Kohana: Omit action from url - php

Question

Is there any way I can default a route to use action_index and not have to specify it in the url?
ie.
Route::set('user_profile','(<controller>(/<action>(/<id>)))')
->defaults(array(
'directory' => 'public',
'controller' => 'user',
'action' => 'index',
));
To use that I need to specify /users/index/1234
But I'd like to use /users/1234
I tried taking out action from the Route::set() but I ended up with a 404 page.
UPDATE
Now that I have added this route (the top one) my default route doesn't seem to be working now
Route::set('user_profile','(<controller>(/<id>))')
->defaults(array(
'directory' => 'public',
'controller' => 'users', // Note I changed it to plural to match 'users/*' from your url
'action' => 'index',
));
Route::set('default', '(<controller>(/<action>(/<id>)))')
->defaults(array(
'directory' => 'public',
'controller' => 'home',
'action' => 'index',
));

Answer 1

It's as simple as omitting the <action> param from the URL, but still keeping the default value:
Route::set('user_profile','(<controller>(/<id>))')
->defaults(array(
'directory' => 'public',
'controller' => 'users', // Note I changed it to plural to match 'users/*' from your url
'action' => 'index',
));
Note, that unless you have other Route that overrides this behaviour, your user controller will only be able to execute the index action.
Edit
If your users_profile route is only handling /users path then you can set it in the route explicitly:
Route::set('user_profile','users(/<id>)')
->defaults(array(
'directory' => 'public',
'controller' => 'users', // Note I changed it to plural to match 'users/*' from your url
'action' => 'index',
));
This should address the conflicting routes.