Reverse engineering on a php function - php

I know it isn't actually the reverse engineering
I have this function:
<?=$this->get('translator')->trans('dashboard.actions', array(), 'front');?>
I want to understand how to insert a function (using include maybe) that gets called when using that code.
I know the function name needs to be trans, and it has 3 arguments, but how to define it? Let me put this in a more easy way: In a php script how do I print Hello world when using $this->get('translator')->trans('dashboard.actions', array(), 'front');

It's just a regular class method:
class Traslator{
public function trans($a, $b, $c){
return 'Hello world';
}
}
Now, you only need another class method called get() that returns an instance of the previous class:
class Foo{
public function get(){
return new Traslator;
}
}
Full code:
<?php
class Traslator{
public function trans($a, $b, $c){
return 'Hello world';
}
}
class Foo{
public function get(){
return new Traslator;
}
public function test(){
?>
<?=$this->get('translator')->trans('dashboard.actions', array(), 'front');?>
<?php
}
}
$f = new Foo;
$f->test();

$this references the current object instance, and that variable may not be re-assigned. Meaning, to trick PHP into doing what you want requires to add code before and after the line you mention.
By creating a single class, the result can be obtained.
Before the <?=... line
<?php
class C {
function get($s) {
return $this;
}
function trans($s, $a, $f) {
return 'Hello world';
}
function hw() {
?>
Then the line
<?=$this->get('translator')->trans('dashboard.actions', array(), 'front');?>
Then need, to end the class, and call the method that does what you want
<?php
}}
$i = new C();
$i->hw();
Put the 3 blocks of code into a file and call PHP on it, the <?=... line should show "Hello world".

$this->get('translator') return instance of class lets call it "Translator" - on that instance you call trans() method
so you would like to change instance of "Translator" to your extended version
class ExtTranslator extends Translator{
public function trans($params){
echo 'fdsfds'; // here you could add what you like
return parent::trans($params);
}
}
and yes - it's hard to help you cause I don't really know what are you trying to do - to work with that code you must first understand it...

Related

Using local variable from call in a function

After 9 hours of struggling to get this right, I have turned to the internet for help. I can't seem to find any relevant answers doing a Google search.
I currently have a class called Test. Test accepts a single argument.
<?php
class test {
private $varpassed;
public function getVarpas() {
return $this->varpassed;
}
Public function setVarpas($value) {
$this->varpassed= $value;
}
public function stringGen(){
$testvar = $this->varpassed;
echo $testvar;
}
}
The stringGen function should return the $varpassed variable whenever its called. The value for $varpassed is set using the setVarpas function. However, when ever I call the stringGen() method I only seem to be getting the following error:
Fatal error: Using $this when not in object context in file.php line 14.
Pointing to this line:
$testvar = $this->varpassed;
Is there any other way to pass the variable to the stringGen method? I've tried using:
self::$this->varpassed;
Which also throws an error.
first create an instance of the object (so you can use $this in the context), for example:
$test = new test();
then you can call:
$test->setVarpas('Hello World!');
now you can call:
$test->stringGen();
you have to do something like this
$var = new test();
$var->setVarpas("Hello");
$var->stringGen(); // this will echo Hello
$this is used when you are withing class. outside class you have to use class object.
1) Change this: class test() to class test
2) Create and instance first something like $t1 = new test();
3) Call the function $t1->setVarpas(5);
4) Now you can call the function $t1->stringGen();
Fixed:
<?php
class test
{
private $varpassed;
public function getVarpas() {
return $this->varpassed;
}
Public function setVarpas($value) {
$this->varpassed= $value;
}
public function stringGen(){
$testvar = $this->varpassed;
echo $testvar;
}
}
$t1 = new test();
$t1->setVarpas(5);
$t1->stringGen();
OUTPUT:
5
You should not declare a class with parentheses.
Use
class test {
instead of
class test(){

Aggregating Objects , need help/explanation

I have wrote this code by looking at similar code from a PHP cookbook. I have few troubles with executing and understanding it + it is not working well. Hope someone can help me.
<?php
class example {
//protected $a;
//protected $c;
public function NumberInput($number){
$this->a = $number;
}
public function NumberOutput(){
return $this->a;
}
}
class example2 {
public function __construct(){
$this->mergingclass = new example;
}
public function numberInput2($number){
$this->c = $number;
}
public function NumberOutput2(){
return $this->c;
}
public function __call($method,$arguments){
echo "called methos is $method <br> ";
;
return $this->x = $arguments;
}
}
$b = new example2;
$b->NumberInput(7);
echo $b->NumberOutput();
?>
so my questions are:
Why do I even need __construct function ? Code is working excatly the same with or without it. Or atleast I can't spot the difference with my newbie abilities. If I understand correctly it should agreggate objects but when I put it in comments nothing changes.
When I execute this code insted of number 7 I get "Array". I suppose number 7 is inside of that array, so how can I echo it ?
Thanks in advance.
First of all, __construct is like a magic method in PHP, that makes it possible to create an object out of class. Each time you write something like this:$myObject = new Object(); constructor of Object class is called by default and it creates object referenced by $myObject variable. So without that method in it, you will not be able to properly use classes and create objects.
use print_r($array) or var_dump($array) to see array structure

Convert static method to lambda in PHP

I want to get static method from class and copy it to variable.
This is non-working example illustrating my question:
class foo
{
public static function bar($argument){ return 2*$argument; }
}
$class = new ReflectionClass('foo');
// here is no ReflectionMethod::getClosure() method in reality
$lambda = $class->getMethod('bar')->getClosure();
echo $lambda(3);
So my question: is this possible by any normal way? I find only one way for now. I can parse source file, get method source from it and convert it using create_function() but it's too perverse.
Just wrap it with closure.
$lamda = function($argument){return foo::bar($argument);};
Or you can try to use something like this
function staticMethodToClosure($class, $method) {
return function($argument)use($class, $method){return $class::$method($argument);};
}
An array in the format array($className, $methodName) is invokable as a static method call so this may work for you.
class foo
{
public static function bar($argument){ return 2*$argument; }
public static function getStaticFunction($arg){
return array("foo", $arg);
}
}
$a = foo::getStaticFunction("bar");
echo $a(5); // echos 10

How to Pass a function to a class in php

I have a class that generates data based on a few things. I would like to format that data from the outside. So I am trying to pass a function into the class so that it would format that data. I have looked at many examples, but it seems this is unique.
Can anybody give an idea of how to do this? The following code gives an error.
<?php
class someClass {
var $outsideFunc; // placeholder for function to be defined from outside
var $somevar='Me'; // generated text
function echoarg($abc){
$outsideFunc=$this->outsideFunc; // bring the outside function in
call_user_func($outsideFunc,$abc); // execute outside function on text
echo $abc;
}
}
function outsidefunc($param){ // define custom function
$param='I am '.$param;
}
$someClass=new someClass();
$someClass -> outsideFunc = 'outsideFunc'; // send custom function into Class
$someClass -> echoarg($someClass->somevar);
$someClass -> outsidefunc = 'outsidefunc';
In PHP, function names are not case sensitive, yet object property names are. You need $someClass->outsideFunc, not $someClass->outsidefunc.
Note that good OOP design practice calls for the use of getter and setter methods rather than just accessing properties directly from outside code. Also note that PHP 5.3 introduced support for anonymous functions.
Yeah. You are right. Now there is no error. But it does not work either.
By default, PHP does not pass arguments by reference; outsidefunc() does not actually do anything useful. If you want it to set $param in the caller to something else, and do not want to just return the new value, you could change the function signature to look like this:
function outsidefunc(&$param) {
You would also need to change the way you call the function, as call_user_func() does not allow you to pass arguments by reference. Either of these ways should work:
$outsideFunc($abc);
call_user_func_array($outsideFunc, array(&$abc));
Why not pass your function as an argument?
<?php
class someClass {
public $somevar="Me";
public function echoarg($abc,$cb=null) {
if( $cb) $cb($abc);
echo $abc;
}
}
$someClass = new someClass();
$someClass->echoarg($someClass->somevar,function(&$a) {$a = "I am ".$a;});
i am not sure what exactly you are looking for, but what i get is, you want to pass object in a function which can be acheive by
Type Hinting in PHP.
class MyClass {
public $var = 'Hello World';
}
function myFunction(MyClass $foo) {
echo $foo->var;
}
$myclass = new MyClass;
myFunction($myclass);
OP, perhaps closures are what you're looking for?
It doesn't do EXACTLY what you're looking for (actually add function to class), but can be added to a class variable and executed like any normal anonymous function.
$myClass->addFunc(function($arg) { return 'test: ' . $arg });
$myClass->execFunc(0);
class myClass {
protected $funcs;
public function addFunc(closure $func) {
$this->funcs[] = $func;
}
public function execFunc($index) { $this->funcs[$index](); } // obviously, do some checking here first.
}

PHP add methods to Functions

Is it possible to add methods to functions?
For example:
<?
function func(){
;
}
//add method
func->test = function(){
;
}
func->test();
func();
I'm coming from a javascript background, and therefore I'm used to 'everything is an object'.
EDIT:
I was just explaining where the misconception may often come from for new phpers. I understand the above code doesn't work.
EDIT 2
Figured it out.
class myfunc_class{
function __invoke(){
//function body
}
function __call($closure, $args)
{
call_user_func_array($this->$closure, $args);
}
}
$func = new myfunc_class;
$func->test = function(){
echo '<br>test<br>';
};
$func->test();
$func();
Even sexier :)
class func{
public $_function;
function __invoke(){
return call_user_func_array($this->_function,func_get_args());
}
function __construct($fun){
$this->_function = $fun;
}
function __call($closure, $args)
{
call_user_func_array($this->$closure, $args);
}
}
$func = new func(function($value){
echo $value;
});
$func->method = function(){
echo '<br>test<br>';
};
$func('someValue');
$func->method();
No.
Not everything is an object in PHP. In fact the only thing that is an object is, well, an object. More specifically, and generally, an instantiation of a class.
Your code converted to PHP
// function_object.php
<?php
class FunctionObject {
public method func() {
// do stuff
}
}
?>
In other code you would use it like this:
<?php
// example.php in same folder as function_object.php
include 'function_object.php';
$FuncObj = new FunctionObject;
$FuncObj->func();
Also: read more about PHP & OOP
No, because an object is a different PHP language construct than a function. Functions do not have properties, but are instead simply execution instructions.
But, if func were instead a pre-defined class, then yes... with a bit of witchcraft, ignoring public outcry, foregoing readability and PHP coding standards, and by using closures with the __call() magic method...
class func
{
function __call($func, $args)
{
return call_user_func_array($this->$func, $args);
}
}
$obj = new func;
$obj->test = function($param1, $param2)
{
return $param1 + $param2;
};
echo $obj->test(1,1);
This won't work as you'd think without __call(), because by $obj->test(1,1), PHP thinks you're trying to call a non-existent method of func when out of object scope. But inside, being that the new "test" property is of a type: closure, the call_user_func_array() just sees the "test" property as just another function, so you can hide this bit of trickery from outside scope.
You would need your function func() to return an object, then you'd be able to do something like: func()->test();
But please note that your way of handling objects is not right in PHP and I suggest that you go read the OO documentations here.
In difference to javacript, in PHP not everything is an object. Therefore you need to differ between function and class.
If you want to create an object, you need to define the class first.
class myClass {
}
You can then add as many functions to the class as you need. But you need to define them first:
class myClass {
function test() {
echo "test!\n";
}
}
When everything is ready, you can bring it to life then:
$class = new myClass;
$class->test();
Checkout the manual for more.
You can't do what you're trying to do, but you can define functions inside of other functions.
This example outputs text:
function a() {
function b() { echo 'Hi'; }
}
a();
b();
Output: HiHi
This example outputs an error:
function a() {
function b() { echo 'Hi'; }
}
b();
Output: ERROR

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