I have this mySQL statement:
SELECT COUNT(clicks) FROM ads.statz WHERE user_id = '$_SESSION[user_id]'
Works fine it counts all the number of clicks with the given user id. What I am after is being able to group together the numbers for each month as a total. I need this for both Clicks and impressions.
Here is the layout of the DB.
CREATE TABLE `statz` (
`ad_id` int(50) NOT NULL,
`date` datetime NOT NULL,
`clicks` int(50) NOT NULL,
`impressions` int(50) NOT NULL,
`user_id` int(50) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Thanks!
Use MONTH() and YEAR() with GROUP BY
SELECT
COUNT(clicks)
FROM
ads.statz
WHERE
user_id = '$_SESSION[user_id]'
GROUP BY
MONTH(date),
YEAR(date)
Related
I am trying to show the amount of reviews for each restaurant.
I made 2 tables containing my data.
CREATE TABLE `restaurants` (
`id` int(4) NOT NULL AUTO_INCREMENT,
`name` varchar(200) NOT NULL,
`city` varchar(200) NOT NULL,
`country` varchar(200) NOT NULL,
`score` int(1) NOT NULL DEFAULT '0',
`reviews` int(1) NOT NULL DEFAULT '0',
`slug` varchar(200) NOT NULL DEFAULT 'slug-test',
`approved` int(1) NOT NULL DEFAULT '0',
`description` text NOT NULL,
`review` int(11) DEFAULT '0',
`created_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`updated_date` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
`img_url` varchar(255) NOT NULL,
`category` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=65 DEFAULT CHARSET=latin1
CREATE TABLE `reviews` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`restaurant_id` int(11) NOT NULL,
`review_text` text NOT NULL,
`score` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `restaurant_id` (`restaurant_id`),
CONSTRAINT `reviews_ibfk_1` FOREIGN KEY (`restaurant_id`) REFERENCES `restaurants` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1
I am already showing my restaurants in a list.
$query = "SELECT * FROM restaurants WHERE approved = 1 ORDER BY created_date DESC";
$result = $mysqli->query($query);
while($row = $result->fetch_array()) {
**HTML WITH MY VARIABLES**
}
This is how u currently show my reviews (hardcoded result in my restaurants table.
if ($reviews <= "0") {
echo "<a href='#' title='Write reviews'><p class='purple-def-color fz-12 mb-0'>write a review</p></a>";
} else if ($reviews > "1") {
echo "<p class='purple-def-color mb-0'>". $row['reviews'] ." reviews</p>";
} else {
echo "<p class='purple-def-color mb-0'>" . $row['reviews'] . " review</p>";
}
I tried to use a JOIN query but was not successful to show the amount of reviews in any way.
Based on your table structure, you can get a review count for each restaurant by joining the reviews table, selecting the COUNT of reviews, and grouping by restaurant ID.
Grouping by restaurant allows you to get an aggregate (e.g. count) of the joined review records for each restaurant.
SELECT
rs.*,
COUNT(rv.`id`) as `reviewCount`
FROM `restaurants` rs
LEFT JOIN `reviews` rv
ON (rv.`restaurant_id` = rs.`id`)
WHERE rs.`approved` = 1
GROUP BY rs.`id`
ORDER BY rs.`created_date` DESC;
Then, when you fetch the rows in PHP, you can reference each row's review count:
echo $row['reviewCount'];
To further demonstrate aggregate functions, here's an example of how to select the average, minimum, and maximum review score for each restaurant:
SELECT
rs.*,
COUNT(rv.`id`) as `reviewCount`,
AVG(rv.`score`) as `reviewAverageScore`,
MIN(rv.`score`) as `reviewMinScore`,
MAX(rv.`score`) as `reviewMaxScore`
FROM `restaurants` rs
LEFT JOIN `reviews` rv
ON (rv.`restaurant_id` = rs.`id`)
WHERE rs.`approved` = 1
GROUP BY rs.`id`
ORDER BY rs.`created_date` DESC;
Try a left join:
$query = 'SELECT * FROM restaurants LEFT JOIN reviews on reviews.restaurant_id = restaurants.id'
A left join returns all records from the left table (restaurants), and the matched records from the right table (reviews)
I'm trying to create a ranking table based on how many likes/upvotes a user had on all his items in total. User in the upvotes table links to id of the user that made the like, but I think you don't need this.
Hopefully by giving these tables everything will get clear.
I think the trick here is to get all the upvotes by each item and merge them together towards a user this item was from to get a total likes for each user and then rank all the users based on this total. Of course doing this will probably be a slow query so I need a very performant way to handle this.
The hard thing is here mainly that the upvotes table doesn't include the user id.
3 tables:
CREATE TABLE `items` (
`id` int(255) NOT NULL AUTO_INCREMENT,
`user_id` int(255) NOT NULL,
`img` varchar(500) NOT NULL,
`message` varchar(200) NOT NULL,
`created_on` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`active` int(11) NOT NULL DEFAULT '1',
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=19 DEFAULT CHARSET=latin1;
CREATE TABLE `upvotes` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user` int(255) NOT NULL,
`item_id` int(255) NOT NULL,
`created_on` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=latin1;
CREATE TABLE `users` (
`id` int(255) NOT NULL AUTO_INCREMENT,
`email` varchar(255) NOT NULL,
`password` binary(60) NOT NULL,
`first_name` varchar(255) NOT NULL,
`last_name` varchar(255) NOT NULL,
`active` int(1) NOT NULL DEFAULT '1',
`created_on` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
UNIQUE KEY `email` (`email`)
) ENGINE=MyISAM AUTO_INCREMENT=17 DEFAULT CHARSET=latin1;
I need a performant query giving me the ranking of each user ranked on how many likes they got on all their items?
I managed to write this:
SELECT #rank := #rank + 1 AS rank, m.*
FROM (SELECT
users.first_name as first_name,
users.last_name as last_name,
count(upvotes.item_id) as total
FROM upvotes
INNER JOIN users
ON users.id = (SELECT items.user_id FROM items WHERE items.id = upvotes.item_id LIMIT 1)
GROUP BY users.id
ORDER BY total DESC
) m, (SELECT #rank := 0) r
But I reckon this will be super slow when the database grows...
You can do a simple join query in order to get the total likes for each item of user and order your results with the resulting count in descending order
SELECT u.*,i.*,COUNT(DISTINCT up.user) `total_user_likes_item`
FROM users u
JOIN items i ON(i.user_id = u.id)
JOIN upvotes up ON(up.item_id = i.id)
GROUP BY u.id,i.id
ORDER BY u.id,i.id,total_user_likes_item DESC
Edit from comments For user total likes you remove i.id from group by as below query
SELECT u.*,COUNT(DISTINCT up.user) `total_user_likes_item`
FROM users u
JOIN items i ON(i.user_id = u.id)
JOIN upvotes up ON(up.item_id = i.id)
GROUP BY u.id
ORDER BY total_user_likes_item DESC
I'll try answer your question:
In table users you can add row sum_upvotes. Every time when someone get one like (vote) you will increment this column by:
UPDATE users
SET sum_upvotes = sum_upvotes + 1
;
Of course, you will insert a column in table upvotes.
Finally, you query to select users and order them by upvotes will look like this
SELECT first_name, last_name
FROM users
ORDER BY sum_upvotes
;
Hope this helps.
Optimizng MySQL queries isn't my expertise, so I was wondering if someone could help me formulate the most optimal query here (and indices).
As background, I'm trying to find a distinct visitor id within a table of transactions with certain where criteria (date range, not a certain product, etc. as you see in the query below). Transactions and visitors have a one to many relationship, so there can be many transactions to a single visitor.
Another requirement for the results is that if a visitor_id is found in the result, it must be the first instance of a visitor_id (by date_time) in the entire table. In other words, the visitor_id should only exist in the date range set in the primary query and at no time beforehand.
Here's what I've put together so far. It uses NOT IN and a subquery, but this doesn't seem ideal because the query takes between 2-3 seconds being that the table has over 500k records. I've tried a few variations of indices, but nothing seems to really work.
Here's the query.
SELECT DISTINCT visitor_id, date_time
FROM pt_transactions
WHERE visitor_id NOT IN (SELECT visitor_id FROM pt_transactions WHERE date_time < '$this->_date_time_start')
AND campaign_id = $this->_campaign_id
AND a_aid = '$a_aid'
AND date_time >= '$this->_date_time_start'
AND date_time <= '$this->_date_time_end'
AND product_id != 65
And here's the complete table structure.
CREATE TABLE IF NOT EXISTS `pt_transactions` (
`id` int(32) NOT NULL AUTO_INCREMENT,
`type` varchar(2) NOT NULL COMMENT 'New Lead (NL), Raw Optin (RO), Base Sale (BS), Upsell Sale (US), Recurring Sale (RS), Base Refund (BR), Upsell Refund (UR), Recurring Refund (RR), Unknown Refund (XR), or Chargeback (C)',
`date_time` datetime NOT NULL,
`amount` varchar(255) NOT NULL,
`a_aid` varchar(255) NOT NULL,
`subid1` varchar(255) NOT NULL,
`subid2` varchar(255) NOT NULL,
`subid3` varchar(255) NOT NULL,
`product_id` int(16) NOT NULL,
`visitor_id` int(32) NOT NULL,
`campaign_id` int(16) NOT NULL,
`last_click_id` int(16) NOT NULL,
`trackback_type` varchar(255) NOT NULL COMMENT 'Shows if the transaction is tracked back to the original visitor via cookie or via IP. Usually only applies to sales via pixel.',
`original_transaction_id` int(32) NOT NULL COMMENT 'Reference to original transaction id, in this table, if type is RS, R, or C',
`recurring_transaction_id` varchar(32) NOT NULL COMMENT 'Reference to existing RecurringTransaction if type is RS',
PRIMARY KEY (`id`),
KEY `visitor_id` (`visitor_id`),
KEY `campaign_id` (`visitor_id`,`campaign_id`,`amount`,`product_id`),
KEY `transaction_retrieval_group` (`campaign_id`,`date_time`,`a_aid`),
KEY `type` (`type`),
KEY `date_time` (`date_time`),
KEY `original_source` (`campaign_id`,`a_aid`,`date_time`,`product_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=574636
You can try NOT EXISTS
SELECT DISTINCT visitor_id, date_time
FROM pt_transactions t
WHERE campaign_id = $this->_campaign_id
AND a_aid = '$a_aid'
AND date_time >= '$this->_date_time_start'
AND date_time <= '$this->_date_time_end'
AND product_id != 65
AND NOT EXISTS
(
SELECT *
FROM pt_transactions
WHERE visitor_id = t.visitor_id
AND date_time < '$this->_date_time_start'
)
Do EXPLAIN <query> and see how your indices are used. If you want you can post results in your question in a textual form.
From your query what i can understand is that...
Their is no need to write NOT IN Statement...
Because, you are already keeping a check for
date_time >= '$this->_date_time_start'
so thier is no need to check date_time < '$this->_date_time_start' in not NOT IN statement.
Only below should work fine :)
SELECT DISTINCT visitor_id, date_time
FROM pt_transactions
WHERE
AND campaign_id = $this->_campaign_id
AND a_aid = '$a_aid'
AND date_time >= '$this->_date_time_start'
AND date_time <= '$this->_date_time_end'
AND product_id != 65
I have a seemingly simple task but I cannot seem to find an elegant solution using 1 query...
Problem:
I have a table of recorded 'clicks' on 'posts', where each post is part of a 'category'.
I want to find the 16 highest clicked posts in the last 30 days -- but I want to avoid duplicate categories.
It seems very simple actually, but I seem to be stuck.
I know how to get the most clicked in last 30, but I can't figure out how to avoid duplicate cats.
SELECT cat_id,
post_id,
COUNT(post_id) AS click_counter
FROM cs_coupon_clicks
WHERE time_of_click > DATE_SUB(NOW(), INTERVAL 30 DAY)
GROUP BY post_id
ORDER BY click_counter DESC
I tried to get creative/hacky with it... it's close but not correct:
SELECT cat_id,
Max(sort) AS sortid
FROM (SELECT cat_id,
post_id,
COUNT(post_id) AS click_counter,
CONCAT(COUNT(post_id), '-', post_id) AS sort
FROM cs_coupon_clicks
WHERE time_of_click > DATE_SUB(NOW(), INTERVAL 30 DAY)
GROUP BY cat_id, post_id) t1
GROUP BY cat_id
ORDER BY cat_id ASC
Any help would be greatly appreciated as I am not really a MySQL expert. I may end up just doing some PHP logic in the end, but I am very curious as to the correct way to approach a problem like this.
Thanks guys.
EDIT (structure):
CREATE TABLE `cs_coupon_clicks` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`src` varchar(255) NOT NULL DEFAULT '',
`cat_id` int(20) NOT NULL,
`post_id` int(20) NOT NULL,
`tag_id` int(20) NOT NULL,
`user_id` int(20) DEFAULT NULL,
`ip_address` char(30) DEFAULT NULL,
`referer` varchar(255) NOT NULL,
`browser` varchar(10) DEFAULT NULL,
`server_var` text NOT NULL,
`time_of_click` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
KEY `cat_id` (`cat_id`),
KEY `post_id` (`post_id`),
KEY `user_id` (`user_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
TEMP WORKING SOLUTION (HACKY):
SELECT
cat_id,
MAX(sort) AS sortid
FROM (
SELECT
cat_id,
post_id,
COUNT(post_id) AS click_counter,
RIGHT(Concat('00000000', COUNT(post_id), '-', post_id), 16) AS SORT
FROM cs_coupon_clicks
WHERE time_of_click > DATE_SUB(NOW(), INTERVAL 30 DAY)
GROUP BY cat_id, post_id
) AS t1
GROUP BY cat_id
ORDER BY sortid DESC
There is no easy single query solution to this problem, it's a group-wise maximum kind of problem based on a temporary table (the one with counts) that would require self-joins.
Assuming your database grows big enough (otherwise just go for your php logic) I would go for a statistics table, holding info about categories, posts and click counts:
CREATE TABLE `click_cnts` (
`cat_id` int(20) NOT NULL,
`post_id` int(20) NOT NULL,
`clicks` int(20) NOT NULL,
PRIMARY KEY (`cat_id`,`post_id`),
KEY `cat_id` (`cat_id`,`clicks`)
)
and fill it using the same query as the first one in the question:
INSERT INTO click_cnts(cat_id, post_id, clicks)
SELECT cat_id, post_id, COUNT(post_id) AS click_counter
FROM cs_coupon_clicks
WHERE time_of_click > NOW() - INTERVAL 30 DAY
GROUP BY cat_id,post_id
You could update this table using triggers or running update query periodically (do users really need info up to the very last second? probably not...) and save a lot of processing as finding most clicks for each category on indexed table requires a lot less time using a classic group-wise max approach:
SELECT cg.cat_id, cu.post_id, cg.most_clicks
FROM
( SELECT cat_id, max(clicks) as most_clicks FROM click_cnts
GROUP BY cat_id ) cg
JOIN click_cnts cu
ON cg.cat_id = cu.cat_id
AND cu.post_id = ( SELECT cc.post_id FROM click_cnts cc
WHERE cc.cat_id = cg.cat_id
AND cc.clicks = cg.most_clicks
LIMIT 1 )
ORDER BY cg.most_clicks DESC
LIMIT 16
Shot in the dark here. Did you try Select DISTINCT cat_id
i have a mysql database, in this i have a table called articles. I want to display the archive of this article in my web page. What i want to do is, i have to display the year, once user click the year it will show the list of month which contains the article .. How i can write mysql query for this? The problem i'm facing is, i have to display the year which contains the article same like for months also. I have the article created date in the form of timestamp in my table.. Can any one suggest me how to do this?
EDIT:
CREATE TABLE IF NOT EXISTS `articles` (
`id` int(20) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
`pid` int(20) NOT NULL DEFAULT '0',
`department_id` int(20) NOT NULL,
`author` varchar(100) NOT NULL,
`created` varchar(25) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=23 ;
Your database engine has functions that extract individual parts of the data and time from a SQL timestamp. For example, in MySQL you could do SELECT YEAR(created), MONTH(created) FROM articles ...
i just suggest u the alogorithm
first select all year name from databse using
SELECT FROM_UNIXTIME(created, '%Y') AS `year`
FROM articles
GROUP BY year
then get data of each month using below
SELECT *, FROM_UNIXTIME(created, '%Y') AS `year`
FROM articles
HAVING `year` = 2009
to show the articles
in php
$r = mysql_query("select * from articles order by year, month");
then display them all
$oldYear =0;
while($article = mysql_fetch_array($r){
$year =$article[year]
if($year != $oldYear){
echo $year
oldYear = $year
}
echo $article[month]
}
And with ajax, just make that each mont is a submenu of year
Hope this helps