One regex, multiple replacements [duplicate] - php

Question

This question already has answers here:
Parse through a string php and replace substrings
(2 answers)
Closed 9 years ago.
OK, that's what I need :
Get all entries formatted like %%something%%, as given by the regex /%%([A-Za-z0-9\-]+)%%/i
Replace all instances with values from a table, given the index something.
E.g.
Replace %%something%% with $mytable['something'], etc.
If it was a regular replacement, I would definitely go for preg_replace, or even create an array of possible replacements... But what if I want to make it a bit more flexible...
Ideally, I'd want something like preg_replace($regex, $mytable["$1"], $str);, but obviously it doesn't look ok...
How should I go about this?

Answer 1

Code:
<?php
$myTable = array(
'one' => '1!',
'two' => '2!',
);
$str = '%%one%% %%two%% %%three%%';
$str = preg_replace_callback(
'#%%(.*?)%%#',
function ($matches) use ($myTable) {
if (isset($myTable[$matches[1]]))
return $myTable[$matches[1]];
else
return $matches[0];
},
$str
);
echo $str;
Result:
1! 2! %%three%%
if you don't want to tell upper from lower,
<?php
$myTable = array(
'onE' => '1!',
'Two' => '2!',
);
$str = '%%oNe%% %%twO%% %%three%%';
$str = preg_replace_callback(
'#%%(.*?)%%#',
function ($matches) use ($myTable) {
$flipped = array_flip($myTable);
foreach ($flipped as $v => $k) {
if (!strcasecmp($k, $matches[1]))
return $v;
}
return $matches[1];
},
$str
);
echo $str;