Here is what I'm trying to do:
I need to add a tab on category edit page on the backend (admin panel).
I add it from an Observer file this way:
$tabs = $observer->getEvent()->getTabs();
$tabs->addTab('features', array(
'label' => Mage::helper('catalog')->__('Related Pages'),
'content' => '',
));
The problem is that I do not know how to properly populate the 'content' attribute so I was thinking of getting the "Content" block and manually assigning to it a different phtml file.
Can it be done?
Thanks in advance.
Try this.
$tabs->addTab('features', array(
'label' => Mage::helper('catalog')->__('Related Pages'),
'content' => Mage::app()->getLayout()->createBlock('[module]/[block]')->setTemplate('path/to/template.phtml')->toHtml(),
));
So you need to create you own block that will be rendered by the path/to/template.phtml template.
If you don't need any logic in your template you can skip the creation of the block and use adminhtml/template. Something like this.
$tabs->addTab('features', array(
'label' => Mage::helper('catalog')->__('Related Pages'),
'content' => Mage::app()->getLayout()->createBlock('adminhtml/template')->setTemplate('path/to/template.phtml')->toHtml(),
));
I am dealing with the CGridView widget in Yii. I've customized most of it, but can't seem to customize the icons that appear when you click on the column headers to sort the data. (little arrows that point either up or down depending on the sort order) Also, the icons are completely gone after adding in the 'columns' option. A portion of the code in my view is below:
<?php
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
'pager' => array('cssFile' => '/css/myCss.css'),
'cssFile' => '/css/myCss.css',
'summaryText' => 'Showing {start} - {end} of {count} data rows.',
'htmlOptions' => array('id' => 'grid'),
'columns' => array(
array(
'name' => 'name',
'value' => '$data->name',
),
array(
'name' => 'description',
'value' => '$data->description',
),
array(
'name' => 'date',
'value' => '$data->date',
),
),
));
?>
Yii's documentation isn't clear at all on this and there doesn't seem to be anyone (that I could find) that also has this issue.
->Also, a related question:
How would I make each row an anchor link? I need each row to be a link to view the details about the clicked row. I know that cgridview provides view, edit, and delete links at the end of the row if told to, but is it possible to get the entire row to be a single anchor link? I know how to do this manually in html, but don't know how to do this inside cgridview.
If you want to change the icon in the header of the table, you will need to override styles for classes (.grid-view table.items th a.desc and .grid-view table.items th a.asc). You can also disable visual styles for the table by specifying an option: 'cssFile'=>false and set custom styles for grid.
In order to make the entire string anchor link is likely you will need to insert into each cell of the table with the necessary link url. To do this, add the following description of an array of strings:
'columns'=>array(
...
array(
'name'=>'name',
'value'=>'CHtml::link($data->name, "#myAnchor")',
'type'=>'html'
),
...
)
I am not sure what version of Yii you're working on, but let's try this code
<?php
'columns' => array(
array(
...
'type' => 'html',
'value'=>'CHtml::tag("a",array("class"=>"your-icon-class", "href"=>"#"))',
),
I have a custom module, inside:
/Block/Adminhtml//Edit/Tab/Form.php
I am adding a bunch of fields which relate to fields in a table - all works fine and dandy.
However, I have a button on the page which executes some JavaScript, like so:
$fieldset->addField('trigger', 'submit', array(
'name' => 'trigger',
'label' => 'test',
'value' => Mage::helper('modulename')->__('Submit'),
'style' => 'width:100px;',
'onclick' => $this->getProductChooserURL(),
));
Now, for the life of me, I cannot set the value of that button - at the minute, it just shows as a blank html button - I'm just trying to get it to say something on it!
Someone else has had a similar problem here:
http://www.magentocommerce.com/boards/viewthread/283801/#t397177
But I can't make sense of the solution.
Hello if you want call javascript following code may be help you
$eventElemall=$fieldset->addField('trigger', 'submit', array(
'name' => 'trigger',
'label' => 'test',
'value' => Mage::helper('modulename')->__('Submit'),
'style' => 'width:100px;',
'onclick' => "getProductChooserURL()",
));
$eventElemall->setAfterElementHtml('
<script type="text/javascript">
function getProductChooserURL(){
document.getElementById("trigger").value }
</script>');
I have a gridview which contains a checkbox column and also uses pagination. When I check some checkboxes in the first page and navigate to the second page and check another one in the second page, the options I checked in the first page is not retained there. Is it posssible to retain the checkbox values during pagination?
Code for Gridview is
$widget = $this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
//'filter' => $model,
'ajaxUpdate' => true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header' => 'Selected',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
array(
'name' => 'demo',
'type' => 'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
),
));
Edit:
Extension for remembering the selected options in gridview,check this link Selgridview
Thanks to bool.dev
You could use sessions/cookies to store the checked values. I'm not very sure how to make cookies work, so i'll tell you how to do it with sessions. Specifically the user session that yii creates.
Now to use sessions we need to pass the checked (and unchecked) ids to the controller, therefore we'll modify the data being sent to the controller on every ajax update(i.e between paginations), to do this we exploit the beforeAjaxUpdate option of CGridView.
I'm also using CCheckBoxColumn instead of the following in your code(of course you can modify the solution to suit your own needs):
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
GridView Changes:
<?php $this->widget('zii.widgets.grid.CGridView', array(
// added id of grid-view for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'id'=>'first-grid',
'dataProvider'=>$model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
// added this piece of code
'beforeAjaxUpdate'=>'function(id,options){options.data={checkedIds:$.fn.yiiGridView.getChecked("first-grid","someChecks").toString(),
uncheckedIds:getUncheckeds()};
return true;}',
'ajaxUpdate'=>true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
/* replaced the following with CCheckBoxColumn
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' =>'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
*/
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header'=>'Selected',
'id'=>'someChecks', // need this id for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'checked'=>'Yii::app()->user->getState($data->email_id)', // we are using the user session variable to store the checked row values, also considering here that email_ids are unique for your app, it would be best to use any field that is unique in the table
),
),
));
?>
Pay special attention to the code for beforeAjaxUpdate and CCheckBoxColumn, in beforeAjaxUpdate we are passing checkedIds as a csv string of all the ids(in this case email_ids) that have been checked and uncheckedIds as a csv string of all the unchecked ids, we get the unchecked boxes by calling a function getUncheckeds(), which follows shortly. Please take note here, that when i was testing i had used an integer id field (of my table) as the unique field, and not an email field.
The getUncheckeds() function can be registered like this anywhere in the view file for gridview:
Yii::app()->clientScript->registerScript('getUnchecked', "
function getUncheckeds(){
var unch = [];
/*corrected typo: $('[name^=someChec]') => $('[name^=someChecks]') */
$('[name^=someChecks]').not(':checked,[name$=all]').each(function(){unch.push($(this).val());});
return unch.toString();
}
"
);
In the above function pay attention to the selectors and each and push function.
With that done, we need to modify the controller/action for this view.
public function actionShowGrid(){
// some code already existing
// additional code follows
if(isset($_GET['checkedIds'])){
$chkArray=explode(",", $_GET['checkedIds']);
foreach ($chkArray as $arow){
Yii::app()->user->setState($arow,1);
}
}
if(isset($_GET['uncheckedIds'])){
$unchkArray=explode(",", $_GET['uncheckedIds']);
foreach ($unchkArray as $arownon){
Yii::app()->user->setState($arownon,0);
}
}
// rest of the code namely render()
}
That's it, it should work now.
For developing that scheme you would need to know working of what happens when you navigate.
When ever you navigate to a pagination page ajax calls are made and new data is received and it is fetched from CActive Record or what ever the data source. New data is in accordance of database records or source records. when you come back to previous page again Ajax call is made and content is updated so same comes as it is in database.
what i feel is you should save data of checked items temporary and make it permanent if action is made.
You can do something like this
<script type="text/javascript">
$("input:checkbox").click(function () {
var thisCheck = $(this);
if (thisCheck.is (':checked')){
// do what you want here, the way to access the text is using the
// $(this) selector. The following code would output pop up message with
// the selected checkbox text
$(this).val());
}
});
</script>
you can save temporary storage somewhere
Also make this work on normal form submit:
I wanted to add this as a comment on bool.dev's answer, but I do not have enough reputation to do that yet. So I had to put it in a separate answer.
bool.dev, your answer is great and it works well, thanx.
However, as intended, it only works when ajax calls update the gridview. I have the gridview forming part of a form, so I wanted it to also work on normal submission of the form, otherwise the checkboxes are not loaded again when there are other validation errors on the form.
So, in ADDITION to what you did, I added hidden fields on my form e.g.:
<input type="hidden" name='checkedBox1' id='checkedBox1' value=''>
<input type="hidden" name='uncheckedBox1' id='uncheckedBox1' value=''>
Then, before submitting the form, my sumbit button runs your getChecked() and getUncheckeds() functions and store their results in the hidden fields:
if ($('#checkedBox1').length >0) {$('[name=checkedBox1]').val(getChecked());}
if ($('#uncheckedBox1').length >0) {$('[name=uncheckedBox1]').val(getUncheckeds());}
In the controller, besides from checking for $_GET['checkedIds'], you also check for $_POST['checkedBox1'] and store its values to session in the same way you do for $_GET['checkedIds'], using the same session variable.
Do the same with $_POST['uncheckedBox1'].
That should work.
I want an alert that pops when user tries to click "add to favorite"
1) if there's no checkboxes checked.
2) I also want to know how to get the values of the checked boxes here's my current code on backend
<?php $this->widget('zii.widgets.grid.CGridView',array(
'id' => 'wsrecruitcvhead-grid',
'dataProvider' => $model->search(),
#'filter' => $model,
'columns' => array(
array(
'name' =>'',
'value' => 'CHtml::checkBox("rid[]",null,array("value"=>$data->ResumeID,"id"=>"rid_".$data->ResumeID))',
'type'=>'raw',
'htmlOptions' => array('width'=>5),
'visible' => !Yii::app()->user->isGuest,
),
array(
'name' => 'ResumeTitle',
'value' =>$model->ResumeTitle,
),
'ResumeSummaryIntroduction',
'Name',
array(
'class' => 'CButtonColumn',
'viewButtonUrl' => 'Yii::app()->createUrl("wsrecruitcvhead/view",array("id"=>$data["ResumeID"]))',
'template'=>'{view}',
),
),
));
?>
and here's the screen shot http://pastebin.com/sEpJBCiU
I hope this helps you.
Your code works just fine, just tried it. I would implement the functionality you mentioned using jQuery, like this:
<script type="text/javascript">
$("input:checkbox").click(function () {
var thisCheck = $(this);
if (thisCheck.is (':checked')){
// do what you want here, the way to access the text is using the
// $(this) selector. The following code would output pop up message with
// the selected checkbox text
$(this).val());
}
});
</script>
This code selects all those DOM elements of type checkbox, and then checks with the if condition if it is selected or not. Here you can find more information about this jQuery selector. jQuery is such a powerful tool!!
For get all seleccions of a Grid yii provides the follow code
var seleccions = ($.fn.yiiGridView.getSelection('id_my_cgridview'));
this return an array with the values of checkboxes selected