JSON decode with PHP: Key started with # sign - php

Question

JSON is like
{
"#http_status_code": 200,
"#records_count": 200,
"warnings": [],
"query": { ... ...
In PHP
$data = json_decode($json_entry);
print $data->#http_status_code; //returns error
print $data->http_status_code; //returns nothing
How can I retrieve status code?

Answer 1

1) As Object way
$data = json_decode($json_entry);
print $data->{'#http_status_code'};
2) OR use as array way by passing second argument as true in json_decode
$data = json_decode($json_entry, true);
print $data['#http_status_code'];

Answer 2

Try json_decode to get the json in form of array ..
$json_array = json_decode($data, true);
$required_data = $data['required_key']
with reference to your particular problem .. you will get array as
Array
(
[#http_status_code] => 200
[#records_count] => 200
[warnings] => Array
(
)
....
)
so you can access you data as $data['#http_status_code']

Answer 3

To access an object property that has funky characters in the name, quote the name and stick it in braces.
print $data->{'#http_status_code'};
Or, say $data = json_decode($json_entry, true); to get the data back as an array.

Answer 4

PHP cwill give syntax error when you do this:
$data->#http_status_code;
it looks for $http_status_code variable which is not present
so in order to make this work you have to do this:
echo $data->{'#http_status_code'};

Answer 5

Try this:
$data = json_decode($json_entry, true);
print $data["#http_status_code"];