Show data from db into another div (from selected $rowId ) - php

I'm having problems with showing data from a selected row into another div.
Meaning I'm showing eg forename and lastname, when the user clicks on the name (as a link), I would like to show more data from the Id chosen, and I would like it to be shown in a div box below.
See the site here: http://kristoff.it/onlinecoaching/
And my code:
<div class="greenBox1">
<h1>1 - VÆLG DIN ONLINE COACH</h1>
<div class="whiteBox1">
<?php
$sql = "SELECT * FROM coach ";
$coachId = $row["coachId"];
$fornavn = $row["fornavn"];
$efternavn = $row["efternavn"];
$result = mysql_query($sql);
while($row=mysql_fetch_assoc($result))
{
echo '<table border="0" align="left" height="100">';
echo '<tr>';
echo '<td width="95" rowspan="2" align="center" valign="middle"><img src="' . $row['imgUrl'] . '" width="85" height="85" alt="' . $row['imgAlt'] . '"/>' . '</td>';
?>
<!-- here I'm trying to write the id of the selected name to the div box below -->
<?
echo '<td><h2>' . $row['fornavn'] . $row['efternavn'] . '</h2></td>';
echo '</tr>';
echo '<tr>';
echo '<td valign="top" width="190"><p>' . $row['beskrivKort'] . '<br></p></td>';
echo '</tr>';
echo '</table>';
}
?>
</div>
</div>
<div class="greenBox2">
<h1>2 - BOOK TID I COACHENS KALENDER</h1>
<div class="whiteBox2" id="whiteBox2">
<!-- here would like the more data to show -->
</div>
</div>
Regards Maria

In your website, your URLs are empty. You need to put your ID.
echo '<td><h2>' . $row['fornavn'] . $row['efternavn'] . '</h2></td>';
With that URL, you will send the ID as a GET variable.
You must then request your data if the ID is set.
<div class="whiteBox2" id="whiteBox2">
<?php
if (isset($_GET['id']))
{
$sql = "SELECT * FROM coach WHERE coachId=" . (int)$_GET['id'];
// Do your stuff...
echo "Hello";
}
?>
<!-- here would like the more data to show -->
</div>

Related

echo two tables issues required to post twice (mysql, php)

I finally get reviews to work, which will allow user to post their review about the product and display them in a review page with product details, however I can't get it to work perfectly. When a user posts their review, it will update in the table but only the second post will show up.
The following image is from the test i was running,
Before posting a review
After posting the first review
After posting the second review
As the images display, the first review will never show up, only starting from the second and above,
Here my code for review page updated with full code
<?php
if (!isset($_SESSION)) {session_start();} //start session
if (!isset($_SESSION['client_ID'])) {
//echo "<script>alert('not logged in');</script>";
header("Location: index.html" );
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<meta name="keywords" content="Games, Gaming, PS4, PS3, XBOX, Video games">
<meta name="description" content="Games 4 You">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title>Games 4 You</title>
<link rel="stylesheet" type="text/css" href="Styles/ProductsStyle.css">
<!-- javascript/jQuery -->
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
</head>
<body>
<!--Add the following script at the bottom of the web page (before </body></html>)
Support system using MyLiveChat.com
-->
<script type="text/javascript" async="async" defer="defer" data-cfasync="false" src="https://mylivechat.com/chatinline.aspx?hccid=42206151"></script>
<script>// disable zoom to keep image fit and always in position
document.firstElementChild.style.zoom = "reset";
// the above script will disable zoom in and out
</script>
<script type="text/javascript">
// this will auto change the background image to the following 7 images which are in the root Images/
// this is set to change every five second
// declare list of backgrounds
var images = ['bg-01.jpg', 'bg-02.jpg', 'bg-03.jpg', 'bg-04.jpg', 'bg-05.jpg', 'bg-06.jpg', 'bg-07.jpg'];
// declare function that changes the background
function setRandomBackground() {
// choose random background
var randomBackground = images[Math.floor(Math.random() * images.length)];
// set background with jQuery
$('body').css('background-image', 'url("Images/' + randomBackground + '")');
}
// declare function that sets the initial background, and starts the loop.
function startLoop() {
// Set initial background.
setRandomBackground();
// Tell browser to execute the setRandomBackground every 5 seconds.
setInterval(setRandomBackground, 5 * 1000);
}
// One the page has finished loading, execute the startLoop function
$(document).ready(startLoop);
</script>
<header id="header">
<div class="container">
<center><img src="Images/Title.png" alt="Title"></div>
</center>
</header>
<center>
<nav>
<?php
echo "<p> Welcome ".$_SESSION['client_name']."</p>";
//create connection
$con = new mysqli("localhost", "student", "student", "cib4003_h00233671_at");
if ($con->connect_errno) { //failed
echo "Failed to connect to MySQL: (" . $con->connect_errno . ") " . $con->connect_error;
}?>
<div class="wrapper">
<ul id="category" >
<li>Home</li>
<li>Products</li>
<li>View Cart</li>
<li>About</li>
<li>Settings</li>
<li>Logoff</li>
</ul>
</nav>
</div>
</center>
<main>
<h3>Available Products</h3>
<?php
$product = $_GET["RID"];
$_SESSION["product_name_RID"] = $_GET["RID"];
$sql="SELECT * FROM products,reviews WHERE products.Product_Name = '$product' AND reviews.Product_Name = '$product'";
//$sql="SELECT * FROM reviews WHERE Product_Name = '$product'";
// $sql="SELECT * FROM pizza,pizzacart WHERE pizza.Pizza_ID=pizzacart.Pizza_ID AND pizzacart.client_ID=".$_SESSION['client_ID'];
//echo "connected to DB";
//run SQL query
$result = mysqli_query($con,$sql);
//output result
if(mysqli_num_rows($result)==0) //no records found
{
$sql="SELECT * FROM products WHERE Product_Name = '$product'";
$result = mysqli_query($con,$sql);
// echo "<p>no records in DB".mysqli_num_rows($result)."</p>";
// echo "<p><a href=products.php></a>";
// link has been disable because i am using the <a for something else so i can't force the image to be in the center when using <a
// so the result will only be image that tell the customers no products found click all or search with different data
?>
<table class="table-style-one">
<tr>
<th>Product Image</th>
<th>Product Name</th>
<th>Description</th>
<th>Product Type</th>
<th>Console Type</th>
</tr>
<?php
while($row = mysqli_fetch_array($result)) { //loops through records
echo "<tr>";
echo "<td><img src='".$row['picture']."'/>";
echo "<td>".$row['Product_Name']."</td>";
echo "<td>".$row['Description']." <center><b><br>".$row['Trailer']."<br></b></center></td>";
echo "<td>".$row['Product_Type']."</td>";
echo "<td>".$row['Console_Type']."</td>";
echo "</tr>";
}
//end of loop
echo "</table>";
echo "<p>No Reviews available for this product.<br> To post a review of this product, fill up the below form.</p>";
//end of else
}
else
{
?>
<table class="table-style-one">
<tr>
<th>Product Image</th>
<th>Product Name</th>
<th>Description</th>
<th>Product Type</th>
<th>Console Type</th>
</tr>
<?php
while($row = mysqli_fetch_array($result)) { //loops through records
echo "<tr>";
echo "<td><img src='".$row['picture']."'/>";
echo "<td>".$row['Product_Name']."</td>";
echo "<td>".$row['Description']." <center><b><br>".$row['Trailer']."<br></b></center></td>";
echo "<td>".$row['Product_Type']."</td>";
echo "<td>".$row['Console_Type']."</td>";
echo "</tr>";
echo "<br>";
?>
<?php
while($row = mysqli_fetch_array($result)) {
echo "<table class=table-style-one align=center>";
// echo "<tr><th>Review ID</th><td>".$row['Review_ID']."</td></tr>";
echo "<tr><th>Review By:</th><td>".$_SESSION['client_name']."</td></tr>";
echo "<tr><th>Review Title</th><td>".$row['Review_Title']."</td></tr>";
echo "<tr><th>Rate:</th><td>".$row['Review_Rate']."/5</td></tr>";
echo "<tr><th>Review</th><td colspan=2>".$row['Review']."</td></tr>";
echo "<tr><th>Submitted On</th><td>".$row['Review_Date']."</td></tr>";
echo "<br>";
?>
<?php
}
//end of loop
echo "</table>";
//end of else
}
}
?>
<table class="table-style-one" align="center">
<tr>
<form method="POST" action="submitreview.php">
<!--<th>Product Name:</th><td> <input type="text" size="30" id="ReviewTitle" name="ReviewTitle" pattern=".{5,}" required title="5 characters minimum" placeholder="Review Title"></td> -->
<th>Review Title:</th><td> <input type="text" required size="30" id="ReviewTitle" name="ReviewTitle" pattern=".{5,}" required title="5 characters minimum" placeholder="Review Title"> </td>
<th>Rate: </th>
<td>
<select name="Review_Rate" required>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
</td>
<tr>
<td colspan="4">
<textarea name="WriteReview" id="WriteReview" required rows="10" cols="50" wrap="physical" placeholder="Write your Review here" style="margin: 0px; width: 437px; height: 150px;"></textarea>
</td>
</tr>
<td align="center" colspan="2"><input type="submit" value="submit"></td>
<td colspan="2"><input type="Reset"></td>
</form> </tr>
</table>
</h2>
<br>
<br>
<br>
</main>
</body>
<footer>
<p>Made by Humaid Al Ali - H00233671</p>
<div id="google_translate_element"></div><script type="text/javascript">
function googleTranslateElementInit() {
new google.translate.TranslateElement({pageLanguage: 'en', layout: google.translate.TranslateElement.InlineLayout.HORIZONTAL, multilanguagePage: true}, 'google_translate_element');
}
</script><script type="text/javascript" src="//translate.google.com/translate_a/element.js?cb=googleTranslateElementInit"></script>
</footer>
</html>
and here the php file where I insert the review into the table
<?php
if (!isset($_SESSION)) {session_start();} //start session
if (!isset($_SESSION['client_ID'])) {
//echo "<script>alert('not logged in');</script>";
header("Location: index.html" );
}
?>
<?php
//new connection
$con = new mysqli("localhost", "student", "student", "cib4003_h00233671_at");
if ($con->connect_errno) { //failed
echo "Failed to connect to MySQL: (" . $con->connect_errno . ") " . $con->connect_error;
}
//success
//if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// run sql
$sql ="INSERT INTO `cib4003_h00233671_at`.`reviews`(`Review_ID`, `Product_Name`, `client_ID`, `Review_Title`, `Review_Rate`, `Review`) VALUES (NULL, '".$_SESSION['product_name_RID']."', '".$_SESSION['client_ID']."', '".$_POST["ReviewTitle"]."', '".$_POST['Review_Rate']."', '".$_POST['WriteReview']."');";
if ($con->query($sql) === TRUE) {echo "<h3> New record created successfully</h3>";
header('Location: '. $_SERVER['HTTP_REFERER'] );
} else {
echo "Error : " . $sql . "<br>" . $con->error;
}
$con->close();
?>
Problem:
As the images display, the first review will never show up, only starting from the second and above
That's because you're fetching the first row which includes the first review but you don't display it, rather you starting fetching next reviews and display them. Look at the two conditions in while block inside the else block.
Solution:
To display reviews, you should do something like this:
<?php
// your code
if(mysqli_num_rows($result)==0){
// your code
}else{
echo "<table class='table-style-one'>";
echo "<tr>";
echo "<th>Product Image</th>";
echo "<th>Product Name</th>";
echo "<th>Description</th>";
echo "<th>Product Type</th>";
echo "<th>Console Type</th>";
echo "</tr>";
// fetch first row, which also contains first review
$row = mysqli_fetch_array($result);
echo "<tr>";
echo "<td><img src='" . $row['picture'] . "'/>";
echo "<td>" . $row['Product_Name'] . "</td>";
echo "<td>" . $row['Description'] . "<center><b><br>" . $row['Trailer'] . "<br></b></center></td>";
echo "<td>" . $row['Product_Type'] . "</td>";
echo "<td>" . $row['Console_Type'] . "</td>";
echo "</tr>";
echo "</table>";
echo "<table class=table-style-one align=center>";
echo "<tr>";
echo "<th>Review ID</th>";
echo "<th>Review By:</th>";
echo "<th>Review Title</th>";
echo "<th>Rate:</th>";
echo "<th>Review</th>";
echo "<th>Submitted On</th>";
echo "</tr>";
do{
// display first review and then fetch rest of the reviews
echo "<tr>";
echo "<td>" . $row['Review_ID'] . "</td>";
echo "<td>" . $_SESSION['client_name'] . "</td>";
echo "<td>" . $row['Review_Title'] . "</td>";
echo "<td>" . $row['Review_Rate'] . "/5</td>";
echo "<td colspan=2>" . $row['Review'] . "</td>";
echo "<td>" . $row['Review_Date'] . "</td>";
echo "</tr>";
}while($row = mysqli_fetch_array($result));
echo "</table>";
?>
</table>
<?php
}
// your code
?>
The problem looks to me to be in your SQL query. It looks as though your SQL query should actually be doing a join on the related column to bring together data across two different tables
$sql="SELECT *
FROM products AS p,
JOIN reviews AS r
ON p.Product_Name = r.Product_Name
WHERE products.Product_Name = '$product'";
But I think the easiest solution would be to run another query within the table output loop where you get the reviews for the product name you are currently outputting and loop over those.

PHP / MySQL - Query not fetching any data

I have been trying to set up a page that lists prices of items from a table in a database. Here is my code:
<?php
$querylist = mysql_query("SELECT item_name,image,price,added_by FROM values");
while($row = mysql_fetch_array($querylist))
{
echo '<div class="post rareitem" style="margin-right: 15px;float: left;">
<div class="rarename">
<strong>';
// Shows Item Name
echo $row['item_name'];
echo '</strong>
</div>';
// Shows Item Image
echo '<div class="rareimage" style="background-image: url(/app/tpl/skins/Mango/images/values/rares/';
echo $row['image'];
echo ');"></div>';
// Shows Item Price
echo '<div class="rarecontrols">
<div class="coinsbox"></div>
<span>
<b> <b>Credits: </b> </b> ';
echo $row['price'];
echo '</span>';
// Shows Who Added the Item
echo '<div class="addedbox"></div><b><b><span><font color="#c93734"><font color="#c93734">Added By: </font> </font>';
echo $row['added_by'];
echo '</span></b></b>
</div>
<div class="clear"></div>
</div>';
}
?>
There is another chunk of code (shown below) that I have based this off of, and it works perfectly fine. I can't seem to get this to work though. I believe it has something to do with the SQL, the syntax, or something. No matter what I do, it produces absolutely no results, yet the code below results exactly as planned. I know for a fact it is not a connection issue because the below code can be placed on the same exact page as the above one and it works fine, however the above does not.
<?php
$querylist = mysql_query("SELECT id,username,motto,country,look,rank,account_created,role,account_created,online,last_online FROM users WHERE rank='9' ORDER BY ID LIMIT 20");
while($row = mysql_fetch_array($querylist))
{
echo '
<div class="team">';
// Showing Avatar
echo '<div style="float: left; margin-top:-1px;height: 60px; width: 64px; background: url(http://www.habbo.nl/habbo-imaging/avatarimage?figure=';
echo $row['look'];echo "&action=wav&direction=3&head_direction=3&gesture=sml&size=m) no-repeat 0px -10px";
echo "\"/>";
echo "<img alt=\"badge\" src=\"/app/tpl/skins/habbo/images/icons/";
echo $row['online'];echo ".gif\"></div>";
// Flags
echo "<br/><img src=\"/app/tpl/skins/habbo/images/icons/flags/";
echo $row['country'];echo ".png";
echo '" style="float:right;" /> <b><uf>';
echo $row['username'];echo "</u></b>";
// Bans & Ticket Count
$Bans = mysql_query("SELECT * FROM `bans` WHERE `added_by` = '" . $row['username'] . "'");
$BanCount = mysql_num_rows($Bans);
$Tickets = mysql_query("SELECT * FROM `moderation_tickets` WHERE `moderator_id` = '" . $row['id'] . "'");
$TicketCount = mysql_num_rows($Tickets);
//Role
echo "<br/><gb>Role: </b><fi> ";
echo $row['role'];echo "";
echo "</i>";
// Echoing bans & Tickets
echo "<br/><gb>Bans: </b><fi> ";
; echo $BanCount;
echo "</i>";
echo " <gb>Tickets: </b><if>";
; echo $TicketCount;
echo "</i>";
echo "</div>";
}
?>
Thanks in advanced, any assistance will be greatly appreciated!
values is Reserved Words in mysql it should be on backtick
SELECT item_name,image,price,added_by FROM `values`
And stop using mysql it is deprecated. Instead use mysqli or PDO

How to save in session?

How can i save a session in php so that when i click value in td tag it will save a session and redirect into another page?
this is my code:
<?
$sql = "SELECT * from members";
$result = mysql_query($sql);
while($row1 = mysql_fetch_array($result)){
echo '<tr><td><img src='. $row1['propict'] .' width="70" height="70" /></td><td name="frnd"><a href="fprofile.php">' . $row1['name'] . '</td>';
}
?>
what i want here is when i click name that shows from td i will be redirected to fprofile.php that contain the information base on the name i clicked.
please help me guys to do this i really need to know this information.
You have 2 ways of doing the same :-
1). You can follow this approach also, but the user name will be displayed in the url.
Like:-
http://googl.com/aba.php?name=dinesh
<?
$sql = "SELECT * from members";
$result = mysql_query($sql);
while($row1 = mysql_fetch_array($result)){
echo '<tr>
<td><img src='. $row1['propict'] .' width="70" height="70" /></td>
<td name="frnd" onClick="showUserInfo('$row1[name]')"><a href="fprofile.php">' . $row1['name'] . '</td>';
}
?>
Js function write just below of you code..
function showUserInfo(name) {
window.location= <YOUR BASE URL>+'user_info.php?name='+name;
}
2). The name can also be set in the SESSION by AJAX also. This is a bite long approach but the name will not be displayed in the url.
You need to follow the following steps.
<?
$sql = "SELECT * from members";
$result = mysql_query($sql);
while($row1 = mysql_fetch_array($result)){
echo '<tr>
<td><img src='. $row1['propict'] .' width="70" height="70" /></td>
<td name="frnd" onClick="showUserInfo('$row1[name]')"><a href="fprofile.php">' . $row1['name'] . '</td>';
}
?>
JS function:---
Write the name in session in set_name_in_session.php file, then redirect the control to user_info.php page. There read the user name in user_info.php page and fetch the user details..
function showUserInfo(user_name) {
$.ajax({
url: <BASE_URL_OF_YOUR_SITE>+'set_name_in_session.php', //SET THE SESSION IN THIS FILE
data: {name: user_name},
method:'post',
success:function(response) {
window.location = <BASE_URL_OF_YOUR_SITE>+"user_info.php";
}
});
}
<?
$sql = "SELECT * from members";
$result = mysql_query($sql);
while($row1 = mysql_fetch_array($result)){
echo "<tr><td><img src='. $row1['propict'] .' width='70' height='70' /> </td>";
echo "<td name='frnd'><a href='fprofile.php?name=". $rows['name']. "'>" .
$row1['name'] . '</td>';
}
?>
and in fprofile.php
$_SESSION['name']= $_GET['name'];
now the clicked name is in the variable of $_SESSION['name']
just tell me if there is a syntax error
Update the link so that it passes the name you want to store in the session.
<a href="fprofile.php?name=' . $row1['name'] . '">' .$row1['name'] . '</td>
In fprofile.php, detect if $_GET['name'] has been set, and store it in the session.
if (isset($_GET['name']) && !empty($_GET['name'])) {
$_SESSION['name'] = $_GET['name'];
}
This assumes you are auto starting your session.
You can use $_REQUEST instead of $_GET to handle POST and GET requests similarly.

Activating certain PHP code before a section of the page is Created

I am working with an HTML webpage connected to a database and using PHP. I have in a div at the top a variable that doesn't get properly set until some PHP later in the document. Is there a way to make the div build after the later PHP, but still be where it should be at the top of the page?
Here's the code that uses the variables
<div id="HeaderRight">
<div id="HeaderRight">
<?php
echo '<a href="../Cart/index.php" class="header">
<img src="../Images/shoppingcart.gif" height="18" width="127" border="0" align="ABSMIDDLE" /> Contains '.$_SESSION["num_items"].' Items</a>'
?>
</div>
Here's the code that sets the variables
<?php
echo '<TABLE WIDTH="100%" BGCOLOR="#FFFFFF" ALIGN = "RIGHT" BORDER = "1">';
echo '<TR BGCOLOR = "818996" HEIGHT = "25"><TD>Product</TD><TD>Availability</TD> <TD>Qty</TD><TD>Price</TD><TD>Total</TD></TR>';
$strTotalPrice = 0;
for ($i=0; $i<$_SESSION['num_products']; $i++) {
$strSQL = "SELECT * FROM products WHERE ProductCode = '".$_SESSION['cart'][$i]['name']."'";
$rsProd = mysql_query($strSQL)
or die($db_name . " : " . $strSQL . " : " . mysql_error());
$rowProd = mysql_fetch_array($rsProd);
$strSQLDetails = "SELECT * FROM pagedetails WHERE Category = '".$rowProd["Category"]."'";
$rsDetails = mysql_query($strSQLDetails)
or die($db_name . " : " . $strSQLDetails . " : " . mysql_error());
$rowDetails = mysql_fetch_array($rsDetails);
// End Of "Retrieve Desired Record Set"
echo ' <TR HEIGHT = "' .$rowProd["ThumbnailHeight"]. '" ><TD style="vertical-align:middle"><img src="../'.$rowProd["Department"].'/Images/'.$rowProd["ProductCode"].'_sm.jpg" align = "left" border="0" height = "'.$rowProd["ThumbnailHeight"].'" width="100" hspace="25" />
<br><a href = "../Products/Products.php?PageID='.$rowDetails["PageID"].'" >'.$rowProd["ProductName"].'</a>
</TD>';
$strAvailability = "";
$strQuantity = 0;
if($rowProd["Stock"] < $_SESSION["cart"][$i]["qty"]){
$strAvailability = "Only " .$rowProd["Stock"]. " in Stock, Quantity Changed";
$strQuantity = $rowProd["Stock"];
$_SESSION["cart"][$i]["qty"] = $rowProd["Stock"];
}
else{
$strAvailability = "In Stock";
$strQuantity = $_SESSION["cart"][$i]["qty"];
}
echo '<TD ALIGN = "center">'.$strAvailability.'</TD>';
echo '<TD ALIGN = "center">
<input type="text" name="txtQuantity" size="2" maxlength="2" value ='.$strQuantity.'>';
echo '<form action="index.php?=?product='.$rowProd["ProductCode"].'&quantity=1" method="post">
<input type="submit" name="submit" value="Update">
</form>
</TD>';
$strPrice = $rowProd["RegPrice"] * $strQuantity;
$strTotalPrice += $strPrice;
echo '<TD ALIGN = "center">$'.$rowProd["RegPrice"].'.00</TD>';
echo '<TD ALIGN = "center">$'.$strPrice.'.00</TD></TR>';
//echo '( <a href=index.php?product=' . $_SESSION['cart'][$i]['name'] . '&quantity=1>+</a> )';
}
As Rocket Hazmat points out, it is a good idea to run all of your PHP code before rendering the HTML. Without rewriting your current code, you can achieve this with some output buffering:
<?
// add this block
function firstDiv() {
ob_start();
?>
<div id="HeaderRight">
... <? echo $_SESSION["num_items"]; ?> ...
</div>
<?
// ... and this block
$_SESSION["firstDiv"] = ob_get_contents();
ob_end_clean();
} // end of firstDiv
?>
and the same with the rest of your page
<?
function restOfYourPage() {
ob_start();
?>
<TABLE> ... <? $_SESSION["num_items"] = 666; ?> ... </TABLE>
<?
$_SESSION["restOfYourPage"] = ob_get_contents();
ob_end_clean();
} // end of restOfYourPage
?>
Then you can run the php code in reverse order, but display it in normal order:
<?
restOfYourPage();
firstDiv();
echo $_SESSION["firstDiv"];
echo $_SESSION["restOfYourPage"];
?>

Order list/ while loop php issue

I have put together a basic order list for admin users in php for checking order contents placed by logged in users.
The aim of this script is to retrieve the order details (item, quantity, price) as well as the user’s first name and surname (where ‘Order for:’ is).
The script below does everything ok in that it retrieves the order (and orders if there are more than one) and it’s/their item, quantity and price.
However, it doesn’t display the user’s name and surname.
I know the problem is that where I am trying to display the name is outside the while loop but Im a little stuck in where it should sit. Any suggestions? Code is below:
<?php
$page_title = 'View Individual Order';
include ('includes/header.html');
// Check for a valid user ID, through GET or POST.
if ( (isset($_GET['id'])) && (is_numeric($_GET['id'])) )
{ // Accessed through view_users.php
$id = $_GET['id'];
} elseif ( (isset($_POST['id'])) && (is_numeric($_POST['id'])) )
{ // Form has been submitted.
$id = $_POST['id'];
} else { // No valid ID, kill the script.
echo '<h1 id="mainhead">Page Error</h1>
<p class="error">This page has been accessed in error.</p><p><br /><br /></p>';
include ('./includes/header.html');
exit();
}
?>
<h1>Order Details</h1>
<?php
require_once ('database.php'); // Connect to the db.
// Retrieve the user's, order and product information.
$query = "SELECT us.users_id, us.users_sales_id, us.users_first_name, us.users_surname, us.users_dealer_name,
ord.order_id, ord.users_id, ord.total, ord.order_date,
oc.oc_id, oc.order_id, oc.products_id, oc.quantity, oc.price,
prd.products_id, prd.products_name, prd.price
FROM users AS us, orders AS ord, order_contents AS oc, products AS prd
WHERE ord.order_id=$id
AND us.users_id = ord.users_id
AND ord.order_id = oc.order_id
AND oc.products_id = prd.products_id
";
$result = mysql_query ($query) or die(mysql_error());
if (mysql_num_rows($result)) { // Valid user ID, show the form.
echo '<p>Order for:<strong>' . $row[2] . ' ' . $row[3] . ' </strong> </p>
<table border="0" style="font-size:11px;" cellspacing="1" cellpadding="5">
<tr class="top">
<td align="left"><b>Product</b></td>
<td align="center"><b>Price</b></td>
<td align="center"><b>Qty</b></td>
</tr>';
$bg = '#dddddd'; // Set the background color.
while($row = mysql_fetch_array($result, MYSQL_NUM)) { // WHILE loop start
$bg = ($bg=='#eaeced' ? '#dddddd' : '#eaeced');
echo '<tr bgcolor="' . $bg . '">';
echo '<td align="left">' . $row[15] . '</td>
<td align="center">' . $row[13] . ' pts</td>
<td align="center">' . $row[12] . '</td>
</tr>';
echo '';
}// end of WHILE loop
echo '</table>
<p> Here:</p>
<br><br>
<p> << Back to Orders</p>
<p> </p>
<p> </p>
<p> </p>
';
} else { // Not a valid user ID.
echo '<h1 id="mainhead">Page Error</h1>
<p class="error">This page has been accessed in error.</p><p><br /><br /></p>';
}
mysql_close(); // Close the database connection.
?>
<p>Footer here</p>
<?php
include ('./includes/footer_admin_user.html'); // Include the HTML footer.
?>
One way you could do it is grab the row first, and then use a do/while loop instead of just a basic while loop. Like this:
if (mysql_num_rows($result)) { // Valid user ID, show the form.
/*********** I added this line ***********/
$row = mysql_fetch_array($result, MYSQL_NUM);
echo '<p>Order for:<strong>' . $row[2] . ' ' . $row[3] . ' </strong> </p>
<table border="0" style="font-size:11px;" cellspacing="1" cellpadding="5">
<tr class="top">
<td align="left"><b>Product</b></td>
<td align="center"><b>Price</b></td>
<td align="center"><b>Qty</b></td>
</tr>';
$bg = '#dddddd'; // Set the background color.
/*********** I changed this from a while loop to a do-while loop ***********/
do { // WHILE loop start
$bg = ($bg=='#eaeced' ? '#dddddd' : '#eaeced');
echo '<tr bgcolor="' . $bg . '">';
echo '<td align="left">' . $row[15] . '</td>
<td align="center">' . $row[13] . ' pts</td>
<td align="center">' . $row[12] . '</td>
</tr>';
echo '';
} while($row = mysql_fetch_array($result, MYSQL_NUM)); // end of WHILE loop
It looks like the problem is when you're trying to display the user's name:
echo '<p>Order for:<strong>'.$row[2].' '.$row[3]
The $row variable doesn't exist yet. Not seeing your database or the result from your database query, my guess is that the user's name is repeated next to every single item in their order, so it might be as simple as just starting the WHILE loop, and checking to see if you've printed their name yet:
$lastUser = NULL;
while($row = mysql_fetch_array($result, MYSQL_NUM)) {
if ($row[0] !== $lastUser) {
if (isset($lastUser)) {
// finish up the report for the previous user
}
// echo the stuff for the current user's name
$lastUser = $row[0];
}
// go on echo-ing their order information
}
// after the while loop is over,
// close up the last user's report
But like I said, this is just a guess, and might be totally off.
The problem is that you tried to access $row[2] and $row[3] before mysql_fetch_array(). Since you are already echo'ing HTML tags, why don't you "buffer" your output first like this?:
while($row = mysql_fetch_array($result, MYSQL_NUM)) {
$bg = ($bg=='#eaeced' ? '#dddddd' : '#eaeced');
$order = '<tr bgcolor="' . $bg . '">
<td align="left">' . $row[15] . '</td>
<td align="center">' . $row[13] . ' pts</td>
<td align="center">' . $row[12] . '</td>
</tr>';
$orders[$row[2] . " " . $row[3]][] .= $order;
}
Then do a second foreach loop for the $orders
foreach($orders as $name => $orderList)
{
echo "Order for: $name";
echo "<table ...>";
foreach($orderList as $order)
{
echo $order;
}
echo "</table>";
}

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