The idea is to obtain in a javascript variable an array provided by a mysql query. It works fine, but the result of the variable shows minus 1 row than the query.
Below I have provided just the code ref the problem, skipping all of the rest, I suppose isn't needed.
Thanks in advance for help!
The query:
$search_qryvalAltnsRotas = "-1";
if (isset($_GET['search'])) {
$search_qryvalAltnsRotas = $_GET['search'];
}
mysql_select_db($database_connect, $connect);
$query_qryvalAltnsRotas = sprintf("SELECT altn, destino FROM tblalternativos WHERE destino = %s ORDER BY destino ASC", GetSQLValueString($search_qryvalAltnsRotas, "text"));
$qryvalAltnsRotas = mysql_query($query_qryvalAltnsRotas, $sado_leitor) or die(mysql_error());
$row_qryvalAltnsRotas = mysql_fetch_assoc($qryvalAltnsRotas);
$totalRows_qryvalAltnsRotas = mysql_num_rows($qryvalAltnsRotas);
(...) below is the variable (part of a javascript function):
var alternatesq =
<?php
while( $row_qryvalAltnsRotas = mysql_fetch_assoc($qryvalAltnsRotas) ) {
$alternates[] = $row_qryvalAltnsRotas['altn'];
}
echo json_encode( $alternates );
?>;
Because you have called mysql_fetch_assoc two times, remove this line
$row_qryvalAltnsRotas = mysql_fetch_assoc($qryvalAltnsRotas);
And use only this one
while( $row_qryvalAltnsRotas = mysql_fetch_assoc($qryvalAltnsRotas) )
Related
I have this php script.
$cwZ = count($wiegen_zutat);
$cwM = count($wiegen_menge);
$cwS = count($wiegen_schritt);
if($cwM == $cwS and $cwM == $cwZ and $cwZ == $cwS){
for($x = 0; $x < $cwZ; $x++){
$aktZuat = $wiegenZutat[$x];
$qr = "SELECT ID_Zutat FROM Zutaten WHERE Name='$aktZutat' LIMIT 1";
$id_get = mysqli_query($verbindung,$qr );
$id = mysqli_fetch_array($id_get);
$zuatenID = $id['ID_Zutat'];
echo $id['ID_Zutat'];
echo $zutatenID;
$sql3 = "INSERT INTO Wiegen (ID_Zutat, Menge) VALUES ('$zutatenID', '$wiegenMenge[$x]')";
$wiegenEintragen = mysqli_query($verbindung, $sql3);
}
}
$wiegen_zutat, _menge, _schritt are all three arrays which contain the information from my form.
I go through the first array, and check the variable against a table which contains the ingredients for my website. I want to get the id of a ingredient which was added some steps before and add it into another table.
The problem is that neither the echos or the query are working.
What am I missing?
Please don't get confused by the name of the variables, I'm german :)
Best regards
EDIT1 : used double quotes and single quotes but I am getting same error.
EDIT2 : same query is returning me result in mysql shell
I am selecting a row from a table.
if(!isset($_GET['title']) || !isset($_GET['user'])){
echo "hi"; //something come here
}
else{
$title = $_GET['title'];
$title = mysqli_real_escape_string($conn,$title);
$user = $_GET['user'];
$user = mysqli_real_escape_string($conn,$user);
echo $title ;
echo $user ;
// tried giving value directly to test but no luck
$query = "SELECT * FROM site WHERE client=\"Chaitanya\" && title=\"werdfghb\" ";
$result5 = mysqli_query($conn,$query) or die(mysqli_error());
$count = mysqli_num_rows($result5);
echo $count ;
while($result9 = mysqli_fetch_array($result5)){
$kk=$result9['url'];
echo $kk ;
}
$page = $kk;
include ( 'counter.php');
addinfo($page);
}
In my database there is a row with columns title and client and the values I entered are in that row but when I echo count(no of rows) it is showing zero.
Is there anything wrong with code ?
The error you are getting is due to the line
$page = $kk;
in this code $kk is not declared previously. The defined $kk is in the while loop scope.
declare the variable like this in the outer scope from the while loop
...
$kk = null;
while($result9 = mysqli_fetch_array($result5)) {
$kk = $result9['url'];
echo $kk ;
}
$page = $kk;
...
Error on Fetching Data
You have to crack you SQl into smaller pieces and test the code like this.
run the query SELECT * FROM site without any where and get the count
run the query SELECT * FROM site WHERE client='Chaitanya' and get the count
SELECT * FROM site WHERE title='werdfghb' and check the count
Then run the whole query
And see the results. This way u can find out in where the issue is in your SQL code. I prefer you use the mysql client to execute this queries
As I pointed out in my comment, $kk is undefined in the $page = $kk;, since it is declared in the while loop.
Do something like:
$kk = ''; //can also do $kk=NULL; if you want.
while($result9 = mysqli_fetch_array($result5)) {
$kk=$result9['url'];
echo $kk ;
}
$page = $kk;
try this one
$client = "Chaitanya";
$title = "werdfghb";
$query="SELECT * FROM site WHERE client='".$client."' and title='".$title."' ";
you can also use this
$query="SELECT * FROM site WHERE client={$client} and title={$title} ";
why $subadmin = 1 row only?
i have few users with "MaTeam = 8"
but its select 1 user only!
my code:
$query8 = mysql_query("SELECT * FROM users WHERE MaTeam='8';");
$subadmin = array();
while ($rowa = mysql_fetch_array($query8)) {
$subadmin=$rowa["username"];
}
Your while loop is overwriting the $subadmin value on every iteration. To append to your array you can use [] after the array variable name:
while ($rowa = mysql_fetch_array($query8)) {
$subadmin[] = $rowa["username"];
}
(Side note: Consider switching to the mysqli library since the older mysql library is deprecated.)
Replace
while ($rowa = mysql_fetch_array($query8)) {
$subadmin = $rowa["username"];
with:
while ($rowa = mysql_fetch_assoc($query8)) {
$subadmin[] = $rowa["username"];
I'm trying to accomplish the following situation:
$mysql_query = "
SELECT *
FROM st_users
WHERE
`user_comp_supervisor_id` = '$team_supervisor' AND
`user_exempt_from_goals` = '0'
ORDER BY 'calculate_progress_percent()' ASC
";
I know that I can't accomplish ordering by a function in a MySQL statement, but I'm trying to figure out how to take all the returned records, and then order them in order of highest to lowest from a php function result. Any ideas would be greatly appreciated; I've been trying to wrap my head around this for a few hours now... :-(
function diy_calc_progress_percent($user_id,$period_id,$period_week_number)
{
$this->user_id = $user_id;
$this->period_id = $period_id;
$this->period_week_number = $period_week_number;
if ($this->period_week_number == 1)
{
$this->week_id = mysql_result( mysql_query(" SELECT `period_week_one` FROM `st_comp_periods` WHERE `period_id` = '$this->period_id' "),0 );
}
else if ($this->period_week_number == 2)
{
$this->week_id = mysql_result( mysql_query(" SELECT `period_week_two` FROM `st_comp_periods` WHERE `period_id` = '$this->period_id' "),0 );
}
else
{
echo "Week number not valid.";
exit();
}
$this->week_start_date = mysql_result( mysql_query(" SELECT `week_start_date` FROM `st_comp_weeks` WHERE `week_id` = '$this->week_id' "),0 );
$this->week_end_date = mysql_result( mysql_query(" SELECT `week_end_date` FROM `st_comp_weeks` WHERE `week_id` = '$this->week_id' "),0 );
$this->user_department = $this->user_info($this->user_id,"user_comp_department_id");
$this->user_week_diy_goal = mysql_result( mysql_query(" SELECT `goal_diy_department` FROM `st_comp_department_goals` WHERE `goal_department_id` = '$this->user_department' AND `goal_week_id` = '$this->week_id' "),0 );
$this->calc_totals_result = mysql_query("SELECT SUM(record_total_diy_revenue) AS user_week_total FROM `st_entered_records` WHERE `record_user_id` = '$this->user_id' AND `record_date` BETWEEN '$this->week_start_date' AND '$this->week_end_date'");
$this->calc_totals_row = mysql_fetch_assoc($this->calc_totals_result);
$this->user_week_total = $this->calc_totals_row['user_week_total'];
$this->user_week_one_percent = ($this->user_week_total / $this->user_week_diy_goal) * 100;
$this->user_week_one_percent = number_format( (float)$this->user_week_one_percent, 2, '.', '' );
return $this->user_week_one_percent;
}
You probably will have to do some array juggling.
First get all your entries FROM st_users into a first array (mysql_query)
Then you could run through that array, and for each entry you do the calculate_progress_percent() and build up a second array in which you could add the additional info ("user_progress_percent").
After this you can sort the new array ba your new info ("user_progress_percent").
And here is some quick and dirty code-suggestions – code is however not tested… of course…:)
First:
$mysql_query = "SELECT * FROM st_users
WHERE `user_comp_supervisor_id`='$team_supervisor' AND
`user_exempt_from_goals` = '0'";
Then something like this:
$i = 0;
while($tmp = mysql_fetch_array($mysql_query)) {
$my_second_array[$i]['user_id'] = $tmp['user_id'];
$user_id = $my_second_array[$i]['user_id'];
diy_calc_progress_percent($user_id,$period_id,$period_week_number);
$my_second_array[$i]['user_result'] = $diy_calc_progress_percent_result;
$i++;
}
And then sorting that second array should be possible as described here:
Sort Multi-dimensional Array by Value
…hope this helps at some point…
I need help to convert the following Visual Basic statement into a PHP equivalent:
If Not IsNumeric(siteid) Then
dr = GetDataReader("SELECT siteid FROM nwsite WITH (NOLOCK) WHERE mac_address = '" & siteid & "'")
If Not dr.HasRows Then
Response.Write(sep & siteid & "=" & siteid)
sep = ","
End If
If Not dr Is Nothing Then
dr.Close()
End If
End If
I need help with the If statements more than anything.
Thanks
See here for the docs you need to check, also here
Seems like you also need to learn how to use mySQL in PHP
The code is relatively easy, in its simplest step- almost line for line from what you have to help you see the transformation to PHP (there are better implementations):
$siteid = 1; // where 1 is the value of siteid, PHP vars are prefixed with '$'
// you also could do
// if(!isset($siteid){
// if(!$siteid){
if(!is_numeric($siteid){
// there is no site ID, so get it from the DB
// Make a MySQL Connection
mysql_connect("localhost", "user", "password") or die(mysql_error());
mysql_select_db("dbname") or die(mysql_error());
// Run your query
$result = mysql_query("SELECT siteid FROM nwsite WITH (NOLOCK) WHERE mac_address = ".$siteid)
or die(mysql_error());
if(mysql_num_rows($result)>0){
// rows returned
//assuming only one row is returned, with your siteid value
$row = mysql_fetch_array( $result );
$siteid=$row['siteid'];
}else{
// no rows returned
// do something
}
}else{
// $siteid is already a valid value
}
AN if statement goes something like this:
if(someexpression){
$yourcode = "your things";
}
quick mockup of your code:
if(!is_numeric($siteid){
//sql call
$result = yourdb->query('SELECT');
if(!$result){
echo "error";
}
}
if(!$this->IsNumeric($siteid))
{
$dr = $this->GetDataReader("SELECT siteid FROM nwsite WITH (NOLOCK) WHERE mac_address = $siteid");
if(!$dr->hasRows())
{
echo "$sep$siteid = $siteid";
$sep = " , ";
}
if(!is_null($dr))
{
$dr->close();
}
}
Following code may help you:
if (!is_numeric($siteid)) {
$res = mysql_query("SELECT siteid FROM nwsite WHERE mac_address = " . mysql_real_escape_string($siteid));
$rows = mysql_fetch_assoc($res);
if (count($rows) == 0) {
print($sep . $siteid . "=" . $siteid);
$sep = ',';
}
}