images from database via php can't display - php

Question

thank's for help. I have problem displaying images retrieving from my database.
I cant see the image when loading image.php in img src or directly from the page. When i display the variable without header('Content-type: image/jpeg'); i can see all the code inside, as i put this line all goes off.
I have a table called TABLE with id, title, img stored as longblob directly uploaded inside phpmyadmin.
Can anyone help me?
index.php
<?php
session_start();
include "admin/include/connection2.php";
$data = new MysqlClass();
$data->connect();
$query_img ="SELECT * FROM table ORDER BY data ASC LIMIT 4";
$post_sql = $data->query($query_img);
if(mysql_num_rows($post_sql) > 0){
while($post_obj = $data->estrai($post_sql)){
$id = $post_obj->id;
$titolo = stripslashes($post_obj->title);
$data_articolo = $post_obj->data;
$immagine = $post_obj->img;
// visualizzazione dei dati
echo "<h2>".$titolo."</h2>";
echo "Autore <b>". $autore . "</b>";
echo "<br />";
echo '<'.'img src="image.php?id='.$post_sql['id'].'">';
echo $id;
echo "<hr>";
}
}else{
echo "no post aviable.";
}
// here is the image.php code
<?php
include "admin/include/connection2.php";
$data = new MysqlClass();
// connect
$data->connetti();
$id = $_GET['id'];
echo $id;
$query = mysql_query("SELECT * FROM articoli_news WHERE id='".$id."'"; //even tried to send id='1' but not working
echo $query;
$row = mysql_fetch_array($query);
echo $row['id']; //correct displaying
$content = base64_decode($query['img']);
header('Content-type: image/jpeg');
echo $content;
?>

Answer 1

Delete all "echo" commands except "echo $content;" because there are also appear in the output, and damage your image.
And use ob_start(); in the begining of the script, and check out your script file not contain any of whitespace characters before or after the php begint and close tags .