mysql and php array mixture - php

Question

I got mysql table like this
id | type | number
1 | c | 2
2 | c | 10
3 | c | 20
Also i got PHP array with values:
$array[c] = 5;
$array[d] = 10;
I wanna do something like this
( SELECT * FROM table WHERE number >= $array[ type ] )
so that type could be taken from mysql column somehow and used for finding correct value from array.
Thats kinda tricky, but I'm not sure how better I could ask.

Answer 1

This isn't the most elegant way but something like this?
$where = "WHERE ";
foreach($array as $key => $value)
{
$where .= "(type = $key AND number >= $value) OR";
}
$where = substr($where, 0, strlen($where)-2);
You'd have to attach that to your select statement and then run the query obviously.
Hopefully that allows someone else to catch on and provide a more elegant solution.

Answer 2

Try this:
$type = 'c';
$query = "SELECT * FROM table WHERE number >= " . intval( $array[ $type ] ) . " AND type = '" . $type . "'";

Answer 3

try to do it in two steps:
before use an sql query to put in an array the values of type
then in a while
( SELECT * FROM table WHERE number >= $array[$i] )
where $i is the index of the while loop

Answer 4

Possibly a bit better than using lots of WHERE clauses would be something like this:-
SELECT *
FROM table a
INNER JOIN
(SELECT 'c' AS RowType, 5 AS RowVal
UNION
SELECT 'd', 10) Sub1
ON a.type = Sub1.type AND a.number >= Sub1.RowVal
Set up a subselect which is just getting the constants, and then do a join between that subselect and your existing table.
In php done something like this:-
<?php
$SubQuery = array();
foreach ($array AS $key=>$value)
{
$SubQuery[] = "SELECT '$key' AS RowType, $value AS RowVal";
}
$sql = "SELECT *
FROM table a
INNER JOIN (".implode(" UNION ", $SubQuery).") Sub1
ON a.type = Sub1.type AND a.number >= Sub1.RowVal";
?>