Show blob file(text + img) in website. From phpbb database - php

Question

I have a phpbb forum and I want to show the latest 3 post in my website. I can connect to the DB and retrieve what I want but not img from post. Post content is stored as Blob, when I do a post looks like:
"Hello this is a test post.
[img]http://www.petfinder.com/wp-content/uploads/2012/11/101418789-cat-panleukopenia-fact-sheet-632x475.jpg[/img]
End of the file."
In the forum you can see the text and the image. But when I show the post in my website it looks like:
(Hello this is a test post. [img:3vv18at0]http://www.petfinder.com/wp-content/uploads/2012/11/101418789-cat-panleukopenia-fact-sheet-632x475.jpg[/img:3vv18at0]End of the file.)
Show the entery post as text, I would like to see the post as in the forum, text and images in their places.
This is the code I am using:
<?php
$conexion = mysql_connect("localhost","MYUSER","MYPASS");
$nPost = "0,3";
//DB a la que me conecto
mysql_select_db("DATABASE", $conexion) OR die("No se puede establecer la conexión a MySQL");
$consulta1 = "SELECT * FROM phpbb_topics WHERE forum_id = '4' ORDER BY topic_id DESC LIMIT $nPost";
$resultado1 = mysql_query($consulta1);
$consulta2 = "SELECT * FROM phpbb_posts WHERE forum_id = '4' ORDER BY topic_id DESC LIMIT $nPost";
$resultado2 = mysql_query($consulta2);
while ($row = mysql_fetch_array($resultado1)) {
$datosPost = mysql_fetch_array($resultado2);
$id = "$row[topic_id]";
$titulo = "$row[topic_title]";
$respuestas = "$row[topic_replies]";
$by = "$row[topic_first_poster_name]";
$text = "$datosPost[post_text]";
///////////////////EDIT AND WORKING//////////////////
$b = preg_replace('#\[img:(.*?)\](.*?)\[/img:(.*?)\]#s', '<br><img src="$2"/><br> ', $text);
$c = preg_replace('#\((.*?)\)#s', '$1', $b);
$text = $c;
////////////////////////THANKS TO damienkeitel//////////////
echo"<a href='http://www.compraclientes.com/foro/viewtopic.php?f=4&t=$id'><div class='postEntry'><div class='postHeader'><div class='postTitle'>$titulo</div><div class='postOwner'>(By $by)</div> <div class='postReplies'>($respuestas Respuestas)</div></div><div class='postText'>($text)</div></div></a>";
}
mysql_close($conexion);
?>
Thank you very much

Answer 1

$a = "(Hello this is a test post. [img:3vv18at0]http://www.petfinder.com/wp-content/uploads/2012/11/101418789-cat-panleukopenia-fact-sheet-632x475.jpg[/img:3vv18at0]End of the file.)";
$b = preg_replace('#\[img:(.*?)\](.*?)\[/img:(.*?)\]#s', '<br><img src="$2"/><br> ', $a);
$c = preg_replace('#\((.*?)\)#s', '$1', $b);
echo $c;
http://www.damienkeitel.com/pr.php <-- demo

Answer 2

I believe one of my previous answers, slightly modified, can provide you with information you need.
Display the 5 most recent posts on an external page
The short answer to your question is this chunk of code. This will clean up various aspects of your data.
$topic_title = $posts_row['topic_title'];
$post_author = get_username_string('full', $posts_row['poster_id'], $posts_row['username'], $posts_row['user_colour']);
$post_date = $user->format_date($posts_row['post_time']);
$post_link = append_sid("{$phpbb_root_path}viewtopic.$phpEx", "p=" . $posts_row['post_id'] . "#p" . $posts_row['post_id']);
$post_text = nl2br($posts_row['post_text']);
$bbcode = new bbcode(base64_encode($bbcode_bitfield));
$bbcode->bbcode_second_pass($post_text, $posts_row['bbcode_uid'], $posts_row['bbcode_bitfield']);
$post_text = smiley_text($post_text);
As I mention in the previous answer, that code is based on Example 4 the PHPBB Wiki.