jQuery pop-up with php form validation - php

Question

i have a registration page
<form class="register" action="regist.php" method="post" >
<h3>Register</h3>
<div class="column">
<div>
<label>First Name:</label>
<input type="text" name="f_name"/>
<span ></span>
</div>
<div>
<label>Last Name:</label>
<input type="text" name="l_name"/>
<span class="error">This is an error</span>
</div>
<div>
<label>mobile:</label>
<input type="text" name="mobile"/>
<span class="error">This is an error</span>
</div>
</div>
<div class="column">
<div>
<label>Username:</label>
<input type="text"name="user"/>
<span >This is an error</span>
</div>
<div>
<label>Email:</label>
<input type="text" name="email"/>
<span class="error">This is an error</span>
</div>
<div>
<label>Password:</label>
<input type="password" name="pass"/>
<span class="error">This is an error</span>
</div>
</div>
<div class="bottom">
<div class="remember">
</div>
<input type="submit" value="Register" name="submet" />
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<div class="clear"></div>
</div>
</form>
that use jquery bpopup
$(function() {
// Binding a click event
// From jQuery v.1.7.0 use .on() instead of .bind()
$('#my-button').bind('click', function(e) {
// Prevents the default action to be triggered.
e.preventDefault();
// Triggering bPopup when click event is fired
$('#element_to_pop_up').bPopup();
});
}
so when some one click register the form will pop up every thing work fine the problem is that i cant do validation to the form because when i click register after filling the form
the pop up will disappear so i cant make the validation on the same form
i tried
1 to make another pop up that show the error but the data wont pass to the new popup
2 to make the action $_SERVER['self_request']
can some one help me withe this please i have a project for my college i nee to do it in 3 dayes
what i need is a validation for the form in the same page or another popup before send it to the MySQL script

Answer 1

Make an php page ( here called validation.php ) that uses the GET function to get the info...
Then set some ID's on the input fields...
And then make an function like this:
function checkAll(){
var firstName = document.getElementById("f_name").value();
var lastName = document.getElementById("l_name").value();
$.get( "validation.php?f_name=" + firstName + "&l_name=" + lastName, function( response ) {
// console.log( response ); // server response
response = response.trim();
if(response == 1){
alert("Everything is alright");
} else{
alert(response);
return false;
}
});
}
And change your form to this:
<form class="register" action="regist.php" method="post" onSubmit="checkAll();">
Now the key is that in the validation.php ,if everything works fine then you can echo value 1, and when something is not alright, you echo the error code ( or any code, and then with an switch clause you can dynamically add the error to your form).
The return false prevents the form from submitting...