drop down menu from databse no result - php

Question

im trying to get the value from the database and display them in a dropdown menu
but im getting nothing in the drop down menu, here's the code please anyone ?
<select name="car" value="Select" size="1">
<?php
$sql = "SELECT fullname FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$name=$row['fullname'];
$options.="<OPTION VALUE=\"$name\">";
}
?>
<option>
<? echo $options ?>
</option>
</select>

Answer 1

You have several errors in your code. Try this instead:
<select name="car" value="Select" size="1">
<?php
$sql = "SELECT fullname FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
//securing from XSS
$name= htmlentities($row['fullname']);
//you had no closing tag, no name
$options.="<OPTION VALUE=\"$name\">$name</option>";
}
//need semicolon, no need for tags
echo $options;
?>
</select>

Answer 2

you missed option full syntax $options.="<OPTION VALUE=\"$name\">";
should be $options.="<OPTION VALUE=\"$name\">$name</OPTION>";
EDIT
<option><!--< not required as you already used in $options-->
<? echo $options ?>
</option><!--< not required as you already used in $options-->

Answer 3

in your code Semicolon(;) is missing in the end of $options:
<option>
<? echo $options ?>
</option>
also remove `value="Select"` with select tag
try this:
<select name="car" size="1">
<?php
$sql = "SELECT fullname FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$name=$row['fullname'];
echo "<OPTION VALUE='$name'>$options</option>";
}
?>
</select>

Answer 4

you mean
<select name="car" value="Select" size="1">
<? echo $options; ?>
</select>
also $options should be of the following form:
$options .= '<option value="'.$name.'">'.$name.'</option>';

Answer 5

change ur code to this..
<select name='cars'> <?php $sql = "SELECT fullname FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
echo "<OPTION VALUE='".$row['fullname']."'>".$row['fullname']."</OPTION>";
}?></select>

Answer 6

if you have entry in you table just remove extra option from your code
<select name="car" value="Select" size="1">
<?php
$sql = "SELECT fullname FROM users";
$result = mysql_query($sql) or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$name=$row['fullname'];
$options.="<OPTION VALUE=\"$name\">";
}
?>
<? echo $options ?>
</option>
</select>
just remove <option> before <? echo $options ?>