp":"16.0", "humidity":"71.0" }
Now If I press my button, this is the response I get checking the console in my web browser:
Response:
["{\"date\":\"26\/09\/2016\", \"time\":\"22:40:46\",\"temp\":\"16.0\", \"humidity\":\"71.0\" }{\"date\":\"26\/09\/2016\", \"time\":\"23:10:47\",\"temp\":\"16.0\", \"humidity\":\"71.0\" }\n"]
JSON:
"{"date":"26/09/2016", "time":"22:40:46","temp":"16.0", "humidity":"71.0" }{"date":"26/09/2016", "time":"23:10:47","temp":"16.0", "humidity":"71.0" }\n"
obviously something is wrong with the formatting, but I don't know what. As I said, this code worked just fine when I had my php and HTML in the same file.
EDIT:
I have also tried formatting the JSON with something like this, but it just prints the brackets:
function getLog(){
$text = file('../../../home/shares/flower_hum/humid.log');
$textRemoved ="["; //Add opening bracket.
$textRemoved .= substr($text, 0, strlen($text)-1); (Remove last comma)
$textRemoved .="]";//Add closing bracket
$json = json_encode($textRemoved);
echo $json;
}
So I managed to solve it myself. Basicly The formatting of the textfile was wrong and as some commentors said, I don't need to encode it if I am doing it myself. What I ended up doing was in my application that generates the log file to add comma after each row. Then in my PHP I added brackets and removed the last comma.
function getLog(){
header('Content-Type: application/json');
$file = file_get_contents('../../../home/shares/flower_hum/humid.log');
$lengthOfFile = strlen($file)-2;
$subFile = substr($file, 0, $lengthOfFile);
$res ="[";
$res .= $subFile;
$res .="]";
echo $res;
}
You can't just jam two+ JSON strings togther. It's JSON, which means it HAS to be syntactically correct Javascript CODE. If you want to join two json strings together, you HAVE to decode them to a native data structure, join those structures together, then re-encode the new merged structure:
$temp1 = json_decode('{"foo":"bar"}', true);
$temp2 = json_decode('{"baz":"qux"}', true);
$new = array_merge($temp1, $temp2);
echo json_encode($new);
which will produce:
{"foo":"bar","baz":"qux"}
and remain valid JSON/Javascript.
Why? Consider that bare integers are valid json:
json_encode(42) -> 42
json_encode(123) -> 123
If you have two json-encoded integers and jam together, you get a "new" integer:
42123
and on the receiving end, you'll be going "Ok, so where is the split between the two", because 4 and 2123 are just as valid as possible original values as 4212 and 3.
Sending the two integers as distinct and SEPARATABLE values would require an array:
[42,123]

PHP jSon data clean values for unwanted white spaces

Below is my JSON data which i get it by using
$json = json_encode($array);
my JSON Data;
{
"id":"352",
"date":"2013-12-25 01:10:06",
"category":"2",
"subtitle":null,
"description":" This text is description... ",
"hit":"144",
"rate":"50.00",
"active":"1"
}
Think that there are thousands of items like this.
But the problem is how can I trim the description value of this object automatically when running json_encode?
I dont wanna use "for each" because of performance i think.
Thanks...
use trim in array_map as :
$json = json_encode(array_map('trim',$array));

Parsing JSON in PHP with a prepend of sorts

if my JSON data is coming back as this:
{"errorCodes":[0]}resultArray=[{....}]
how do I grab the resultArray as the actual JSON string and ignore the rest?
and why would I need errorCodes in front of it?
Just use string manipulation to get rid of everything up through resultArray= and then decode with json_decode().
$json_raw = '...'; // the raw "JSON" string
$delimiter = 'resultArray=';
$cleaned_json = substr($json_raw, strpos($json_raw,$delimiter) + strlen($delimiter)));
$object = json_decode($cleaned_json);

json inside function, (php parsing)

I have sth like that inside *.txt file.
function_name({"one": {"id": "id_for_one", "value": "value_for_one"}, ...});
And I am getting the file like this:
$source = 'FILE_NAME.txt';
$json = json_decode(file_get_contents($source),true);
echo $json['one']['value'];
It doesn't work, but when I remove function_name( and ); it works.
How to parse it without removing these strings?
You can't. It is not valid JSON with those. Take a substring that excludes them.
You will have to remove those strings. With the function_name portion it is not valid JSON.
A JSON string will typically either begin with { (object notation) or [ (array notation), but can also be scalar values such as a string or number. You cannot parse it without first making sure the string is valid JSON.
You are trying to get the string within a file and decoding it as a JSON file.
The 'function_name' isn't a valid JSON string, the rest inside yes.
How to parse it without removing these strings?
There is no way.
This should work for you.
$data = file_get_contents($source);
$data = substr($data, strlen("function_name("));
$data{strlen($data)-1}=$data{strlen($data)-2}=" ";
$json = json_decode($data,true);
Both {} and [] works for string to access individual characters.
The function in your text file, means that isn't a json file.
Remove the string using a regular expression, and your problem is fixed.
If the function is a fixed name, do something like this:
$source = 'FILE_NAME.txt';
$json_content = str_replace('function_name(', '', file_get_contents($source));
$json_content = substr($json_content,0,-2);
$json = json_decode($json_content,true);
echo $json['one']['value'];

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