MySQL join from two tables with one condition - php

Question

I can't figure out join..
need to select all rows from one table where a column equals something in another table..
like this:
SELECT ALL FROM someTable
WHERE COLUMN someColumn = '123' (IN A DIFFERENT TABLE)
something like that..
and the IDs need to match of course..

Answer 1

Just use an INNER JOIN:
SELECT *
FROM SomeTable S
JOIN SomeOtherTable S2
ON S.SomeKey = S2.SomeKey
WHERE S.SomeColumn = '123'
A Visual Explanation of SQL Joins
I wasn't completely clear of your question, so you may not need the WHERE clause if that represented your JOIN criteria.

Answer 2

A bit error in my question, let me clarify
tblplace
id place
1 London
2 Paris
3 New York
tbltraveller
tr_id tr_name id
1 John 3
2 Jackson 2
3 Susanna 1
4 Jimmy 3
5 Lucy 2
The problem is missing some data for New York:
Paris Jackson Lucy
New York
My code(guess there is an error in the while loop):
<?php
require_once("connMysql1.php");
$qry = "SELECT * FROM tblPlace WHERE tblPlace.id > 1 ORDER BY tblPlace.id";
$result = mysqli_query($db_link, $qry);
$qry1 = "SELECT tblPlace.id, tblPlace.Place, tbltraveller.tr_id,
tbltraveller.tr_name, tbltraveller.id FROM tblPlace INNER JOIN tbltraveller ON
tblPlace.id = tbltraveller.id WHERE tblPlace.id > 1 ORDER BY tbltraveller.id";
$result1 = mysqli_query($db_link, $qry1);
$no_of_row1 = mysqli_num_rows($result1);
$no_of_row = mysqli_num_rows($result);
echo "<table border=1 cellpadding=10>";
if ($no_of_row >0){
while ($row = mysqli_fetch_assoc($result)){
echo "<tr>";
echo "<td>";
echo $row['place']."<br>";
echo "</td>"." ";
echo "<td>";
while ($row1 = mysqli_fetch_assoc($result1)){
if($row1['id'] == $row['id']){
echo $row1['tr_name']." ";
}
}
echo "</td>";
"</tr>";
}
}
echo "</table>";
?>
`