It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
I'm trying to set a custom message for an input:
$this->form_validation->set_message('username', 'Choose a business, Mang!');
and display this:
<?php echo form_error('username'); ?>
But nothing displays for me, what is wrong?
Is this what I need? Example:
if($result)
{
$this->form_validation->set_message('username', 'Choose a business, Mang!');
}
You need to set rules as such:
$this->form_validation->set_rules('form_field_username', 'username', 'required|callback_business_check');
function business_check($username) {
if(strlen($this->input->post('form_field_business')) == 0) {
$this->form_validation->set_message('business_check', 'Choose a business, Mang!');
return false;
}
return true;
}
This is providing I have the right idea of what you are doing...
Related
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
How to add email function to send if the port isnt responding (false) to this script below ?
<?php
function test_port($host,$port=80,$timeout=6)
{
$fsock = fsockopen($host, $port, $errno, $errstr, $timeout);
if ( ! $fsock )
{
return FALSE;
}
else
{
return TRUE;
}
}
/* check our website http://www.example.com is up and running (port 80) and timeout after 20 seconds */
$ok = test_port('IP/website',80,20);
?>
The simplest way would be replacing return FALSE; with an appropriate call to the PHP mail function
EDIT: this solves the mail() poblem, but note that fsockopen might not be the right way to detect if a host is up. This question could be a good starting point.
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I have a page count to limit the number of times a logged out user can view profiles. If a user is logged out they are redirected to a sign-up page, this is right and should be what's happening but i'm getting the same thing happen when the user is logged in, how can i add an else statement or if statement to say only redirect to sign up page or only limit profile hits if not logged in?
Thanks
<?
!session_id() ? session_start() : null;
verify_profile_visit_limit();
function verify_profile_visit_limit(){
$free_profiles = array(99999,99998,99997,99996,99995,99994,99993);
if(in_array($_GET["id"], $free_profiles)) return;
if(! isset($_SESSION["page_access_count"])){
$_SESSION["page_access_count"] = 1;
}
$_SESSION["page_access_count"]++;
if($_SESSION["page_access_count"] > 5){
header("Location: limit.php");
exit();
}
}
?>
Just add an OR condition so you return if the user is logged in:
if(in_array($_GET["id"], $free_profiles) || isset($_SESSION['loggedIn']) && $_SESSION['loggedIn']) return;
With that your function will return before running the limit check. Assuming you store a boolean (true/false) in $_SESSION['loggedIn'].
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
I want to design a dynamic form using php. suppose i have created a text box using javascript as follow
var labels=new Array()
function add(type) {
var element = document.createElement("input");
var label=prompt("Enter the name for lable","");
labels.push(label);
document.getElementById('raj').innerHTML=document.getElementById('raj').innerHTML+label;
element.setAttribute("type", type);
element.setAttribute("name",label);
var rohit = document.getElementById("raj");
rohit.appendChild(element);
document.getElementById('raj').innerHTML=document.getElementById('raj').innerHTML+"<br/>";
}
I want to make this field as a required field using php(it is required). what should i do for that
In html5 you can set a required attribute.
element.setAttribute("required", "required");
If you want to use PHP, as mentioned in the question, that would happen on the server side. You have to validate the request received by a php script & check whether it is empty or not.
It's not clear what you want do do, but if you're using POST to send it to PHP then you can check if the value is empty like this
<?php
if(empty($_POST['value_name']))
{
echo 'value is required';
}
else
{
// OK
}
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
My pseudo code is as follows:
if($_GET['action'] == 'list'){
do function getFileList($dir)
else
do nothing
exit;
}
require_once "./dir.php";
require_once "./echo.php";
function getFileList($dir)
{
}
Your psuedo code is almost there.
require_once "./dir.php";
require_once "./echo.php";
function getFileList($dir)
{
/* ... */
}
if($_GET['action'] == 'list') {
getFileList($dir);
}
Are you asking how to send a variable via GET to a PHP file from within the same PHP file? You can create a form that submits to itself: http://www.tellingmachine.com/post/Simple-self-submitting-PHP-forms.aspx.
If you are looking to do something else, please provide additional details.
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 11 years ago.
I found a great contact form over here. How to show a "Successfully sent" message right under the contact from instead of using a redirect to an other page?
$formproc->SetFormRandomKey('9nLzAt2cQM2Zysm');
if(isset($_POST['submitted']))
{
if($formproc->ProcessForm())
{
$formproc->RedirectToURL("thank-you.php");
}
}
Change the form process code to this.
$formproc->SetFormRandomKey('9nLzAt2cQM2Zysm');
$successful = false;
if(isset($_POST['submitted']))
{
if($formproc->ProcessForm())
{
$successful = true;
}
}
Where you want the message to show.
if($successful){
echo "Successfully sent.";
}