I am aware that there are multiple posts about this, but I was not able to make it work for my code.
As the title suggests I want to join two tables from two different DBs together.
Here is my code:
$dbh1 = mysql_connect("$host", "$username", "$password")or die("cannot connect");
$dbh2 = mysql_connect("$host2", "$username2", "$password2", true)or die("cannot connect");
mysql_select_db("$db_name", $dbh1)or die("cannot select DB");
mysql_select_db("$db_name2", $dbh2)or die("cannot select DB");
//first table
//$sql = mysql_query("SELECT InterestedEntityId, Score FROM users.`user_interests` WHERE UserId= //$userID ORDER BY Score DESC", $dbh1);
//second table
//$sql = mysql_query("SELECT entities.`Name` FROM tags.`entities` WHERE Id = InterestedEntityId", $dbh2);
I want to get the 3 fields mentioned in select statements in one go (I.E. InterestedEntityId, Score, entities.Name)
Any idea on how to join these two tables in one sql query. I tried using inner joins and adding the tablename (as this thread suggested), but the query did not return anything.
Any ideas please?
Something like this should work.
SELECT t1.InterestedEntityId, t1.Score, t2.Name
FROM DB1.users.`user_interests` t1
JOIN DB2.tags.`entities` t2 ON t2.UserId = t1.Id
Note: Use PDO as mysql_* is deprecated and not secure enough.
Pretty much the model is:
SELECT dbName1.TableName1.ColumnName1, dbName2.TableName2.ColumnName2 FROM dbName1.TableName1 JOIN dbName2.TableName2 ON dbName1.TableName1.ColumnName1 = dbName2.TableName2.ColumnName2
Please, don't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.
While it is theoretically possible to join tables from two different databases on the same server, what you are trying to do cannot possibly work because you appear to be accessing two different servers.
In order to get the result set you want you will need to combine them manually.
For example (using PDO):
$dsn1 = "mysql:host=$host;dbname=$db_name";
$dsn2 = "mysql:host=$host2;dbname=$db_name2";
try {
// Create the connections
$db1 = new PDO($dsn1, $username, $password);
$db1->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db1->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$db1->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
$db2 = new PDO($dsn2, $username2, $password2);
$db2->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db2->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$db2->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
// Get the initial recordset
$sql1 = "
SELECT InterestedEntityId, Score
FROM `user_interests`
WHERE UserId = :userId
ORDER BY Score DESC
";
$stmt1 = $db1->prepare($sql1);
$stmt1->bindParam('userId', $userID, PDO::PARAM_INT);
$stmt1->execute();
// Prepare the statement for the second database
$sql2 = "
SELECT Name
FROM entities
WHERE Id = :entityId
";
$entityId = 0;
$stmt2 = $db2->prepare($sql2);
$stmt2->bindParam('id', $entityId, PDO::PARAM_INT);
// Loop the first result set
$result = array();
foreach ($stmt1 as $row1) {
// Fetch the related data from the second DB
$entityId = $row1['InterestedEntityId'];
$stmt2->execute();
$row2 = $stmt2->fetch();
// Construct the final result row and store it
$result[] = array(
'InterestedEntityId' => $row1['InterestedEntityId'],
'Score' => $row1['Score'],
'Name' => $row2['Name']
);
}
} catch(PDOException $e) {
die($e->getMessage());
}
// The result set you want should now be available
var_dump($result);
Related
I am trying to update for some products their category in database. I want to find products that have in their name a specific word and after that I want to update the category for this products.
I want to select IDs from sho_posts where sho_posts.post_title contain this part of word '%Audio CD%' and after that to update the sho_term_relationships.term_taxonomy_id with value 2 where sho_term_relationships.object_id=sho_posts.id.
I wrote a little PHP code but it make only selection part. What is wrong?
<?php
$username = "user_name";
$password = "password";
$hostname = "host";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
$selected = mysql_select_db("1812233_shoping",$dbhandle)
or die("Could not select examples");
echo "Connected to MySQL<br>";
$result = mysql_query ("SELECT `id` FROM `sho_posts` WHERE CONVERT(`post_title` USING utf8) LIKE '%Audio CD%' ");
while ($row = mysql_fetch_array($result)) {
echo "ID:".$row{'id'}."<br>";
}
$sql = "UPDATE 'sho_term_relationships'
SET 'term_taxonomy_id' = '123'
WHERE 'object_id' = $row";
//close the connection
mysql_close($dbhandle);
My new cod for script now is:
$username = "_shoping";
$password = "password";
$hostname = "localhost";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
$selected = mysql_select_db("_shoping",$dbhandle)
or die("Could not select examples");
echo "Connected to MySQL<br>";
$result = mysql_query ("SELECT `id` FROM `sho_posts` WHERE CONVERT(`post_title` USING utf8) LIKE '%Audio CD%' ");
while ($row = mysql_fetch_array($result)) {
$id[] = $row['id'];
/*echo "ID2:".$id."<br>";*/
}
foreach ($id as $value) {
echo "value:".$value."<br>";
}
/*$id = $row['id'];*/
$sql = "UPDATE sho_term_relationships
SET term_taxonomy_id = '123'
WHERE object_id =".$value;
mysql_query($sql);
//close the connection
mysql_close($dbhandle);
now it make an update but only for one row, how to make for all rows? From select query I get 4 result
Try this:
$sql = "UPDATE sho_term_relationships
SET term_taxonomy_id = '123'
WHERE object_id = ".$row{'id'};
And make sure to run the query mysql_query($sql)
Also, I think you might want to add this query inside the while loop
You are using single quotes instead of backticks (which are in this case not necessary). Change your update query to this:
$sql = "UPDATE sho_term_relationships
SET term_taxonomy_id = 123
WHERE object_id = $row";
Also, you are missing some pieces of your code; nothing will be called on that query. It's not being executed at all.
Also you have some other problems here, mainly due to the high risk of sql injection. First of all stop using mysql_ functions, they are deprecated. You should prepare your variables. Here's a demonstration of the key parts of your script in mysqli_ format.
This should also solve most of your issues (there may be a few more if I don't full understand your original question).
You would call your database like this (and check for errors)
$dbhandle = new mysqli($hostname, $username, $password);
if ($dhandle->connect_error) {
die("Connection failed: " . $dbhandle->connect_error);
}
Then you would select your data like this (assuming that term might not be the same every time, and might be coming from a post variable named search).
Edit: For example, if you have an HTML form that is getting this variable like so:
<input type="select" name="search_term" />
you name the variable like this:
$search = $_POST['search_term'];
and then you set it up for your query for the like operator
$search_term = '%'.$search.'%';
$result = $dbhandle->prepare("SELECT `id`
FROM `sho_posts`
WHERE CONVERT(`post_title` USING utf8)
LIKE ? ");
$result->bind_param("s",$search_term);
$result->execute();
$result->bind_result($id);
And then you can get your data through the while loop like so
while ($result->fetch()) {
... stuff you want to do here...
}
$result->close();
Then you would use this in your update query (which would take a similar syntax), and you can just get the information from $id which was created with the bind_result above:
$sql = $dbhandle->("UPDATE sho_term_relationships
SET term_taxonomy_id = 123
WHERE object_id = ?");
$sql->bind_param("s",$id);
$sql->execute();
$sql->close();
It may take a little bit to get used to this, but I find it easier to parse, and also is much more secure
I have information spread out across a few databases and want to put all the information onto one webpage using PHP. I was wondering how I can connect to multiple databases on a single PHP webpage.
I know how to connect to a single database using:
$dbh = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
However, can I just use multiple "mysql_connect" commands to open the other databases, and how would PHP know what database I want the information pulled from if I do have multiple databases connected.
Warning : mysql_xx functions are deprecated since php 5.5 and removed since php 7.0 (see http://php.net/manual/intro.mysql.php), use mysqli_xx functions or see the answer below from #Troelskn
You can make multiple calls to mysql_connect(), but if the parameters are the same you need to pass true for the '$new_link' (fourth) parameter, otherwise the same connection is reused. For example:
$dbh1 = mysql_connect($hostname, $username, $password);
$dbh2 = mysql_connect($hostname, $username, $password, true);
mysql_select_db('database1', $dbh1);
mysql_select_db('database2', $dbh2);
Then to query database 1 pass the first link identifier:
mysql_query('select * from tablename', $dbh1);
and for database 2 pass the second:
mysql_query('select * from tablename', $dbh2);
If you do not pass a link identifier then the last connection created is used (in this case the one represented by $dbh2) e.g.:
mysql_query('select * from tablename');
Other options
If the MySQL user has access to both databases and they are on the same host (i.e. both DBs are accessible from the same connection) you could:
Keep one connection open and call mysql_select_db() to swap between as necessary. I am not sure this is a clean solution and you could end up querying the wrong database.
Specify the database name when you reference tables within your queries (e.g. SELECT * FROM database2.tablename). This is likely to be a pain to implement.
Also please read troelskn's answer because that is a better approach if you are able to use PDO rather than the older extensions.
If you use PHP5 (And you should, given that PHP4 has been deprecated), you should use PDO, since this is slowly becoming the new standard. One (very) important benefit of PDO, is that it supports bound parameters, which makes for much more secure code.
You would connect through PDO, like this:
try {
$db = new PDO('mysql:dbname=databasename;host=127.0.0.1', 'username', 'password');
} catch (PDOException $ex) {
echo 'Connection failed: ' . $ex->getMessage();
}
(Of course replace databasename, username and password above)
You can then query the database like this:
$result = $db->query("select * from tablename");
foreach ($result as $row) {
echo $row['foo'] . "\n";
}
Or, if you have variables:
$stmt = $db->prepare("select * from tablename where id = :id");
$stmt->execute(array(':id' => 42));
$row = $stmt->fetch();
If you need multiple connections open at once, you can simply create multiple instances of PDO:
try {
$db1 = new PDO('mysql:dbname=databas1;host=127.0.0.1', 'username', 'password');
$db2 = new PDO('mysql:dbname=databas2;host=127.0.0.1', 'username', 'password');
} catch (PDOException $ex) {
echo 'Connection failed: ' . $ex->getMessage();
}
I just made my life simple:
CREATE VIEW another_table AS SELECT * FROM another_database.another_table;
hope it is helpful... cheers...
Instead of mysql_connect use mysqli_connect.
mysqli is provide a functionality for connect multiple database at a time.
$Db1 = new mysqli($hostname,$username,$password,$db_name1);
// this is connection 1 for DB 1
$Db2 = new mysqli($hostname,$username,$password,$db_name2);
// this is connection 2 for DB 2
Try below code:
$conn = mysql_connect("hostname","username","password");
mysql_select_db("db1",$conn);
mysql_select_db("db2",$conn);
$query1 = "SELECT * FROM db1.table";
$query2 = "SELECT * FROM db2.table";
You can fetch data of above query from both database as below
$rs = mysql_query($query1);
while($row = mysql_fetch_assoc($rs)) {
$data1[] = $row;
}
$rs = mysql_query($query2);
while($row = mysql_fetch_assoc($rs)) {
$data2[] = $row;
}
print_r($data1);
print_r($data2);
$dbh1 = mysql_connect($hostname, $username, $password);
$dbh2 = mysql_connect($hostname, $username, $password, true);
mysql_select_db('database1', $dbh1);
mysql_select_db('database2',$dbh2);
mysql_query('select * from tablename', $dbh1);
mysql_query('select * from tablename', $dbh2);
This is the most obvious solution that I use but just remember, if the username / password for both the database is exactly same in the same host, this solution will always be using the first connection. So don't be confused that this is not working in such case. What you need to do is, create 2 different users for the 2 databases and it will work.
Unless you really need to have more than one instance of a PDO object in play, consider the following:
$con = new PDO('mysql:host=localhost', $username, $password,
array(PDO::ATTR_PERSISTENT => true));
Notice the absence of dbname= in the construction arguments.
When you connect to MySQL via a terminal or other tool, the database name is not needed off the bat. You can switch between databases by using the USE dbname statement via the PDO::exec() method.
$con->exec("USE someDatabase");
$con->exec("USE anotherDatabase");
Of course you may want to wrap this in a catch try statement.
You might be able to use MySQLi syntax, which would allow you to handle it better.
Define the database connections, then whenever you want to query one of the database, specify the right connection.
E.g.:
$Db1 = new mysqli('$DB_HOST','USERNAME','PASSWORD'); // 1st database connection
$Db2 = new mysqli('$DB_HOST','USERNAME','PASSWORD'); // 2nd database connection
Then to query them on the same page, use something like:
$query = $Db1->query("select * from tablename")
$query2 = $Db2->query("select * from tablename")
die("$Db1->error");
Changing to MySQLi in this way will help you.
You don't actually need select_db. You can send a query to two databases at the same time. First, give a grant to DB1 to select from DB2 by GRANT select ON DB2.* TO DB1#localhost;. Then, FLUSH PRIVILEGES;. Finally, you are able to do 'multiple-database query' like SELECT DB1.TABLE1.id, DB2.TABLE1.username FROM DB1,DB2 etc. (Don't forget that you need 'root' access to use grant command)
if you are using mysqli and have two db_connection file. like
first one is
define('HOST','localhost');
define('USER','user');
define('PASS','passs');
define('**DB1**','database_name1');
$connMitra = new mysqli(HOST, USER, PASS, **DB1**);
second one is
define('HOST','localhost');
define('USER','user');
define('PASS','passs');
define(**'DB2**','database_name1');
$connMitra = new mysqli(HOST, USER, PASS, **DB2**);
SO just change the name of parameter pass in mysqli like DB1 and DB2.
if you pass same parameter in mysqli suppose DB1 in both file then second database will no connect any more. So remember when you use two or more connection pass different parameter name in mysqli function
<?php
// Sapan Mohanty
// Skype:sapan.mohannty
//***********************************
$oldData = mysql_connect('localhost', 'DBUSER', 'DBPASS');
echo mysql_error();
$NewData = mysql_connect('localhost', 'DBUSER', 'DBPASS');
echo mysql_error();
mysql_select_db('OLDDBNAME', $oldData );
mysql_select_db('NEWDBNAME', $NewData );
$getAllTablesName = "SELECT table_name FROM information_schema.tables WHERE table_type = 'base table'";
$getAllTablesNameExe = mysql_query($getAllTablesName);
//echo mysql_error();
while ($dataTableName = mysql_fetch_object($getAllTablesNameExe)) {
$oldDataCount = mysql_query('select count(*) as noOfRecord from ' . $dataTableName->table_name, $oldData);
$oldDataCountResult = mysql_fetch_object($oldDataCount);
$newDataCount = mysql_query('select count(*) as noOfRecord from ' . $dataTableName->table_name, $NewData);
$newDataCountResult = mysql_fetch_object($newDataCount);
if ( $oldDataCountResult->noOfRecord != $newDataCountResult->noOfRecord ) {
echo "<br/><b>" . $dataTableName->table_name . "</b>";
echo " | Old: " . $oldDataCountResult->noOfRecord;
echo " | New: " . $newDataCountResult->noOfRecord;
if ($oldDataCountResult->noOfRecord < $newDataCountResult->noOfRecord) {
echo " | <font color='green'>*</font>";
} else {
echo " | <font color='red'>*</font>";
}
echo "<br/>----------------------------------------";
}
}
?>
I have two databases, one online (mysql) and one in my office (SQL Server) which I would like to compare and update where a value is different.
I am using php to connect to the SQL Server database and run a query to retrieve the information, then connecting to the Mysql database running a query. Then I need to compare the two queries and update where necessary.
Is there somewhere I can look for tips on how to do this, I am sketchy on PHP and struggling really.
This is as far as I have got-:
<?php
$Server = "**server**";
$User = "**user**";
$Pass = "**password**";
$DB = "**DB**";
//connection to the database
$dbhandle = mssql_connect($Server, $User, $Pass)
or die("Couldn't connect to SQL Server on $Server");
//select a database to work with
$selected = mssql_select_db($DB, $dbhandle)
or die("Couldn't open database $DB");
//declare the SQL statement that will query the database
$query = "SELECT p.id, p.code, ps.onhand";
$query .= "FROM products p with(nolock)";
$query .= "INNER JOIN productstockonhanditems ps with(nolock)";
$query .= "ON ps.ProductID = p.ID";
$query .= "WHERE ps.StockLocationID = 1";
//execute the SQL query and return records
$get_offlineproduct2 = mssql_query($query);
mysql_connect("**Host**", "**username**", "**password**") or die(mysql_error());
mysql_select_db("Database_Name") or die(mysql_error());
$get_onlineproducts = mysql_query(SELECT w.ob_sku, w.quantity
FROM product_option_value AS w
ORDER BY ob_sku)
or die(mysql_error());
//close the connection
mssql_close($dbhandle);
?>
I am looking to compare the value p.code to w.ob_sku and whenever they match copy the value of ps.onhand to w.quantity so the online database has the correct quantities from the office database.
My question I guess is how close am I to getting this right? Also am I doing this the right way, I don't want to get so far and realise that i am just wasting my time...
Thanks!
You do not need to fetch any record from MySQL, since you actually want to update it.
I would do something like this:
$query = 'SELECT p.code, ps.onhand FROM (...)';
// execute the SQL query and return a result set
// mssql_query() actually returns a resource
// that you must iterate with (e.g.) mssql_fetch_array()
$mssqlResult = mssql_query($query);
// connect to the MySQL database
mysql_connect("**Host**", "**username**", "**password**") or die(mysql_error());
mysql_select_db("Database_Name") or die(mysql_error());
while ( $mssqlRow = mssql_fetch_array($mssqlResult) ) {
$mssqlCode = $mssqlRow['code'];
$mssqlOnHand = $mssqlRow['onhand'];
mysql_query(
"UPDATE product_option_value SET quantity = $mssqlOnHand WHERE ob_sku = $mssqlCode"
// extra quotes may be required around $mssqlCode depending on the column type
);
}
I would like to ask for help with converting my mysql_* query to prepared statement using PDO technology. There are many of them which I cannot find on the internet how to solve them properly - mostly advanced ones like this one for example:
mysql_query("SELECT * FROM pet_auction JOIN people ON (pet_auction.pet=people.guid)
LEFT OUTER JOIN login.account ON (pet_auction.winner=login.account.id)
WHERE active=1 AND seller=$userid ORDER BY id DESC");
How to succesfully convert it to PDO STMT using these?:
$people = new PDO("mysql:host=localhost;dbname=people", "myuser", "mypass");
$login = new PDO("mysql:host=localhost;dbname=login", "myuser", "mypass");
Thank you all I rather will not try else it would be false because i tested already ... I have no idea how to convert LEFT OUTER JOIN and multiple databases together.
You do not need to open a pdo object for each database. Just give myuser grant access to both login and people databases. Then query like so:
$dbh = new PDO("mysql:host=localhost;dbname=people", "myuser", "mypass");
$stmt= $dbh->prepare("SELECT * FROM pet_auction JOIN people ON (pet_auction.pet=people.guid)
LEFT OUTER JOIN login.account ON (pet_auction.winner=login.account.id)
WHERE active=1 AND seller=:userid ORDER BY id DESC");
$stmt-> execute(array(':userid' => $userid));
$variable = $stmt->fetch(PDO::FETCH_ASSOC);
$dbh = new PDO($dsn, "myuser", "mypass");
$select = $dbh->prepare("SELECT * FROM `table`");
$select -> execute();
$variable = $select->fetch(PDO::FETCH_ASSOC);
where $dsn is a string containing 'mysql:dbname=racerost_reekris_db;host=localhost'
the query can contain any mySQL query including joins.
I have information spread out across a few databases and want to put all the information onto one webpage using PHP. I was wondering how I can connect to multiple databases on a single PHP webpage.
I know how to connect to a single database using:
$dbh = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
However, can I just use multiple "mysql_connect" commands to open the other databases, and how would PHP know what database I want the information pulled from if I do have multiple databases connected.
Warning : mysql_xx functions are deprecated since php 5.5 and removed since php 7.0 (see http://php.net/manual/intro.mysql.php), use mysqli_xx functions or see the answer below from #Troelskn
You can make multiple calls to mysql_connect(), but if the parameters are the same you need to pass true for the '$new_link' (fourth) parameter, otherwise the same connection is reused. For example:
$dbh1 = mysql_connect($hostname, $username, $password);
$dbh2 = mysql_connect($hostname, $username, $password, true);
mysql_select_db('database1', $dbh1);
mysql_select_db('database2', $dbh2);
Then to query database 1 pass the first link identifier:
mysql_query('select * from tablename', $dbh1);
and for database 2 pass the second:
mysql_query('select * from tablename', $dbh2);
If you do not pass a link identifier then the last connection created is used (in this case the one represented by $dbh2) e.g.:
mysql_query('select * from tablename');
Other options
If the MySQL user has access to both databases and they are on the same host (i.e. both DBs are accessible from the same connection) you could:
Keep one connection open and call mysql_select_db() to swap between as necessary. I am not sure this is a clean solution and you could end up querying the wrong database.
Specify the database name when you reference tables within your queries (e.g. SELECT * FROM database2.tablename). This is likely to be a pain to implement.
Also please read troelskn's answer because that is a better approach if you are able to use PDO rather than the older extensions.
If you use PHP5 (And you should, given that PHP4 has been deprecated), you should use PDO, since this is slowly becoming the new standard. One (very) important benefit of PDO, is that it supports bound parameters, which makes for much more secure code.
You would connect through PDO, like this:
try {
$db = new PDO('mysql:dbname=databasename;host=127.0.0.1', 'username', 'password');
} catch (PDOException $ex) {
echo 'Connection failed: ' . $ex->getMessage();
}
(Of course replace databasename, username and password above)
You can then query the database like this:
$result = $db->query("select * from tablename");
foreach ($result as $row) {
echo $row['foo'] . "\n";
}
Or, if you have variables:
$stmt = $db->prepare("select * from tablename where id = :id");
$stmt->execute(array(':id' => 42));
$row = $stmt->fetch();
If you need multiple connections open at once, you can simply create multiple instances of PDO:
try {
$db1 = new PDO('mysql:dbname=databas1;host=127.0.0.1', 'username', 'password');
$db2 = new PDO('mysql:dbname=databas2;host=127.0.0.1', 'username', 'password');
} catch (PDOException $ex) {
echo 'Connection failed: ' . $ex->getMessage();
}
I just made my life simple:
CREATE VIEW another_table AS SELECT * FROM another_database.another_table;
hope it is helpful... cheers...
Instead of mysql_connect use mysqli_connect.
mysqli is provide a functionality for connect multiple database at a time.
$Db1 = new mysqli($hostname,$username,$password,$db_name1);
// this is connection 1 for DB 1
$Db2 = new mysqli($hostname,$username,$password,$db_name2);
// this is connection 2 for DB 2
Try below code:
$conn = mysql_connect("hostname","username","password");
mysql_select_db("db1",$conn);
mysql_select_db("db2",$conn);
$query1 = "SELECT * FROM db1.table";
$query2 = "SELECT * FROM db2.table";
You can fetch data of above query from both database as below
$rs = mysql_query($query1);
while($row = mysql_fetch_assoc($rs)) {
$data1[] = $row;
}
$rs = mysql_query($query2);
while($row = mysql_fetch_assoc($rs)) {
$data2[] = $row;
}
print_r($data1);
print_r($data2);
$dbh1 = mysql_connect($hostname, $username, $password);
$dbh2 = mysql_connect($hostname, $username, $password, true);
mysql_select_db('database1', $dbh1);
mysql_select_db('database2',$dbh2);
mysql_query('select * from tablename', $dbh1);
mysql_query('select * from tablename', $dbh2);
This is the most obvious solution that I use but just remember, if the username / password for both the database is exactly same in the same host, this solution will always be using the first connection. So don't be confused that this is not working in such case. What you need to do is, create 2 different users for the 2 databases and it will work.
Unless you really need to have more than one instance of a PDO object in play, consider the following:
$con = new PDO('mysql:host=localhost', $username, $password,
array(PDO::ATTR_PERSISTENT => true));
Notice the absence of dbname= in the construction arguments.
When you connect to MySQL via a terminal or other tool, the database name is not needed off the bat. You can switch between databases by using the USE dbname statement via the PDO::exec() method.
$con->exec("USE someDatabase");
$con->exec("USE anotherDatabase");
Of course you may want to wrap this in a catch try statement.
You might be able to use MySQLi syntax, which would allow you to handle it better.
Define the database connections, then whenever you want to query one of the database, specify the right connection.
E.g.:
$Db1 = new mysqli('$DB_HOST','USERNAME','PASSWORD'); // 1st database connection
$Db2 = new mysqli('$DB_HOST','USERNAME','PASSWORD'); // 2nd database connection
Then to query them on the same page, use something like:
$query = $Db1->query("select * from tablename")
$query2 = $Db2->query("select * from tablename")
die("$Db1->error");
Changing to MySQLi in this way will help you.
You don't actually need select_db. You can send a query to two databases at the same time. First, give a grant to DB1 to select from DB2 by GRANT select ON DB2.* TO DB1#localhost;. Then, FLUSH PRIVILEGES;. Finally, you are able to do 'multiple-database query' like SELECT DB1.TABLE1.id, DB2.TABLE1.username FROM DB1,DB2 etc. (Don't forget that you need 'root' access to use grant command)
if you are using mysqli and have two db_connection file. like
first one is
define('HOST','localhost');
define('USER','user');
define('PASS','passs');
define('**DB1**','database_name1');
$connMitra = new mysqli(HOST, USER, PASS, **DB1**);
second one is
define('HOST','localhost');
define('USER','user');
define('PASS','passs');
define(**'DB2**','database_name1');
$connMitra = new mysqli(HOST, USER, PASS, **DB2**);
SO just change the name of parameter pass in mysqli like DB1 and DB2.
if you pass same parameter in mysqli suppose DB1 in both file then second database will no connect any more. So remember when you use two or more connection pass different parameter name in mysqli function
<?php
// Sapan Mohanty
// Skype:sapan.mohannty
//***********************************
$oldData = mysql_connect('localhost', 'DBUSER', 'DBPASS');
echo mysql_error();
$NewData = mysql_connect('localhost', 'DBUSER', 'DBPASS');
echo mysql_error();
mysql_select_db('OLDDBNAME', $oldData );
mysql_select_db('NEWDBNAME', $NewData );
$getAllTablesName = "SELECT table_name FROM information_schema.tables WHERE table_type = 'base table'";
$getAllTablesNameExe = mysql_query($getAllTablesName);
//echo mysql_error();
while ($dataTableName = mysql_fetch_object($getAllTablesNameExe)) {
$oldDataCount = mysql_query('select count(*) as noOfRecord from ' . $dataTableName->table_name, $oldData);
$oldDataCountResult = mysql_fetch_object($oldDataCount);
$newDataCount = mysql_query('select count(*) as noOfRecord from ' . $dataTableName->table_name, $NewData);
$newDataCountResult = mysql_fetch_object($newDataCount);
if ( $oldDataCountResult->noOfRecord != $newDataCountResult->noOfRecord ) {
echo "<br/><b>" . $dataTableName->table_name . "</b>";
echo " | Old: " . $oldDataCountResult->noOfRecord;
echo " | New: " . $newDataCountResult->noOfRecord;
if ($oldDataCountResult->noOfRecord < $newDataCountResult->noOfRecord) {
echo " | <font color='green'>*</font>";
} else {
echo " | <font color='red'>*</font>";
}
echo "<br/>----------------------------------------";
}
}
?>