Availability Check from MySQL with PHP Jquery - php

Question

I've a online book store where I sell books. Here I store data's of the cart on session. When two or more books are selected there may not be all the books available. I can do check only fore one book that is available or not. But I can't make it through when two or more books selected for ordering. What I did for one book is:
$result = mysql_query("SELECT id FROM book_table WHERE id IN ($cart)");
while ($row = mysql_fetch_array($result)) {
$q=mysql_num_rows(mysql_query("SELECT available FROM book_table WHERE id='$row[0]'"));
if($q!=0){
//order goes fore processing.
}
else{
//books not available.
$q2=mysql_fetch_array(mysql_query("SELECT name FROM book_table WHERE id='$row[0]'"));
echo "The book: $q2[0] Not Available";
//If there is more than 1 books in the cart and one or two books of them are not in the stock, its showing the order cant be processed(But I want to show which books aren't available).
}
}
Here $cart is the books cart saved on session like 1,2,3,4.
Now I need to show which books aren't available to buy by redirecting with another page.
Can anyone help me out on this?

Answer 1

make a array and put id and availaibilty as key and values pair and check for availaiblity for each id.

Answer 2

$all_available = true;
$orders = array();
$result = mysql_query("SELECT id, available, name FROM book_table WHERE id IN ($cart)");
while ($row = mysql_fetch_assoc($result)) {
if ($row['available')) {
$orders[] = $row['id'];
} else {
$all_available = false;
echo "The book: " . $row['name'] . " is not available.\n"
}
}
if ($all_available) {
// Process $orders
} else {
// Send redirect
}

Answer 3

You can do like below,
$query=mysql_query("SELECT id,available FROM book_table WHERE id IN ($cart) ");
$books_available_num = mysql_num_rows($query);
$books_order_num = count(explode(",",$cart));//i think there should be better way to do this...
if($books_available_num==0){
//no book is available
}elseif($books_available_num==$books_order_num ){
//all books are available
while($fetch=mysql_fetch_array($query)){
//order done successfully.
}
}else{
//some are available some are not.
while($fetch=mysql_fetch_array($query)){
if($fetch['status']=="available"){
//place in order
}else{
//this is not available
}
}
}
//rest of code. I think now you can do yourself.
I show you method and you can improve yourself. Code may contain errors, and you can improve it.

Answer 4

you can use ajax like without redirecting to other page
$.ajax({
url :'yourpage.php',
type :'post',
sucess : function(data){ alert(data)}
})
and your php code need a bit modification
$result = mysql_query("SELECT id FROM book_table WHERE id IN ($cart)");
$error = array();
while ($row = mysql_fetch_array($result)) {
$q=mysql_num_rows(mysql_query("SELECT available FROM book_table WHERE id='$row[0]'"));
if($q!=0){
//order goes fore processing.
}
else{
//books not available.
$q2=mysql_fetch_array(mysql_query("SELECT name FROM book_table WHERE id='$row[0]'"));
$error[] = "The book: $q2[0] Not Available";
//If there is more than 1 books in the cart and one or two books of them are not in the stock, its showing the order cant be processed(But I want to show which books aren't available).
}
if (!empty(error))
{
// print array as you want
}
else
{
echo "order successfully placed"
}
}
see more about jquery ajax
if you want to do that redirecting to other page the out $error in session.
I dont think any other thing can help you
NOTE : avoid using mysql_* as they are deprecated