Problem solved
The answer was
$query = "SELECT manager FROM tablename WHERE manager='$manager'";
Subtle difference, but removing the dots before and after $manager was the answer.
Credit to PHPFreaks.com
I had this;
<?php include 'dbdetails.php';
$id = mysql_real_escape_string($_GET['id']);
$query = 'SELECT `column` FROM `tablename` WHERE `id` = '.$id.' ';
$result = mysql_query($query);
$row = mysql_fetch_array($result);
echo $row['column'];
?>
(taken from here)
This works fine if I am solely working with an ID, however I have repeated values in the column I need to work with so ID will not work for what I am trying to achieve.
Essentially I am trying to create pages on the fly using the Manager column as the query as opposed to the ID.
What would be the correct way to achieve this? I presume DISTINCT comes into play?
I am aiming for;
Micky Adams
as my structure, where it fetches all instances of Micky Adams or whichever manager name is set up as the anchor.
If you changed it to:
$manager = $_GET['manager'];
$query = 'SELECT `column` FROM `tablename` WHERE `manager` = '.$manager.' ';
Wouldn't that achieve what you want? If you had more than one instance of the manager DISTINCT only partly helps depending how your data is actually stored.
Related
I am trying to do a query in PHP PDO where it will grab a simple result. So like in my query I need it to find the row where the column group is 'Admin' and show what ever is in the group column. I know that we already know what it should be [Should be admin] but just need to get the query to work. Its only grabbing 1 row from my table, so will I need forsearch?
If I change WHERE group = 'Admin' to WHERE id = '1' it works fine. But I need it so it can be where group = 'admin'
$sql2 = "SELECT * FROM groups WHERE group = 'Admin'";
$stm2 = $dbh->prepare($sql2);
$stm2->execute();
$users2 = $stm2->fetchAll();
foreach ($users2 as $row2) {
print ' '. $row2["group"] .' ';
}
Thanks
group is a reserved word in MySQL, that's why it's not working. In general it's a bad idea to use reserved words for your column and table names.
Try using backticks around group in your query to get around this, so:
$sql2 = "SELECT * FROM groups WHERE `group` = 'Admin'";
Also you should really use placeholders for values, because you're already using prepared statement it's a small change.
Edit: just to clarify my last remark about the placeholders. I mean something like this:
$sql2 = "SELECT * FROM groups WHERE `group` = ?";
$stm2->execute(array('Admin'));
try to use wildcard in your WHERE Clause:
$sql2 = "SELECT * FROM groups WHERE group LIKE '%Admin%'";
Since the value in your table is not really Admin but Administrator then using LIKE and wildcard would search the records which contains admin.
I would like to get the id of an item in the database, set it to a variable, and use it. I'm quite new to all this coding stuff. I'm basing this on.
http://jameshamilton.eu/content/simple-php-shopping-cart-tutorial?PHPSESSID=99d373741727e3010a32319f1ebed001
cart.php?action=add&pdin=fbs
$product = $_GET[pdin];
I can't use an integer for 'pdin' so, id like to use its corresponding id which is an integer and plug it into this line of code which only takes integers?
$sql = sprintf("SELECT * FROM products WHERE pdin = %d;", $product);
so in i would take $product = 'pdin' find it's id $id = 'id' and plug it in to the above code
$sql = sprintf("SELECT * FROM products WHERE id = %d;", $id);
I tried reading up on this sql FROM SELECT WHERE... confused me some
I'd use a prepared statement which would also make yourself a bit safer from SQL injection. What database interface are you using from php to mysql?
Here's one option:
$product = $_GET['pdin'];
$stmt = $db->Prepare("select * from products where pdin = ?");
$res = $db->GetAssoc($stmt,$product);
btw,
if you acces array items via key, always use quotations (' or ") otherwise PHP (unnecessary) first check, if key is constant
Ok, I figured it out. I'm sorry i didn't explain it all that well last night. I have a limited brain battery per day, and last night it was depleted.
What i wanted was quite simple. I wanted to find an items associated id in the database.
$query = "SELECT * FROM products WHERE pdin = '$product'";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_assoc($result)) {
$productID = $row['id'];
}
Now that parts done and returns the correct id. And the 'item exists' function fires correctly.
//function to check if a product exists
function productExists($productID) {
//use sprintf to make sure that $productID is inserted into the query as a number - to prevent SQL injection
$sql = sprintf("SELECT * FROM products WHERE id = %d;", $productID);
return mysql_num_rows(mysql_query($sql)) > 0;
}
So, Mark and Michal Hatak; When you where talking about using quotations on keys, does that mean...
$sql = sprintf("SELECT * FROM products WHERE 'id' = %d;", $productID);
putting quotations around things like 'id'? And it's for security?
Forgive me, I'm a new graphic designer and not adept at code.
I am having some difficulty running some SQL code.
What I am trying to do is, find a row that contains the correct username, and then get a value from that correct row.
This is my SQL in the php:
mysql_query("SELECT * FROM users WHERE joined='$username' GET name")
As you can see, it looks for a username in users and then once found, it must GET a value from the correct row.
How do I do that?
You need some additional PHP code (a call to mysql_fetch_array) to process the result resource returned by MySQL.
$result = mysql_query("SELECT name FROM users WHERE joined='$username'");
$row = mysql_fetch_array($result);
echo $row['name'];
mysql_query("SELECT `name` FROM users WHERE joined='$username' ")
Just select the right column in your 'select clause' like above.
Edit: If you are just starting out though, you might want to follow a tutorial like this one which should take you through a nice step by step (and more importantly up to date functions) that will get you started.
mysql_query("SELECT name FROM users WHERE joined='$username'")
$q = mysql_query("SELECT * FROM users WHERE joined='$username'");
$r = mysql_fetch_array($q);
$name = $r['user_name']; // replace user_name with the column name of your table
mysql_query("SELECT name FROM users WHERE joined='$username' ")
Read documentation : http://dev.mysql.com/doc/refman/5.0/en/select.html
I have the code below:
$do_id=$_GET['id'];
$new_workorder=$_GET['workorder'];
//get current workorder on file for record that will be updated
$query = "SELECT workorder FROM jvltodos WHERE id = '$do_id' LIMIT 1";
$bla = mysql_query($query);
$workorder_old = mysql_fetch_row($bla);
//get record for workorder on file that will have the new workorder
$query = "SELECT id FROM jvltodos WHERE workorder = '$new_workorder' LIMIT 1";
$bla = mysql_query($query);
$id_fix = mysql_fetch_row($bla);
if (isset($new_workorder) && $new_workorder!=$workorder_old) {
//update the changed record
$query = "UPDATE jvltodos
SET workorder={$new_workorder}
WHERE id = {$do_id}";
$result = mysql_query($query);
//update the record that had the old workorder
$query = "UPDATE jvltodos
SET workorder={$workorder_old}
WHERE id = {$id_fix}";
$result = mysql_query($query);
}
I pass the 'id' and 'workorder' into the url, so I GET them first. With that I update the record with that 'id' to the new 'workorder'. So far so good.
But I want to find the record that has that 'workorder' and update that with the 'workorder' from the old 'id'. (In simple terms: when I increase/decrease the 'workorder', I want to switch two records around)
To me it looks pretty straightforward, but it doesn't work. The first thing (update the id with the new workorder works.. but the other record stays the same.. it keeps the workorder that was already in there)
What am I missing? (must be something simple that I'm just overlooking.)
#andrewsi Thank you for the suggestion! I took the code out, copied it over to another page and did some echo's to see what was going on and that way I figured out easily what the problem was.
Example:
$bla = mysql_query($query);
$workorder_old = mysql_fetch_row($bla);
The $workorder_old that I wanted to have should've been a number. However, this didn't happen, but returned.. an array.
When I changed the code to...
$bla = mysql_query($query);
$bla = mysql_fetch_row($bla);
$workorder_old = $bla[0];
... it worked like a charm.
tiny note: I'm so used to grabbing the data in 1 step (another language), that I forgot that I needed to make a few steps in PHP. Guess it's time to throw it in a function perhaps.. :-)
I have small PHP script which has
$query = "SELECT MAX(id) FROM `dbs`";
//query run
$row = mysql_fetch_array($result);
$val = $row[0];
Which runs fine, but I want to understand why i can't access the row with the fieldname, like if i have this
$query = "SELECT id FROM `dbs`";
i am able to use the folowing
$val = $row['id'];
but whenever i use this MAX() function, i have to change to
$val = $row[0];
to access the values
I have no clue about this. Any help would be appreciated. Thankss
You need to give it an alias:
<?php
$query = "SELECT MAX(id) AS `id` FROM `dbs`";
//query run
$row = mysql_fetch_array($result);
$val = $row['id'];
Edit:
To explain this it's probably best to show an example of a different query:
SELECT MAX(`id`) AS `maxId`, `id` FROM `dbs`
Using the above it will return as many rows are in the table, with 2 columns - id and maxId (although maxId will be the same in each row due to the nature of the function).
Without giving it an alias MYSQL doesn't know what to call it, so it won't have an associative name given to it when you return the results.
Hope that helps to explain it.
SELECT MAX(id) AS myFieldNameForMaxValue
FROM `dbs`
and then
$row = mysql_fetch_array($result);
$val = $row['myFieldNameForMaxValue'];
If you run this query on mysql commandline you'll see that the field name returned by mysql is MAX(id). Try running on phpmyadmin and you'll see the same. So if you try $row['MAX(id)'] it'll work. When using a mysql function, it gets added to the name, so use an alias, like other said here, and you're good to go: SELECT MAX(id) AS id FROM dbs. Also, never forget to use the ` chars, just in case you have some columns/tables with reserved names, likefrom`.