I am trying to pass a variable from my ajax to my php script. I can't see to get it to work. It keeps on giving me NULL when I do a var_dump on the variable.
JQUERY:
$(document).ready(function() {
$('.trigger').click(function() {
var id = $(this).prev('.set-id').val();
$.ajax({
type: "POST",
url: "../modules/Slide_Show/slide_show.php",
data: id
});
LinkUpload(id);
function LinkUpload(id){
$("#link-upload").dialog();
}
});
});
</script>
PHP:
$id = $_POST['id'];
$query = mysql_query("SELECT * FROM xcart_slideshow_slides where slideid='$id'")or die(mysql_error());
$sli = mysql_fetch_array($query);
$slide_id = $sli['slideid'];
$link = $sli['link'];
var_dump($id);
I need the $id variable to post so I can dynamically change the dialog box when the click function is activated.
EDIT:
So I have changed some of my coding:
Jquery:
$(document).ready(function() {
$('.trigger').click(function() {
var id = $(this).prev('.set-id').val();
$.post(
"slide-show-link.php",
{ id: id },
function(data,status){alert("Data: " + data + "\nStatus: " + status); }
);
// alert(id);
LinkUpload(id);
});
function LinkUpload(id){
$("#link-upload").dialog();
}
});
I wanted to see if the data was in fact being passed so I threw an alert in the .post. This is the error I'm getting now:
I have tried passing plain text and echoing it back on the page but it fails. It is just not passing.
Try this -
$.ajax({
type: "POST",
url: "../modules/Slide_Show/slide_show.php",
data: { id : id }
});
Related
Hi i don't get retrieve Ajax Data to PhP page its throwing error. i pass data as json object.
The error i'm getting is
Edit.php
$('#regForm').on('submit', function (e) {
var url = document.URL; // Get current url
var id = url.substring(url.lastIndexOf('=') + 1);
var data1 = $("#regForm").serialize();
data = {data:data1,id:id};
console.log(data)
$.ajax({
method:"POST",
url: 'update.php',
dataType : 'json',
data: data,
success: function () {
alert('form was submitted');
}
});
});
update.php
if(isset($_POST["submit"]))
{
print_r($_POST['data']);
// Error::: Undefined index:data in
pass Id using hidden input field and then form data serialize then after you can use by name wise on php page.
$_POST['name'];
Read my comment, then look at this:
JavaScript may look like this
$('#regForm').on('submit', function(e){
var s = location.search.split('&'), serialId = s[s.length-1], idArray = serialId.split('=');
if(idArray.length === 2 && idArray[1].trim() !== '' && idArray[0].match(/^id$/i)){
var serialData = $(this).serialize()+'&'+serialId;
$.ajax({
method:'POST', url:'update.php', dataType:'json', data:serialData},
success:function(jsonObj){
console.log(jsonObj);
}
});
}
e.preventDefault();
});
PHP may look like this
<?php
if($_POST['id']){
// each property as $_POST[propertyHere]
// sending back to JavaScript
$c = new stdClass; $c->someProp = 'some value';
echo json_encode($c); // dataType is json so you should get Object as result
}
?>
I have a PHP page that will return JSON data as output. I get the data as AJAX. I want to display the results from JSON. But when I try to display each value I am getting undefined error.
This is the PHP code for getting data:
if (isset($_POST['dcqid'])) {
$question_id = intval($_POST['dcqid']);
if ($question_id != "") {
$user_id = $session->id;
$questiondetail = getData("dcquestions", "dcqid", "dcqid", $question_id, "", "");
//print_r($questiondetail);
echo json_encode($questiondetail);
?>
}
}
This is the JSON output I am getting
[{"dcqid":"10","current_id":"3","question":"Another Question","answer":"This is another question","description":"This is the description","date":"2017-08-10 11:55:51","active":"1"}]
This is the AJAX code I am using to display data
<script type="text/javascript">
$(".edit-current").on('click', function (e) {
e.preventDefault();
var id = $(this).data('currentid');
alert(id);
var url = "<?php SITE_URL ?>admin/" + "admin_edit_current.php";
var info = 'dcqid=' + id;
$.ajax({
type: "POST",
url: url,
data: info,
success: function (data) {
console.log(data);
console.log(data.dcqid); // undefined
},
error: function (data) {
alert(data.responseText);
alert("Error occured in showing details");
}
})
});
</script>
I am currently getting undefined for the values I want to display.
Its because the data var is an array. it's like this:
data = [
{
dcqid : 123
}
]
so try using
console.log(data[0].dcqid)
1st : Access it like this
console.log(data[0].dcqid);
2nd : Add dataType in ajax
dataType:"json"
Note : your value is inside the 0th index . so you need to access it like above.
var data =[{"dcqid":"10","current_id":"3","question":"Another Question","answer":"This is another question","description":"This is the description","date":"2017-08-10 11:55:51","active":"1"}];
console.log(data[0].dcqid);
I can't access my variables through ajax using php.
AJAX CODE
$("input[name='absent[]'").change(function() {
var obj = $(this); //checkbox
var valueZero = obj.val();
var Code = obj.attr('data-Code');
var value = obj.attr('data-session');
/*var theTR = $(this).parent('tr').children().find('td:eq(0)').addClass('hidden');*/
/* alert( theTR.text());*/
/*$(this).addClass('hidden');*/
$.ajax({
data: "{ code: '"+ Code +"', abt_prt: "+ valueZero +", InOut: "+ value +" }", // need to access these variables in php
type: "post",
dataType:'json',
url: "insertabsent.php",
success: function(){
obj.addClass('hidden');
}
});
});
PHP CODE
<?php
if(isset($_REQUEST))
{
$code = $_POST['code']; //variable
$absent_present = $_POST['abt_prt']; //variable
$session = $_POST['InOut']; //variable
//need this variables to perform a insert query
}
?>
Do try this :
JAVASCRIPT
var mainString = "code="+Code+"&abt_prt="+valueZero+"&InOut="+value;
IN AJAX
data : mainString
PHP
$code = $_POST['code']; //variable
$absent_present = $_POST['abt_prt']; //variable
$session = $_POST['InOut']; //variable
use data like
data: { code:Code , abt_prt : valueZero , InOut : value },
and in php I don't really know what is $_REQUEST is but you can use
if(isset($_POST)){
}
Try changing data variable to:
data: {"code":Code,"abt_prt":valueZero,"InOut":value},
You are misunderstanding how AJAX parameters have to be sent. You do not need to send an index, you can send a simple Javascript object, like this:
$.ajax({
data: { code: Code, abt_prt: valueZero, InOut:value}, // need to access these variables in php
type: "post",
dataType:'json',
url: "insertabsent.php",
success: function(){
obj.addClass('hidden');
}
});
However, if for some reason you want to send a string like you did, then decode it using json_decode.
First i echo images for which i set ID with php function. Now im tyring to get the ID value with jQuery click function and pass it to another php function, but unfortunately i always get the undefined index error. Can the reason be in xampp config or something else? Becasuse the code seems to be "right".
jQuery
$(function postImgId() {
$('img').click(function() {
var imgId = $(this).attr('id');
$.post('functions.php', {postId:imgId},
function(data) {
$('#content').html(data);
console.log(imgId);
});
});
});
php
function showPlayer() {
$number ='';
$number = $_POST['postId'];
if(isset($_POST['postId'])) {
echo "<h2>";
echo $_POST['postId'];
echo "</h2>";
}
}
Try:
Put this in your click function:
var imgId = $(this).attr('id');
$.ajax({
type: "GET",
url: "functions.php",
data: 'playerId=' + imgId,
success: function(data){
$('#content').html(data);
}
});
now check with isset($_GET['playerId']) and so on in your php:
if(isset($_GET['playerId'])) {
echo "<h2>";
echo $_GET['playerId'];
echo "</h2>";
}
This playerId should not be something important in your database like the unique AI id.
Whole thing also works with POST see: http://api.jquery.com/jquery.post/
In a JS file I am performing this function:
$(function() {
$(".button").click(function() {
//get the button's ID (which is equal to its row's report_id)
var emergency = this.id;
var button = this.attributes['name'].value;
var dataString = 'reportid=' + emergency;
alert(dataString);
if (button == "clockin") {
$.ajax({
type: "POST",
url: "/employeetimeclock.php",
data: dataString,
success: function() {
window.location = "/employeetimeclock.php";
}
});
} else if (button == "closereport") {
var r = confirm("Are you sure you want to close this report?\nThis action CANNOT be undone!");
if (r == true) {
$.ajax({
type: "POST",
url: "/closeemergencyreport.php",
data: dataString,
success: function() {
alert("Report Successfully Closed!");
window.location = "/closeemergencyreport.php";
},
error: function() {
alert("An error has occured, the report was not closed");
}
});
} else {
alert("Report was not closed.");
}
}
});
});
For the else if (to closeemergencyreport.php) the code in that php script is as follows:
<?php
require_once("models/config.php");
require_once("models/header.php");
require_once("models/dbconnect.php");
$reportid = $_POST['reportid'];
var_dump($_POST);
$sql = "UPDATE emergency_report SET report_closed = '1' WHERE report_id IN ( $reportid )";
//execute and test if succesful
$result = mysql_query($sql) or die(mysql_error());
if($result){
} else{
}
?>
I've done this same exact thing on 3 other pages and it works flawlessly however this is giving me trouble where on that php script the VAR_DUMP is saying it's returning an empty array. I've been reading and rereading the code for about an hour and a half now so I think i'm burnt out and need to have an outside view. Ive been all over the site and no one has had a solution that worked for me.
I know it's posting because fire bug is showing this on the form's page that the javascript is run on:
http://i.imgur.com/hItdVU1.png (sorry cant post images yet)