PHP Array only stores last value - php

Question

Well, basically what this code does is grab some links from a source code of a website and send them to an mp3 player.
The big problem is on the get_link function, where i want to store the urls to an array. The section where im having problems is commented.
Sorry for posting all this code but the functions are connected to each others.
function getHost($db,$id){
if(isset($_GET['id'])){
$sql1 = "SELECT host FROM mixtape WHERE id=?";
$stm = $db->prepare($sql1);
$stm->execute(array($id));
$row1 = $stm->fetch(PDO::FETCH_ASSOC);
if($row1['host']=='host1'){
$sql2 = "SELECT link1 FROM faixa WHERE id_mixtape IN(SELECT id FROM mixtape WHERE id=?)";
$stm = $db->prepare($sql2);
$stm->execute(array($id));
$rows_affected = $stm->rowCount();
$array=array();
if (count($rows_affected) > 0) {
for($i=1; $i <= $rows_affected; $i++) {
$row2 = $stm->fetch(PDO::FETCH_ASSOC);
$url=$row2['link1'];
get_Link($db,$url,$i,$rows_affected,$array);
}
}
}
}
}
function get_Link($db,$url,$pos,$rows_affect,$array){
$find = 'url:';
$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";
$data = file_get_contents($url);
$data = explode("\n", $data);
for ($line = 0; $line < count($data); $line++) {
if (strpos($data[$line], $find) !== false) {
$link = preg_replace($reg_exUrl,"", $data[$line]);
$v[]=$link;
}
}
if($pos!=$rows_affect-1){
$url="mylink.com/".$link."|";
}else{
$url="mylink.com/".$link."&amp";
}
$array[$pos]=$url;
var_dump($array); // Here says that are 3 values in the array. True
if($pos==$rows_affect-1){
var_dump($array); // Here is only showing the last value in the array. Why?
player($db,$array);
}
}
function player($db,$array){
if(isset($_GET['id'])){
foreach($array as $i=>$item){
echo $item;
}
}
}

Answer 1

This piece of code:
$c=0;
for ($line = 0; $line < count($data); $line++) {
if (strpos($data[$line], $find) !== false) {
$link = preg_replace($reg_exUrl,"", $data[$line]);
$v[$c]=$link;
}
}
Should be like:
$c=0;
for ($line = 0; $line < count($data); $line++) {
if (strpos($data[$line], $find) !== false) {
$link = preg_replace($reg_exUrl,"", $data[$line]);
$v[$c]=$link;
$c = $c+1; //this is missing or $c++;
}
}
OR:
for ($line = 0; $line < count($data); $line++) {
if (strpos($data[$line], $find) !== false) {
$link = preg_replace($reg_exUrl,"", $data[$line]);
$v[]=$link; //That way works too
}
}

Answer 2

Miguelfsf, you must first learn about variable scope.
Your problem is, you created the $array=array() (the $array show be the $row2).
You declared a new variable, but you didn't used, the $array was just to tell you, declare your array that way
$row2=array().
After that you need to do
$row2[] = $stm->fetch(PDO::FETCH_ASSOC);
Why?
Because the assoc returns a associative array, then it will do
$array => {title => "last title} = $newData => {title => "new title"}
It will replace the value
Using the [] everytime you do this it'll create a new element.
Then
{
0 => { title => "title1"}
1 => { title => "title2"}
2 => { title => "title3"}
3 => { title => "title4"}
}