Form without value atribute in the submit input - php

I have this form:
<form action="http://xxx" method="post">
<img src="" id="imagenOriginal">
<label>Nombre</label>
<input type="text" name="nombre" />
<label>Apellido</label>
<input type="text" name="apellido" />
<input id="a" type="submit" value" "name="btnRegistro">
</form>
And if I dont set a value to the submit input the form dont submit , but if I put value="SEND" or any thing its make the submit ? Why occurs that?

Should be
<input id="a" type="submit" value="" name="btnRegistro">

Related

why my forms are not working in bootstrap website?

I tried all but no form is working with method or simple action like http://google.com `
<form action="http://google.com" method="post">
<input type="text" />
<input type="submit" />
</form>
even this is not working
use this
<form role="form" action="http://google.com" method="post">
<input type="text" name="text" />
<input type="submit" name="submit" />
</form>
role attribute for FORM
name attribute for input
In PHP, $_POST always accept name attribute from form elements:-
You need to write
<input type="text" name='name_of_your_field' />
instead of
<input type="text" />
You need to refer this Link.

form action, send data from the current form in the URL

for the life of me cant remember how i should be doing this / if its possible.
I am creating a form that takes the user to another page but want to pass the value of the text box in the url.
so e.g:
<form action="newadvert.php?vrm=" class="newadvertform" method="post">
<input type="text" name="carvrm" class="carvrm"/>
<input type="submit" class="newadvertsubmit" value="Create Advert" />
</form>
How can i send the user to newadvert.php?vrm= THE ENTERED TEXT HERE
I need this to then get value on the next page.
Use GET method
<form action="newadvert.php" class="newadvertform" method="GET">
And rename carvrm to vrm
<input type="text" name="vrm" class="carvrm"/>
Use the GET method and rename carvrm to vrm.
<form action="newadvert.php" class="newadvertform" method="GET">
<input type="text" name="vrm" class="carvrm"/>
<input type="submit" class="newadvertsubmit" value="Create Advert" />
</form>
When submitting the form, it'll go as http:///newadvert.php?vrm=
<form action="newadvert.php" class="newadvertform" method="get">
<input type="text" name="vrm" class="carvrm"/>
<input type="submit" class="newadvertsubmit" value="Create Advert" />
</form>
change your form method from post to get
Like this:
<form action="newadvert.php" class="newadvertform" method="get">
<input type="text" name="carvrm" class="carvrm"/>
<input type="submit" class="newadvertsubmit" value="Create Advert" />
</form>
you can get input value by :
$_REQUEST['carvrm']
or change input name to vrm :
<form action="newadvert.php" class="newadvertform" method="get">
<input type="text" name="vrm" class="carvrm"/>
<input type="submit" class="newadvertsubmit" value="Create Advert" />
</form>
now you can get input value by :
$_REQUEST['vrm']
doc: http://www.w3schools.com/PHP/php_forms.asp

PHP Form URL vars

I was wondering if it would be possible to have a variable in the URL created when submitting a form?
form:
<form class="register_form" action="action.php" method="get">
Team Name*: <input type="text" name="teamname" required />
Team Region*: <input type="text" name="teamregion" maxlength="4" required />
Team Leader*: <input type="text" name="teamleader" maxlength="16" required />
Team Members: <input type="text" name="teammembers" />
<input name="register_submit" type="submit" value="Register" />
</form>
I'd like the link to end up as: http://.../action.php?do=register
My reasoning for this is so that I can use action.php for more than one thing using if statements. Thanks ^^
Just append the variable you want to the action link.
<form class="register_form" action="action.php?do=register" method="get">
Team Name*: <input type="text" name="teamname" required />
Team Region*: <input type="text" name="teamregion" maxlength="4" required />
Team Leader*: <input type="text" name="teamleader" maxlength="16" required />
Team Members: <input type="text" name="teammembers" />
<input name="register_submit" type="submit" value="Register" />
</form>
Or you can add a hidden field to your form:
<input type="hidden" name="do" value="register" />
Sure, the form action URL can have a query string:
<form class="register_form" action="action.php?do=register" method="POST">
The form data will be sent via POST but do will still be available via GET.
You need to add this to the form
<input type="hidden" name="do" value="register">
Yes, it is possible. You can use any one of following methods
1) You can set the name of your submit button "do"; As the value of your submit button is "Register"
<input type="submit" name="do" value="Register" />
OR
2) You can add a hidden field to your form
<input type="hidden" name="do" value="register" />

How to process multiple forms using one php script

I have multiple forms and I have one php script that I want to use to process these forms but when I click on submit for any of the forms...the script is processed by the number of forms with the submit button named 'submitForm' in this case, the alert will show 3 times instead of once! What am I not doing right?
NB. I hope this makes much sense?
html code
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
php script
<?php
if (isset($_POST['submitForm'])) {
echo('<script>alert("Form Submitted")</script>');
}
?>
when I click on submit for any particular form, it submits all the forms.
this is not true.
Once your forms have proper formatting, your browser will submit only current one.
(and PHP has nothing to do here)
however, whole page will be reloaded, if you mean that. That is okay - when you submit a form, a page is intended to reload. If you need another behavior, you have to explain your wishes.
Also note that none of your text fields being sent to the server as they have no names.
I guess the question I should be asking is, how do I pass a particular form to php instead of writing multiple php scripts to handle each form!!!
well, it seems you want to ask how to distinguish these forms.
add a hidden field into each
<input type="hidden" name="step" value="1" />
and then in PHP
if ($_POST['step'] == 1) {
//first form
}
if ($_POST['step'] == 2) {
//second
}
This submits one form of many to php. Copy, paste, test, and study.
<?php
if (isset($_POST['submitForm'])) {
print_r($_POST);
}
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
Using a,b,c,d for the first form, e,f,g,h for the second form and i,j,k,l for the third form and submitting the second form yields the following output:
Array
(
[A] => e
[B] => f
[C] => g
[D] => h
[submitForm] => Submit Form
)
#Jay
Actually its not hard.
Once you supply form names, your work is done. the DOM does the rest.
write one php block to do your functions (create/update/retrieve/delete)
Whichever button is clicked, by default it submits only the elements enclosed together with it.
if(!empty($_POST)){
if(isset($_POST['submit'])){
print "<pre>";
var_dump($_POST); // write your code here as you would
print "<pre>";
}
}
try this with your form above.
I know this is an old post but here's how I solve this very problem.
All you need to do is make sure the submit buttons in each form have different names. Eg:
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm1" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm2" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm3" />
</form>
Then, you simply check which form's submit button was pressed.
<?php
if (isset($_POST['submitForm1'])) {
echo('<script>alert("Form 1 Submitted")</script>');
} elseif (isset($_POST['submitForm2'])) {
echo('<script>alert("Form 2 Submitted")</script>');
} elseif (isset($_POST['submitForm3'])) {
echo('<script>alert("Form 3 Submitted")</script>');
}
?>
If you need dynamic forms, you may try below code. While statement can be changed to fetch data from DB and use foreach instead. Hope you know this.
Here, I used while($n<10) for 10 dynamic forms.
You can also use tag as below if you need separate form names.
<form action="" name="form<?=$n?>" method="post">
This will create separate form names such as form1, form2, etc but not necessary here.
<?php
if (isset($_POST['submitForm'])) {
echo '<pre>';
print_r($_POST);
echo '</pre>';
}
$n=0;
while($n<10) {
$n++;
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<?php
}
?>
Sample page with output when I click row 5..

Form data not passing to PHP

I have what should be a simple form to pass data to a php page. The form is:
<form action="php/setlist.php" method="post">
<input type="text" id="SetListName" />
<input type="hidden" id="newList" name="newList" value="" readonly="readonly" style="border: none;">
<input type="submit" style="width:150px;"><br /><br />
and the php is:
$SetListSave = $_REQUEST['newList'];
$SetListName= $_REQUEST['SetListName'];
echo $SetListName;
echo $SetListSave;
I am getting the newList from the form just fine but the SetListName isn't getting passed. I am a novice with php so I could be missing something basic here, but I am stumped.
You are missing name attribute in:
<input type="text" id="SetListName" />
Replace
<input type="text" id="SetListName" />
with
<input type="text" id="SetListName" name ="SetListName"/>
You need to have a 'name' attribute in the form for each input field that you want to read in PHP. So you're code should read:
<form action="php/setlist.php" method="post">
<input type="text" id="SetListName" name="SetListName"/>
<input type="hidden" id="newList" name="newList" value="" readonly="readonly" style="border: none;">
<input type="submit" style="width:150px;"><br /><br />
use
<input type="text" id="SetListName" name="SetListName" />
you have not used name attribute

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