ECHO Variable include newline - php

Question

I have the following code:
<p><?php echo $item['desc']; ?></p>
The code pulls the following from the database:
Point 1
Point 2
Point 3
and displays it as: Point 1 Point 2 Point 3,
What do I need to do to get the new lines included, I've tried adding /n or tags into to the DB reference however it is not making any difference.

Answer 1

This should work
<p><?php echo nl2br($item['desc']); ?></p>
Otherwise:-
echo nl2br(str_replace(' ',"\n", $item['desc']));

Answer 2

The newline is included. It's just not displayed in the browser, because the HTML standard says so. If you want it displayed in the browser, change newline to <br> tags, e.g. using nl2br()

Answer 3

Maybe the newlines are being printed, but you need them to be <br> tags, so they will appear as newlines on the webpage? You can use the function nl2br() for that:
<p><?php echo nl2br($item['desc']); ?></p>

Answer 4

Try this
echo str_replace(' ',"\n", $item['desc']);

Answer 5

\n won't work because the string you print has to be processed by the browser in html.
Use <br> tag instead.

Answer 6

Try like
echo str_replace(' ',"<br>", $item['desc']);

Answer 7

I couldn't understand exactly what you want but probably it's something like this:
$string = "Point 1 Point 2 Point 3";
$string = preg_replace("/(point \d+ )/i", "\$1\r\n", $string);
echo $string
Output:
Point 1
Point 2
Point 3
Note: Use only nl2br (see other answers) if the new lines are already in the string but just not displayed.

Answer 8

if your code in one line like TEST TEST TEST you can use preg_replace function :
echo preg_replace("{[ ]+}","<br/>",$items['desc']);
if your string like this TEST 1 TEST 2 ... and your goal is :
TEST 1
TEST 2
... so on..
you can use this pattern:
$t = preg_match_all("{[\w]+[ ]?[0-9]+}",$items['desc'],$m);
foreach ($m[0] as $val) { echo $val."<br/>"; }