In PHP, if I have a datetime object or timestamp as properties of an object, how can I get a rough age for the record in PHP.
So that instead of a formated date string it says something like"about 1 hour ago", "3 days ago", "1 year ago" etc.A bit like redmine has for task comments, for example.
What is this process called?I tried searching for age and datetime and keep finding code to get someone's age of birth, which is not what I'm looking for.
if you have 2 objects. You need to convert first object to timestamp and second object is time();
time() - Returns the current time measured in the number of seconds since the Unix Epoch (January 1 1970 00:00:00 GMT).
Then you substract time() with date you want and you get difference in seconds. To make minutes from seconds you need divide it by 60, to make hours you need to divide it by 60 * 60 = 3600 etc.
$secondsAgo = time() - $timeStamp;
$minutesAgo= (time() - $timeStamp) / 60;
$hoursAgo= (time() - $timeStamp) / 60*60;
$daysAgo= (time() - $timeStamp) / 60*60*24;
To change string to timestamp you can use strtotime()
The other solution is to use diff() on DateTime object.
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
This returns DateInterval object which has a lot of properties that are public
y Number of years.
m Number of months.
d Number of days.
h Number of hours.
i Number of minutes.
s Number of seconds.
Related
I'm trying to know how many days have passed from a certain timestamp, but the problem is I can't set it up, so that after midnight will count it as another day.
Here is what I tried:
<?php
$now = time(); // or your date as well
$your_date = 1572123244;
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If I put a timestamp of five minutes before midnight (1572134100), five minutes after midnight should appear that "one day passed"
The usual way of counting the days passed since a given timestamp would be something like this:
$dt = date_create_from_format('U', 1572046200);
$diff = $dt->diff(new DateTime());
echo $diff->days;
But this counts the full 24 hour periods as days. In your case you want to count calendar dates irrespective of the time of day. I would recommend then to ceil the timestamp to the midnight.
$dt = date_create_from_format('U', 1572047700);
$dt->setTime(0, 0); // set time to 00:00
$now = new DateTime('now', new DateTimeZone('UTC')); // time now, but in UTC
$now->setTime(0, 0); // set time to 00:00
$diff = $dt->diff($now);
echo $diff->days;
I am not sure about your current time zone, but timestamps are by nature in UTC, hence you should probably normalize your local time to UTC as well.
What this code does is it sets both today's date and the timestamp you are comparing against to the midnight of the UTC day and then calculates the difference between the two. Taking the time out of equation, this will always count the full 24 hour days.
I am having :
hours1 : 403440
and date2 as :2016/01/10
I need to convert date2 in hours and find the difference between the two which should again be in hours.
The second parameter of date is a unix timestamp which is in seconds so multiple your hours by 3600 (3600 seconds per hour).
$hours1 = 403440 * 3600;
$date1 = date("d-m-Y H:i:s", $hours1);
echo $date1;
Output:
09-01-2016 19:00:00
Per your update your code should be:
$date2 = strtotime('2016/01/10');//get date to seconds from 1970
$hours1 = 403440 * 3600; // convert from hours to seconds
echo ($date2 - $hours1)/3600;//subtract seconds then divide by 3600 to get how many hours difference is
Output:
5
The second parameter of date() is unix timestamp which is the number of seconds since January 1 1970 00:00:00 UTC.
So, if $hours1 is number of hours since January 1 1970 00:00:00 UTC, it should be
date("d-m-Y H:i:s",$hours1*3600);
to yield the correct date string.
On the other hand, $hours2=(strtotime($date2)/3600); is giving you the correct number of hours since January 1 1970 00:00:00 UTC.
$now = new DateTime();
$future_date = new DateTime($date);
$interval = $future_date->diff($now);
echo $interval->format("%d days, %h hours, %i minutes, %s seconds");
Basically I want to use the difference between the two dates now and whatever the person has booked. I need to use an if statement to check if the difference is between 24 hours / 1 day.
how do i use datetime in if statements?
like
If ($interval > 24 hours) {
allow } my problem is how do i write 24 hours in php? sounds really dumb I know.
$now_ts = $now->getTime();
$future_date_ts = $future_date->getTime();
if ($future_date_ts - $now > 60 * 60 * 24) {
// more than 24 hours before $future_date
}
If you also want the diff the other way add:
$now - $future_date_ts > 60 * 60 * 24 // more than 24 hours after $future_date
This gives you a 48 hour range around $future_date.
You could instead use the UNIX timestamp ( the current time measured in the number of seconds since the Unix Epoch (January 1 1970 00:00:00 GMT).
time(); will return the current Unix timestamp and you can convert your future_date to a timestamp using strtotime();
So you can calculate the difference in seconds using:
$diff_secs = strtotime($future_date) - time();
And knowing 1 day is 24 hours which is 24*60 minutes which is 24*60*60 seconds,
$diff_days = (strtotime($future_date) - time())/(24*60*60);
Or you could use the difference in hours as your comparison :
$diff_hours = (strtotime($future_date) - time())/(60*60);
if($diff_hours > 24) {
//do something if its more than 24 hours away
}
I would like to compare a difference between two timestamps and a time in base 60 or 10.
More precisely if timestamp1-timestamp2 is longer (or no) than x hours and y seconds.
I'm using DateTime and DateInterval classes, but there isn't such a function, and i don't find a clean solution.
Thanks
$time1 = new DateTime("2011-01-26 01:13:30"); // string date
$time2 = new DateTime();
$time2->setTimestamp(1327560334); // timestamps, it can be string date too.
$interval = $time2->diff($time1);
echo $interval->format("%H hours %i minutes %s seconds");
Output
11 hours 32 minutes 4 seconds
$timestamp1 = strtotime('2012-01-26 14:00:00');
$timestamp2 = strtotime('2012-01-25 17:00:00');
if (abs($timestamp1 - $timestamp2) < 60 * 60 * 5 /* (5 hours) */) {
...
Convert both the timestamp and the real time to the UNIX timestamp. Then simply subtract to get the number of seconds difference.
With datetime objects:
$interval = $TempReceiptDateTime->diff($ShipDateTime);
echo $interval->format('%R%H:%I:%s days');
more
I have to find total months between two dates in Unix timestamp formats. I want to create a PHP function for that. I've tried this:
get_total_month($startunixdate, $endunixdate) {
$monthdiff = $endunixdate-$startunixdate;
$monthdiff = $monthdiff / 60*60*24*31;
return $monthdiff;
}
Does this function consider leap years as well as month with 30 and 31 separately, or it will just count an approximate month?
Your answer is in this line;
$monthdiff = $monthdiff / 60*60*24*31
This will just count a month based on 31 days. The code divides the seconds by 60 to get the number of minutes, 60 again to get hours, 24 to get number of days, then it uses 31 as the length of a month.
This will result in an approximation of the number of months. For instance, if you take timestamps at the beginning and end of February (start of March), you will usually have a timestamp difference equivalent to 28 days (29 in a leap year). Dividing that by 31 will give you a fraction less than 1, since you are using 31 to represent a full month, when in reality a whole calendar month has passed.
In order to do this, use the DateTime class.
function get_total_month($start, $end) {
// Create DateTime objects
$dt1 = new DateTime($start);
$dt2 = new DateTime($end);
// Get DateInterval object representing difference between the two
$diff = $dt1->diff($dt2); // OR: $diff = date_diff($dt1, $dt2);
// Print the "months" out
echo $diff->format("Difference: %R%m months"); // OR access $diff->m manually
U can use PHP 5.3 datetime method.
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Reference: PHP DateTime