Search for form element in database multiple times - php

Question

I am trying to learn php and came across a task which i have need help with.
Background information - I have a postgresql database which has
multiple tables.
What I need - When I enter anything in the form on my HTML page, i
need to extract all information from all the tables that contain
information related to what I have entered.
Example - Suppose I enter food poisoning in the form. I need to access
all the tables and extract the different information related to food
poisoning.
My code: (the connection part is not being posted as it works fine)
<?php
$result = pg_prepare($dbh, "Query1", 'SELECT * FROM Project.bacteria WHERE disease = $1');
// if (pg_numrows($result) == 0) {
// $result = pg_prepare($dbh, "Query1", 'SELECT * FROM Project.virus WHERE disease = $1');
// }
//$sql = "SELECT * FROM Project.bacteria WHERE disease=";
//$result = pg_query($dbh, $sql);
$result = pg_execute($dbh, "Query1", array($disease));
if (!$result) {
die("Error in SQL query: " . pg_last_error());
}
//$rows = pg_fetch_all($result)
/*// iterate over result set
// print each row*/
while ($row = pg_fetch_array($result)) {
echo $row[0]." ".$row[1]. "<br />";
}
?>
For the above code, when I enter food poisoning it searches just one table i.e bacteria and returns the related information ( here as a test i have taken just information at row position 1 and row position 2.)
Since there are multiple tables, like a table drugs that stores information of drugs used to cure food poisoning, i would want to extract that information from the respective table.
Any help would be appreciated.

Answer 1

try this one
SELECT * FROM bacteria WHERE disease = ''
UNION ALL
SELECT * FROM drugs where desease = ''
but i think the best way is to normalize you tables. :)