Jquery .autocomplete not working after ajax call - php

Hi guys i am trying to write a title matcher, i got it working but when an ajax call is made it no longer works below is my code :
<script type="text/javascript" src="jquery.autocomplete.js"></script>
<link rel="stylesheet" type="text/css" href="jquery.autocomplete.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
$(document).ready(function()
{
$(".course").autocomplete("look_me_up.php",
{
width: 260,
matchContains: true,
mustMatch: true,
selectFirst: false
});
$(".course").result(function(event, data, formatted)
{
$(this).next(".course_val").val(data[1]);
});
});
The text box i want to update is called from a ajax request which is made first :
<input type="text" name="course" id="text1" value="Find Title In DB" class="course">
<input type="hidden" id="val1" class="course_val">
And the ajax request is :
function checks()
{
$.ajax({
type : "POST",
url : "get_data.php",
data : "function="+"get_text",
success : function(msg)
{
$(update_me).html(msg);
}
});
}
I assume the jquery is acting up because the its trying to update a value pulled from the ajax request? I am struggling to get it to work so any help would be appreciated.

It looks to be a problem with the dynamic element creation.
You have loaded some course elements and autocomplete was initialized on them, later you seems to be replacing those elements with new elements. Here you are not initializing autocomplete for the new elements.
The solution is to initialize the autocomplete for the dynamically added elements
function createCourse(els){
els.autocomplete("look_me_up.php", {
width: 260,
matchContains: true,
mustMatch: true,
selectFirst: false
});
els.result(function(event, data, formatted){
$(this).next(".course_val").val(data[1]);
});
}
$(document).ready(function() {
createCourse($(".course"))
});
function checks() {
$.ajax({
type : "POST",
url : "get_data.php",
data : "function="+"get_text",
success : function(msg) {
$(update_me).html(msg);
createCourse($(".course", update_me))
}
});
}

Change
$(document).ready(function()
to
$(document).ajaxComplete(function()
and bingo :)

Related

Jquery change not working with Ajax call inside [duplicate]

For past few days i have been struggling to submit a form with jQuery and AJAX. The problem i'm facing is to upload the image in the form field.
My form is something like this:
<form action="#" method="GET" role="form" enctype="multipart/form-data">
<input type="text" placeholder="Name" name="name">
<input type="file" name="img" multiple>
<button type="submit">Submit </button>
</form>
and my jQuery script for getting the form value is something like this:
$("form").submit(function (event) {
$.dataArray = $(this).serializeArray(); // array of form data
console.log($.dataArray);
event.preventDefault();
});
But this returns all the field values except image one, in case of image is return null.
How do I store in the dataarray?
I want to store so I can send the value to the server through the AJAX.
For uploading single image its like this
<html>
<head>
<meta charset="UTF-8">
<title>AJAX image upload with, jQuery</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function (e) {
$('#upload').on('click', function () {
var file_data = $('#file').prop('files')[0];
var form_data = new FormData();
form_data.append('file', file_data);
$.ajax({
url: 'http://localhost/ci/index.php/welcome/upload', // point to server-side controller method
dataType: 'text', // what to expect back from the server
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function (response) {
$('#msg').html(response); // display success response from the server
},
error: function (response) {
$('#msg').html(response); // display error response from the server
}
});
});
});
</script>
</head>
<body>
<p id="msg"></p>
<input type="file" id="file" name="file" multiple />
<button id="upload">Upload</button>
</body>
</html>
For multiple images u will have to loop its kinda different
I have found a similar question, hope it will help you.
Upload image using jquery
Another option to consider is to use some sort of jQuery plugin to upload images like Cloudinary and include it in your HTML pages :
<script src='jquery.min.js' type='text/javascript'></script>
<script src='jquery.cloudinary.js' type='text/javascript'></script>
and then include all required jQuery files:
<script src='jquery.min.js' type='text/javascript'></script>
<script src='jquery.ui.widget.js' type='text/javascript'></script>
<script src='jquery.iframe-transport.js' type='text/javascript'></script>
<script src='jquery.fileupload.js' type='text/javascript'></script>
<script src='jquery.cloudinary.js' type='text/javascript'></script>
try this code, it's work for me.
$("form").submit(function (event) {
var form_data = new FormData($(this));
$.ajax({
url : url,
type : 'POST',
data : form_data,
processData: false, // tell jQuery not to process the data
contentType: false,
success : function(resp){
}
});
});
Try this code. using formData()
$("form").submit(function (event) {
var formData = new FormData($(this));
$.ajax({
url: url,
type: 'POST',
data: formData,
async: false,
success: function (data) {
//success callback
},
cache: false,
contentType: false,
processData: false
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="#" method="GET" role="form" enctype="multipart/form-data">
<input type="text" placeholder="Name" name="name">
<input type="file" name="img" multiple>
<button type="submit">Submit </button>
</form>
serialize() method not able to post file data.
For sending file using ajax use FormData instead of serializing
HTML5 introduces FormData to allow developers to build forms objects dynamically, and then to send this form object via AJAX.
your Html
<form action="upload_image.php" id="form_img" method="GET" role="form" enctype="multipart/form-data">
<input type="text" placeholder="Name" name="name">
<input type="file" name="img" multiple>
<button type="submit">Submit </button>
</form>
AJAX call
<script type="text/javascript" src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#form_img").submit(function(e){
e.preventDefault();
var formData = new FormData($("#form_img")[0]);
$.ajax({
url : $("#form_img").attr('action'),
type : 'POST',
data : formData,
contentType : false,
processData : false,
success: function(resp) {
console.log(resp);
}
});
});
});
</script>
upload_image.php
print_r($_FILES) //check you get file data or not
Try this way.Hope it will help you
Please check the follow the code, which i am using to upload image.
$.ajax({
url: UPLOADURL, // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this),// Data sent to server, a set of key/value pairs representing form fields and values
contentType: false,// The content type used when sending data to the server. Default is: "application/x-www-form-urlencoded"
cache: false,// To unable request pages to be cached
processData:false,// To send DOMDocument or non processed data file it is set to false (i.e. data should not be in the form of string)
success: function(data)// A function to be called if request succeeds
{
data = JSON.parse(data);
console.log(data);
if(data.status == "Success"){
attachmentListing();
//$("#mailerMessage").html(data.data.mailStatus);
//$("#mailerMessage").fadeIn();
setTimeout(function () {
$("#mailerMessage").fadeOut();
},5000);
}else{
toastr.warning(data.status);
}
$("#ajaxloader").addClass("hideajaxLoader");
},
error: function (jqXHR, errdata, errorThrown) {
log("error");
$("#ajaxloader").addClass("hideajaxLoader");
}
});

bootstrap typeahead with ajax

I'm not able to get typeahead to work on my website, here what I have tried.
My html and code
<html>
<head>
<title>typeahead</title>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap.min.css" rel="stylesheet">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/typeahead.js/0.10.4/typeahead.bundle.min.js"></script>
</head>
<body>
<input id="typeahead" type="text" data-provide="typeahead" autocomplete="off">
<script type="text/javascript">
$(document).ready(function() {
$('#typeahead').typeahead({
source: function (query, process) {
$.ajax({
url: 'data.php',
type: 'get',
dataType: 'JSON',
async: true,
data: 'query=' + query,
success: function(data) {
console.log(data);
process(data);
}
});
}
});
});
</script>
</body>
</html>
when I query data.php in my browser, I get the following
http://localhost/data.php?query=a
output
["admin","admin2"]
Yet, I'm not sure why its not working, backend works, I have checked my code many times, I wonder what I'm missing.
Your help is highly appreciated.
$.ajax({
url: 'data.php', // Just try url:'data.php?query=a'
type: 'get',
dataType: 'JSON',
async: true,
data: {'query' : query}, // changed
success: function(data) {
console.log(data);
process(data);
}
});
Typically typeahead uses handlebar.js as well so I included that here. I updated your code to match the remote example here (though I didn't actually test the code). Hopefully that will get you pointed in the right direction.
<html>
<head>
<title>typeahead</title>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/css/bootstrap.min.css" rel="stylesheet">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.1/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/typeahead.js/0.10.4/typeahead.bundle.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/handlebars.js/2.0.0/handlebars.min.js"></script>
</head>
<body>
<input id="typeahead" type="text" data-provide="typeahead" autocomplete="off">
<script type="text/javascript">
$(document).ready(function() {
var mySearch = new Bloodhound({
datumTokenizer: Bloodhound.tokenizers.obj.whitespace('value'),
queryTokenizer: Bloodhound.tokenizers.whitespace,
prefetch: 'data.php',
remote: 'data.php?query=' + query
});
mySearch.initialize();
$('#typeahead').typeahead(null, {
name: 'best-pictures',
displayKey: 'value',
source: mySearch.ttAdapter()
});
});
</script>
</body>
</html>
You can write you ajax call like this with Bootstrap 2.1.0 up to 2.3.2:
$(document).ready(function(){
$('#typeahead').typeahead({
source: function (typeahead, query) {
return $.get('data.php', { 'query': a }, function (data) {
return typeahead.process(data);
});
}
});
});
with Bootstrap 3.0 type is no longer bundled with it, So you can use Ajax Type-ahead
its very easy to use:
$("#ajax-typeahead").typeahead({
ajax: "/path/to/source"
});

.ajax() not sending data to php file

I am having a problem is retrieving data sent to a php file through .ajax() via jquery
Following is my html:
<!-- Jquery tute no 94 onwards -->
<html lang="en">
<head>
<meta charse="utf-8">
<title> jquery4 </title>
<link rel="stylesheet" type="text/css" href="jquery4.css"/>
</head>
<body>
<input id="lo" type="text"> </input>
<input id="ton" type="button" value="Load"> </input>
<div id="content"> </div>
<script type="text/javascript" src="jquery.js"> </script>
<script type="text/javascript" src="jquery4.js"> </script>
</body>
</html>
My jquery4.js is:
$(document).ready(function()
{
$('#ton').click(function()
{
var nm= $('#lo').val();
$.ajax({url: 'page.php', data1: 'name='+nm, success: function(data2)
{
$('#content').html(data2);
}
});
});
});
My page.php is:
<?php
if(isset($_GET['data1']))
{
echo $namer= $_GET['data1'];
}
?>
All the above files are in the same folder, and I have xampp installed.
I guess the error is somewhere in the jquery file where I call the
ajax() function
jQuery ajax doesn't take a data1 parameter. It takes a data parameter, which should be an object of name-value pairs.
$.ajax({
url: 'page.php',
data: {
data1: 'name=' + nm,
},
success: function(data2) {
$('#content').html(data2);
}
});
$.ajax({
type: "GET",
url: "page.php",
data: {
data1: 'name=' + nm,
}
,
success: function(data2) {
$('#content').html(data2);
}
});
Try this:
$(document).ready(function() {
$('#ton').click(function() {
var nm= $('#lo').val();
$.ajax({
url: 'page.php?name=' +nm,
success: function(data2) {
$('#content').html(data2);
}
});
});
});
You don't have to tell jQuery to use GET, as it defaults to that, if nothing else is specified.
So the ajax function does not take an argument called data1, but 'data', this is mostly used for other methods as POST, PUT and DELETE.
I prefer also sending GET requests with a normal query string, like the above example.
You can then check for get GET parameter with PHP, using $_GET['name']

fnDraw to redraw the datatable populated from DB

I use fnDraw to redraw the table. Look at the code below. This thread is similar to my previous one, but this provides an extended solution. The idea is to first call 'estimate.php' that updates DB and then reload the table that is populated from DB. The problem is that I can successfully call 'estimate.php', however the 'success' part of ajax is not performed well and the datatable stays unchanged.
<div id="refresh">
<button id="refresh-table">Refresh</button>
<br>
</div>
<script type="text/javascript" charset="utf-8">
$(document).ready(function(){
$('#newspaper-b').dataTable({
"sPaginationType":"full_numbers",
"aaSorting":[[5, "asc"]],
"bJQueryUI":true
});
$("#refresh-table").button().click(function() {
$.ajax({
url: "callpage.php?page=estimate.php",
success: function(html) {
var table=$("#newspaper-b").dataTable();
table.fnReloadAjax();
table.fnDraw();
}
});
});
});
</script>

$.ajax data not posting specified value to $_POST

Okay, what have I done wrong here?
I'm trying to .POST data from a Form with JQuery $.ajax function and return json data. But every time the post data is null.
Here is the HTML/JQuery Part
<!DOCTYPE HTML>
<html>
<head>
<link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1/themes/redmond/jquery-ui.css">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1/jquery-ui.min.js"></script>
</head>
<body>
<form action="testform" method="post">
OLD ID:
<input id="OldID" name="OldID" type="text"><br>
NewID:
<input id="NewID" name="NewID" type="text"><br>
<input id="do" name="do" type="button" value="Get New ID">
</form>
<script type="text/javascript">
var CID = $('#OldID').val();
$(document).ready(function(){
$('#do').click(function(){
sendValue();
});
function sendValue(CID){
$.ajax({
type: 'POST',
url: 'getNewID.php',
data: {OldID: CID},
dataType: 'json',
cache: false,
success:
function(data){
$('#NewID').val(data.NewID);
}
}) }
});
</script>
</body>
</html>
Here's the PHP page
<?php
if (isset($_POST['OldID'])){
$value = $_POST['OldID'];
}else{
$value = "ELSE VALUE";
}
echo json_encode(array("NewID"=>$value));
?>
I'm sure this is a simple mistake on my part but I'm just going in circles at this point.
Thanks in advance!
$('#do').click(function(){
sendValue();
});
should be:
$('#do').click(function(){
sendValue("VALUE TO SEND TO THE SERVER");
});
because
function sendValue(CID){
takes the scope of CID which it seems you might think should be this var CID = $('#OldID').val();
Your mistake is that you are getting the value of the OldID field in your script, and not on some event handler method. This causes when the script is loaded (when the page is being viewed), the value of the text input is kept on variable CID. and when the user clicks on the #do button, then the value of CID is still the same as the one when the page was loaded. So no value is stored in CID variable, so no value is sent via AJAX.
Define another function (Say sendOldID) that reads the value of the text input in the CID variable, and then calls the sendValue() method with CID paramter. The use that function as the event handler of the #do button clicked.
<script type="text/javascript">
$(document).ready(function(){
$('#do').click(function(){
sendOldID();
});
function sendOldID() {
var CID = $('#OldID').val();
sendValue(CID);
}
function sendValue(CID) {
$.ajax({
type: 'POST',
url: 'getNewID.php',
data: {OldID: CID},
dataType: 'json',
cache: false,
success:
function(data){
$('#NewID').val(data.NewID);
}
}) }
});
</script>

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