Find week days date from range of the two dates - php

Question

$start_date = "2013-05-01";
$last_date = "2013-08-30";
How can I get dates of tuesdays and thursdays between these two dates?

Answer 1

<?php
$start = new DateTime('2013-05-01');
$end = new DateTime('2013-08-30');
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
if ($dt->format("N") == 2 || $dt->format("N") == 4) {
echo $dt->format("l Y-m-d") . "<br>\n";
}
}
See it in action
What this code does:
Creates a starting date object using DateTime.
Creates a starting date object using DateTime.
Creates a DateInterval object to represent our interval of time to iterate through. In this case 1 day.
Creates a DatePeriod object to manage these objects.
Using DatePeriod, it iterates through the date starting with the starting date and ending at the end date. We use DateTime::format() with the N parameter to get the day number of the week. If the day number of the week is 2 (Tuesday) or 4 (Thursday) echo out it's value.

Answer 2

Some PHP-Fu
$start_date = '2013-05-01';
$last_date = '2013-08-30';
$dates = range(strtotime($start_date), strtotime($last_date),86400);
$days = array('tuesday' => array(), 'thursday' => array());
array_map(function($v)use(&$days){
if(date('D', $v) == 'Tue'){
$days['tuesday'][] = date('Y-m-d', $v);
}elseif(date('D', $v) == 'Thu'){
$days['thursday'][] = date('Y-m-d', $v);
}
}, $dates); // Requires PHP 5.3+
print_r($days);
Output
Array
(
[tuesday] => Array
(
[0] => 2013-05-07
[1] => 2013-05-14
[2] => 2013-05-21
[3] => 2013-05-28
[4] => 2013-06-04
[5] => 2013-06-11
[6] => 2013-06-18
[7] => 2013-06-25
[8] => 2013-07-02
[9] => 2013-07-09
[10] => 2013-07-16
[11] => 2013-07-23
[12] => 2013-07-30
[13] => 2013-08-06
[14] => 2013-08-13
[15] => 2013-08-20
[16] => 2013-08-27
)
[thursday] => Array
(
[0] => 2013-05-02
[1] => 2013-05-09
[2] => 2013-05-16
[3] => 2013-05-23
[4] => 2013-05-30
[5] => 2013-06-06
[6] => 2013-06-13
[7] => 2013-06-20
[8] => 2013-06-27
[9] => 2013-07-04
[10] => 2013-07-11
[11] => 2013-07-18
[12] => 2013-07-25
[13] => 2013-08-01
[14] => 2013-08-08
[15] => 2013-08-15
[16] => 2013-08-22
[17] => 2013-08-29
)
)
Online demo

Answer 3

$start_date = strtotime("2013-05-01");
$last_date = strtotime("2013-08-30");
while ($start_date <= $last_date) {
$start_date = strtotime('+1 day', $start_date);
if (date('N',$start_date) == 2 || date('N',$start_date) == 4){
echo date('Y-m-d', $start_date).PHP_EOL;
}
}

Answer 4

<?php echo date('Y-m-d', strtotime('next thursday', strtotime($start_date)));
Also for tuesday ofcourse

Answer 5

Please use the following function for your solution,
function daycount($day, $startdate, $lastdate, $counter=0)
{
if($startdate >= $lastdate)
{
return $counter;
}
else
{
return daycount($day, strtotime("next ".$day, $startdate), ++$counter);
}
}
$start_date = "2013-05-01";
$last_date = "2013-08-30";
echo "Tuesday Count - ".daycount("tuesday", strtotime($start_date), strtotime($last_date));
echo "<br/>";
echo "Thursday Count - ".daycount("thursday", strtotime($start_date), strtotime($last_date));

Answer 6

Try with this
$startDate = strtotime($start_date);
$endDate = strtotime($last_date);
while ($startDate < $endDate) {
echo date('Y-m-d', $startDate ). "\n";
// Give the condition to find last Tuesday
$startDate = strtotime( 'next Tuesday', $startDate );
}

Answer 7

With DateTime:
$start_date = "2013-05-01";
$last_date = "2013-08-30";
$start = new DateTime($start_date);
$clone = clone $start;
$start->modify('next thursday');
$thursday=$start->format('Y-m-d');
$clone->modify('next tuesday');
$tuesday=$clone->format('Y-m-d');
echo $thursday; //2013-05-02
echo $tuesday; //2013-05-07
We need to objects because if in interval tuesday is before thursday we will have next tuesday. But you can modify little code to use one object.

Answer 8

With the help of few php date functions this can be solved easily..
<?php
// Create the from and to date
$start_date = strtotime("2013-05-01");
$last_date = strtotime("2013-08-30");
// Get the time interval to get the tue and Thurs days
$no_of_days = ($last_date - $start_date) / 86400; //the diff will be in timestamp hence dividing by timestamp for one day = 86400
$get_tue_thu_days = array();
// Loop upto the $no_of_days
for($i = 0; $i < $no_of_days; $i++) {
$temp = date("D", $start_date);
if($temp == "Tue" || $temp == "Thu") {
$get_tue_thu_days[] = date("D/M/Y", $start_date); //formating date in Thu/May/2013 formate.
}
$start_date += 86400;
}
print_r($get_tue_thu_days);

Answer 9

if you have a reference date which you know is a tuesday/thursday you can find days which are a multiple of 7 days from your reference date, these days will always be the same day of the week.