inserting if statement into css class in html - php

Question

I am trying to insert the following if statement into a class but getting the unexpected T_IF error;
class="color_icon_filter '. if ($link_data['id']==$link_data['text']) {$active} .' "
is this not possible or am I doing it wrong?

Answer 1

You shoud open PHP tags to be interpreted server side.
class="color_icon_filter <?php if ($link_data['id']==$link_data['text']) {echo $active} ?>"
EDIT
Or if you're already in PHP tags
echo 'class="color_icon_filter '.($link_data['id']==$link_data['text'] ? $active : '').'"';

Answer 2

It is not possible to concatenate an if statement onto a string.
You can do this instead:
$string = "123";
if ($bar) {
$string .= "456";
}
$string .= "789";
or this:
if ($bar) {
$baz = "456";
} else {
$baz = "";
}
$string = "123" . $baz . "789";
You could also use a ternary operator, but your if condition is (relatively) long, so it risks making your code look even more like line noise.

Answer 3

You're trying to concat in an if statement.
I'm assuming there's an echo in front of that line. You can either convert that to sprintf (http://php.net/sprintf) or put the if before the echo line, set the value of $active, and then concat in just the variable.
Personally, I think sprintf/printf is your better solution.

Answer 4

You cannot use an if statement in the middle of an assignment operation, but there are ways to achieve your desired result:
$active = '';
if ( $link_data['id']==$link_data['text'] ) {
$active = 'active';
}
$class = "color_icon_filter $active";
or a shorter way via the ternary operator:
$active = ( $link_data['id']==$link_data['text'] ) ? 'active' : '';
$class = "color_icon_filter $active";