Select and update not working - php

I have a table viewer with id, ip, date_last_viewed & blog_id as the columns. I'm first checking whether a particular entry having the same IP and blog_id is present or not. If yes, it updates the date. Else, it inserts a new entry.
My code is below:
$search_ip = mysql_query("SELECT ip FROM viewer WHERE ip = '".$_SERVER['REMOTE_ADDR']."' AND blog_id= '".$b_id."' ");
if ($search_ip == false){
$insert_ip = mysql_query("INSERT INTO viewer (ip, blog_id, date_last_viewed) VALUES ('".$_SERVER['REMOTE_ADDR']."', '".$b_id."', NOW())");
}
else {
$update_ip = mysql_query("UPDATE viewer SET date_last_viewed = NOW() WHERE ip = '".$_SERVER['REMOTE_ADDR']."' AND blog_id='".$b_id."' ");
}
The table is not inserting anything. What am I doing wrong here? Also, as I'm new to PHP programming, could someone tell me how to modify the above code to PDO?

You can actually do it in just one query.
MySQL has a special feature called INSERT ... ON DUPLICATE KEY UPDATE which basically insert if the record does not exist or update if it already exists. One thing you need to do is to define a unique column(/s)
INSERT ... ON DUPLICATE KEY UPDATE Syntax
Based on your statement, you need to define a unique constraint on both column,
ALTER TABLE viewer ADD CONSTRAINT vw_uq UNIQUE (ip, blog_id)
and execute this statement,
INSERT INTO viewer (ip, blog_id, date_last_viewed)
VALUES ($_SERVER['REMOTE_ADDR'], b_id, NOW())
ON DUPLICATE KEY UPDATE date_last_viewed = NOW()
As a sidenote, the query is vulnerable with SQL Injection if the value(s) of the variables came from the outside. Please take a look at the article below to learn how to prevent from it. By using PreparedStatements you can get rid of using single quotes around values.
How to prevent SQL injection in PHP?

Assuming your mysql_query executes correctly, it wont return false. What you should do is check the number of rows it returns. You can do this using mysql_num_rows.
Also, take note of the big red warning box at the top of the mysql_* man pages.

You should first add error handlers. Then move to mysqli_ and use prepared statements.
$search_ip = mysql_query( "SELECT ... " ) or die( mysql_error() );
if( mysql_num_rows($search_ip) == 0 ) {
$insert_ip = mysql_query( "INSERT ... " ) or die( mysql_error() );
}
else {
$update_ip = mysql_query( "UPDATE ... " ) or die( mysql_error() );
}

$search_ip will never == false, because it is a reference to the result. Use mysql_num_rows($earch_ip) instead. Also note that mysqli replaces this and your code is actually deprecated

That's not the right way to check if a query returned a value:
$search_ip = mysql_query("SELECT ip FROM viewer WHERE ip = '".$_SERVER['REMOTE_ADDR']."' AND blog_id= '".$b_id."' ");
if (mysql_num_rows($search_ip)==0) {
....
}

Related

SQL INSERT INTO table results in duplicates

I have a script that I have setup a CRON for that is getting values from a 3rd party server via JSON (cURL)
Right now every time the cron runs it will INSERT a completely new record. Causing duplicates, and resulting me in manually removing the dups.
How would I go about preventing duplicates, and only update the information that is either missing, or different from the NEW $VAR values?
What I want to do can be expressed like this: IF old value is NOT new value use new value else use old value;
if ($stmt->num_rows !== 1) {
if ($insert_stmt = $mysqli->prepare("
INSERT INTO members (
start_date
)
VALUES (?)"))
{
$insert_stmt->bind_param('s',
$StartDate,
);
if (! $insert_stmt->execute()) { echo ''; }
}
}
}
You should try using INSERT ... ON DUPLICATE KEY UPDATE. Documentation
This does mean that you will have to define some unique (could be primary) key to the table that is always constant so MySQL knows what to update.
A quick example of how you would do it:
INSERT INTO table (f1,f2,f3) VALUES ('something_unique',2,5)
ON DUPLICATE KEY UPDATE f2=2,f3=5
The following statement will be silently ignored if one of the fields with the flags UNIQUE or PRIMARY KEY already exist in the database. If you're searching for INSERT IF NOT EXISTS this is probably what you're looking for:
INSERT IGNORE INTO `members` SET name='Steve',start_date='2015-11-20';
You can also overwrite a record that already exists using REPLACE. If it doesn't yet exist, it will be created:
REPLACE INTO `members` SET name='Steve',start_date='2015-11-20';
Another thing to consider would be INSERT ... ON DUPLICATE KEY UPDATE syntax:
INSERT INTO table (a,b,c) VALUES (1,2,3)
ON DUPLICATE KEY UPDATE c=c+1;
UPDATE table SET c=c+1 WHERE a=1;
I ended up writing another if statement to check if a unique value existed from incoming and the existing db value existed and leaving it blank to prevent it from importing duplicates. I also wrote a separate file to update where values differentiate between what I am receiving as (new) and what is in the database (old) which actually worked out great for my application.
Here is my answer for anyone else that runs into this issue :)
$prep_stmt = "SELECT * FROM table WHERE column_keys=?";
$stmt = $mysqli->prepare($prep_stmt);
if ($stmt) {
$stmt->bind_param('s',$varvalues);
$stmt->execute();
$stmt->store_result();
if ($stmt->num_rows == 1) {
if ($insert_stmt = $mysqli->prepare("")) {
$insert_stmt->bind_param('');
if (! $insert_stmt->execute()) {
echo 'shits broke'; }
}
}
else { if ($insert_stmt = $mysqli->prepare("
INSERT INTO table (column_keys)
VALUES (?)")) // you will need a ? per column seperate by a , (?,?,?...?)
{ $insert_stmt->bind_param('s',
$varvalues
); // you will also need to bind a 's' (string) 'i' for num, etc per $var value.
if (! $insert_stmt->execute()) { echo 'shits broke';} //lol
}
}
}
Also a simple error reporting trick I stumbled upon that helped me clean up a few things I overlooked. Just place it at the top of the file, or above you want to debug ;)
error_reporting(E_ALL);

PHP MySQL PDO duplicates

I have the below code, which works perfect. What i want to do is to check the refNo first to see if there are duplicates entries in MySQL. If there is then appear a warning message, otherwise appear a "ok" message. How can i do that with PDO? Any help?
(include("db.php"));
$SQLquery = "INSERT INTO mydatabase (refNo, name)
VALUES ('".$_POST["refNo"]."', '".$_POST["name"]."');";
$STH = $dbc->query($SQLquery);
?>
edit: Hello guys,
i prefer not to add primary keys. Is there any other way?
Set up refNo as a primary key. You could also create it as unique but that defeats the purpose - your reference number appears to be a unique primary identifier. Perfect choice for a primary key.
Further, change your query
try {
$SQLquery = "INSERT INTO mydatabase (refNo, name) VALUES (:refNo, :name)";
$SQLquery = $dbc->prepare($SQLquery);
$SQLquery->bindValue(':refNo', $_POST['refNo']);
$SQLquery->bindValue(':name', $_POST['name']);
$SQLquery->execute();
} catch (Exception $e) {
die("Insert error");
}
$count = $SQLquery->rowCount();
if ($count == 1) {
echo "Record added!";
}
This binds the post value to prevent SQL injection too.
Edit: You could follow this up with $count = $SQLquery->rowCount(); which will be 1 if the insert was successful, as it appears you've edited your question since you posted it for more info.
If you want to do this without using a database level constraint, you'll need to do an extra SELECT statement before inserting into the table. But that gives you no absolute guarantees, as it might be two processes want to insert the same row at the same time and they will still succeed.
-- it'll look a little something like this; I'm not familiar with PDO but the structure should be the same
$selectQuery = "SELECT * FROM mydatabase
WHERE refno = '".$_POST["refNo"]."'";
$res = $dbc->query( $selectQuery );
if( $res->count() > 0 ) {
// this result already exists; show error
}
else {
// this result is new; put the insert query here
}

If inputs exist, dont insert, else insert PHP mysql

I've just started with php, and i wondered if anyone can help.
i have this
$sql="INSERT INTO $tbl_name SET date='$mydate' , event='$myevent'";
$result=mysql_query($sql);
I need to know how to make it see if the event exists, and if it does i need it to do nothing, if it doesn't then insert it!
split it into 2 queries:
1) check if event exists. If yes then do nothing, else insert a new event
2) continue with your query. this way the event will allays exist when inserting your data
This is something that can be done through MySQL alone.
Setup a unique key for the event column by running the following MySQL Command on your table:
CREATE UNIQUE INDEX `i_event` ON `TABLE_NAME_GOES_HERE` (`event`);
For more information: http://dev.mysql.com/doc/refman/5.0/en/create-index.html
Do this for every possible table you expect to see in the $tbl_name variable.
Then, change your PHP Query:
$sql="INSERT IGNORE INTO $tbl_name SET date='$mydate' , event='$myevent'";
$result=mysql_query($sql);
For more information on INSERT IGNORE: http://dev.mysql.com/doc/refman/5.5/en/insert.html
INSERT IGNORE simply does as it states... it will try to insert the row unless it fails validation (in this case from an index that you declared HAS to be unique).
Try:
$query = mysql_query("SELECT $myevent from $tbl_name ")
$rows = mysql_num_rows($query)
if ($num_rows > 0) {
// do nothing
}
else {
$sql = "INSERT INTO $tbl_name SET date='$mydate' , event='$myevent'";
$result = mysql_query($sql);
}
As a sidenote: mysql_ functions are deprecated and it's recommended to switch to mysqli or PDO.

insert a record or if exist then update in mysql doesnt work

i want that if a record doesnt exist i add it otherwise update it... but it doesnt work, whats the wrong with this code:
<?php
$user_id=$_POST['user_id'];
$user_email="user_email";
$last_stage=$_POST['last_stage'];
$score=$_POST['score'];
$note=$_POST['note'];
$con=mysqli_connect("localhost","ferfer","Drfrj","ferfw");
$result = mysqli_query($con,"SELECT user_email FROM rating WHERE user_email='".$user_email."'");
$num_rows = mysqli_num_rows($result);
if ($num_rows > 0) {
//echo "exist";
mysqli_query($con,"UPDATE rating SET user_id=".$user_id.", user_email='".$user_email."', last_stage=".$last_stage.", score=".$score.", note='".$note."' WHERE user_email='".$user_email."'";
mysqli_close($con);
}else{
//echo "does not exist";
mysqli_query($con,"INSERT INTO rating(user_id, user_email, last_stage, score, note)VALUES (".$user_id.",'".$user_email."',".$last_stage.",".$score.",'".$note."') ");
mysqli_close($con);
}
?>
You can actually do it in a single query since MySQL has implemented INSERT ... ON DUPLICATE KEY UPDATE which basically INSERTs a record if it does not exists otherwise UPDATEs it.
The first thing you need to do is to add a UNIQUE column on the table. In your example I see that user_email is the column you are searching for existence. If this is not unique, you need to alter the table for UNIQUE constraint
ALTER TABLE rating ADD CONSTRAINT tb_uq UNIQUE(user_email)
after it has been implement, build a query like this,
INSERT INTO rating(user_id, user_email, last_stage, score, note)
VALUES($user_id, '$user_email', last_stage, score, '$note')
ON DUPLICATE KEY UPDATE
user_id = $user_id,
last_stage = $last_stage,
score = $score,
note= '$note'
As a sidenote, the query is vulnerable with SQL Injection if the value(s) of the variables came from the outside. Please take a look at the article below to learn how to prevent from it. By using PreparedStatements you can get rid of using single quotes around values.
How to prevent SQL injection in PHP?
$user_email="user_email";
should be changed to
$user_email=$_POST['user_email'];
And missing ( simbol, as #Yogesh Suthar said. You should also consider escaping characters in strings, using i.e. mysql_real_escape_string function.
you forgot ) here
mysqli_query($con,"UPDATE rating SET user_id=".$user_id.", user_email='".$user_email."', last_stage=".$last_stage.", score=".$score.", note='".$note."'
WHERE user_email='".$user_email."'");
^ // here
Better way is to use
REPLACE INTO `rating` (user_id,user_email,last_stage,score,note)
VALUES(#user_id,#user_email,#last_stage,#score,#note) WHERE user_email=#email
use also binding and prepared statements to make it more secure. Your code is very insecure because you have nor escape functions neither casting.
Example of using binding with PHP. $dbh is PDO object.
$stmt = $dbh->prepare("REPLACE INTO `rating` (user_id,user_email,last_stage,score,note)
VALUES(#user_id,#user_email,#last_stage,#score,#note) WHERE user_email=#email");
$stmt->bindParam('#name', (int)$user_id);
$stmt->bindParam('#user_email', $user_email);
$stmt->bindParam('#last_stage', $last_stage);
$stmt->bindParam('#score', $score);
$stmt->bindParam('#note', $note);
more on http://pl1.php.net/pdo
with binding you don't have to escape strings because it goes straight into the database layer without it having to be crudely spliced into the SQL statement.
The MySQL REPLACE statement works like the INSERT statement with the additional rules:
If the record which you want to insert does not exist, the MySQL REPLACE inserts a new record.
If the record which you want to insert already exists, MySQL REPLACE deletes the old record first and then insert a new record.
$user_email="user_email"; should be $user_email=$_POST["user_email"];

Syntax error with IF EXISTS UPDATE ELSE INSERT

I'm using MySQL 5.1 hosted at my ISP. This is my query
mysql_query("
IF EXISTS(SELECT * FROM licensing_active WHERE title_1='$title_1') THEN
BEGIN
UPDATE licensing_active SET time='$time' WHERE title_1='$title_1')
END ELSE BEGIN
INSERT INTO licensing_active(title_1) VALUES('$title_1')
END
") or die(mysql_error());
The error is
... check the manual that corresponds to your MySQL server version for the right syntax to use near 'IF EXISTS(SELECT * FROM licensing_active WHERE title_1='Title1') THEN ' at line 1
My actual task involves
WHERE title_1='$title_1' AND title_2='$title_2' AND version='$version' ...ETC...
but I have reduced it down to make things simpler for my problem solving
In my searches on this, I keep seeing references to 'ON DUPLICATE KEY UPDATE', but don't know what to do with that.
Here is a simple and easy solution, try it.
$result = mysql_query("SELECT * FROM licensing_active WHERE title_1 ='$title_1' ");
if( mysql_num_rows($result) > 0) {
mysql_query("UPDATE licensing_active SET time = '$time' WHERE title_1 = '$title_1' ");
}
else
{
mysql_query("INSERT INTO licensing_active (title_1) VALUES ('$title_1') ");
}
Note: Though this question is from 2012, keep in mind that mysql_* functions are no longer available since PHP 7.
This should do the trick for you:
insert into
licensing_active (title_1, time)
VALUES('$title_1', '$time')
on duplicate key
update set time='$time'
This is assuming that title_1 is a unique column (enforced by the database) in your table.
The way that insert... on duplicate works is it tries to insert a new row first, but if the insert is rejected because a key stops it, it will allow you to update certain fields instead.
The syntax of your query is wrong. Checkout http://dev.mysql.com/doc/refman/5.0/en/control-flow-functions.html
Use the on duplicate key syntax to achieve the result you want. See http://dev.mysql.com/doc/refman/5.0/en/insert-select.html
Another solution
$insertQuery = "INSERT INTO licensing_active (title_1) VALUES ('$title_1')";
if(!$link->query($insertQuery)){ // Insert fails, so update
$updateQuery = "UPDATE licensing_active SET time='$time' WHERE title_1='$title_1'";
$link->query($updateQuery);
}
Here is the example I tried and its works fine:
INSERT INTO user(id, name, address) VALUES(2, "Fadl", "essttt") ON DUPLICATE KEY UPDATE name = "kahn ajab", address = "Address is test"
I am amazed to see so many useless codes and answers...
Just replace INSERT with REPLACE.
¯\(ツ)/¯

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