PHP Weeknumber and start date and end date - php

I am writing a program code to display the week-number between two dates. I als0 want to display the dates between the week-number. I have written the following code as per the example codes from stack overflow.(here && here)
function getStartAndEndDate($week, $year)
{
$time = strtotime("1 January $year", time());
$day = date('w', $time);
$time += ((7*$week)+1-$day)*24*3600;
$return[0] = date('dMY', $time);
$time += 6*24*3600;
$return[1] = date('dMY', $time);
return $return;
}
$startTime = strtotime('2013-04-01');
$endTime = strtotime('2013-05-03');
$weeks = array();
while ($startTime < $endTime)
{
$weeks[] = date('W', $startTime);
$startTime += strtotime('+1 week', 0);
}
echo count($weeks)."<br/>";
$year="2013";
foreach ($weeks as $key => $w)
{
echo "Week Number:".$w."--";
$return=getStartAndEndDate($w,$year);
$r0=$return[0];
$r1=$return[1];
echo "Start-".$r0."-End-".$r1."<br/>";
}
But the output is wrong. Output shows:
5
Week Number:14--Start-07Apr2013-End-13Apr2013
Week Number:14--Start-07Apr2013-End-13Apr2013
Week Number:15--Start-14Apr2013-End-20Apr2013
Week Number:16--Start-21Apr2013-End-27Apr2013
Week Number:17--Start-28Apr2013-End-04May2013
14th week starts from 31Mar2013 to 6Apr2013. I couldn't figure out what the problem is. Any help must be appreciated!

Did you try to check with date
$startTime = strtotime('2012-12-30');
$endTime = strtotime('2013-05-03');
The actual14th week is
Week Number:14--Start-08Apr2013-End-14Apr2013
not
14th week starts from 31Mar2013 to 6Apr2013
The PHP start weeks from Monday -->Sunday. So if you take 2012-12-30 which is Sunday it will calculate
Week Number:01--Start-07Jan2013-End-13Jan2013
Week Number:02--Start-14Jan2013-End-20Jan2013
Week Number:03--Start-21Jan2013-End-27Jan2013
Week Number:04--Start-28Jan2013-End-03Feb2013
Week Number:05--Start-04Feb2013-End-10Feb2013
Week Number:06--Start-11Feb2013-End-17Feb2013
Week Number:07--Start-18Feb2013-End-24Feb2013
Week Number:08--Start-25Feb2013-End-03Mar2013
Week Number:09--Start-04Mar2013-End-10Mar2013
Week Number:10--Start-11Mar2013-End-17Mar2013
Week Number:11--Start-18Mar2013-End-24Mar2013
Week Number:12--Start-25Mar2013-End-31Mar2013
Week Number:13--Start-01Apr2013-End-07Apr2013
Week Number:14--Start-08Apr2013-End-14Apr2013

I have figured it out:
function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
$wk_ts = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
$mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
return date($format, $mon_ts);
}
$year="2013";
$startDate="2012-12-30";
$endDate="2013-05-03";
$p = new DatePeriod(
new DateTime($startDate),
new DateInterval('P1W'),
new DateTime($endDate)
);
foreach ($p as $k=>$w) {
echo $k.":".$w->format('W')."<br/>";
$w=$w->format('W');
$sStartDate = week_start_date($w, $year);
$sEndDate = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));
echo $sStartDate."&&".$sEndDate."<br/>";
}

Related

php how to store monday to friday of the next 6 months begin from tomorrow in an array

I am making a page to let the clients choose a date for an appointment, so I need to build a list of the dates like this :
always begin from tomorrow, end by 6 months
always from Mondy to Saturday, no Sunday
the day of the week need to be in chinese, like "Monday" is "星期一", but the timezone is in France
Here is the php
date_default_timezone_set('Europe/Paris');
$tomorrow = date("Y年m月d日 l", time() + 86400);
$end = date("Y年m月d日 l", time() + 86400 * 7); // just 7 days for a try
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($tomorrow, $interval, $end);
foreach ($daterange as $date) {
echo $date . '<br/>';
}
This code is not working.
I need to build an array, which store all the dates of next 6 months, begin from tomorrow, without Sunday, the days need to be in chinese and the timezone needs to be in Europe, is that possible?
I think strtotime and array_push is what you are looking for. Try this:
$curDate = date('Y-m-d', strtotime('+1 day'));
$endDate = date('Y-m-d', strtotime('+6 months +1 day'));
$myArr = array();
while ($endDate >= $curDate) {
if (date('w', strtotime($curDate)) !== '0') array_push($myArr, $curDate);
$curDate = date('Y-m-d', strtotime($curDate . " +1 days"));
}
var_dump($myArr);
For the Options, create an array from sunday to saturday.
$weekdays = array('Sunday', ..., 'Saturday');
echo date('Y/m/d', strtotime($curDate)) . ' ' . $weekdays[date('w', strtotime($curDate))];

get start and end date of month by week number of the month in php

How do I compute the start and end date of a week by month, year, and week number? The year is a 4-digit integer, such as 2016; the month is an integer, range 1-12; the week is an integer in the range 1-5.
I already have this code block:
function getStartAndEndDate($week, $year)
{
$time = strtotime("1 $year", time());
$day = date('w', $time);
$time += ((7 * $week) + 1 - $day) * 24 * 3600;
$return[0] = date('Y-n-j', $time);
$time += 6 * 24 * 3600;
$return[1] = date('Y-n-j', $time);
return $return;
}
How can I use or rewrite this function?
As for your function above in the question I have no idea, but assuming the week starts on Monday and ends on Sunday something like this might work
function getFirstandLastDate($year, $month, $week) {
$thisWeek = 1;
for($i = 1; $i < $week; $i++) {
$thisWeek = $thisWeek + 7;
}
$currentDay = date('Y-m-d',mktime(0,0,0,$month,$thisWeek,$year));
$monday = strtotime('monday this week', strtotime($currentDay));
$sunday = strtotime('sunday this week', strtotime($currentDay));
$weekStart = date('d M y', $monday);
$weekEnd = date('d M y', $sunday);
return $weekStart . ' - ' . $weekEnd;
}
echo getFirstandLastDate( 2016, 1, 1 );

how can I get last week' date range in php?

how can I get last week' date range in php ?
see my codes bellow:
<?php
function get_last_week_dates(){
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
}
?>
You can use strtotime()
$previous_week = strtotime("-1 week +1 day");
$start_week = strtotime("last sunday midnight",$previous_week);
$end_week = strtotime("next saturday",$start_week);
$start_week = date("Y-m-d",$start_week);
$end_week = date("Y-m-d",$end_week);
echo $start_week.' '.$end_week ;
UPDATE
Changed the code to handle sunday. If the current day is sunday then - 1 week will be previous sunday and again getting previous sunday for that will go the one week back.
$previous_week = strtotime("-1 week +1 day");
In addition if we need to find the current week and next week date
range we can do as
Current week -
$d = strtotime("today");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Next Week -
$d = strtotime("+1 week -1 day");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Simply use
date("m/d/Y", strtotime("last week monday"));
date("m/d/Y", strtotime("last week sunday"));
It will give the date of Last week's Monday and Sunday.
you need you use strtotime function for this
<center>
<?php
function get_last_week_dates()
{
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
$startdate = "last monday";
if (date('N') !== '1')
{
// it's not Monday today
$startdate .= " last week";
}
echo "<br />";
$day = strtotime($startdate);
echo date('r', $day);
echo "<br />";
$sunday = strtotime('next monday', $day) - 1;
echo date('r', $sunday);
}
get_last_week_dates();
?>
</center>
Well just for the fun of trying to solve this:
date_default_timezone_set('UTC');
$firstDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-7);
$lastDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-1);
echo("Last week began on: ".date("d.m.Y",$firstDayOfLastWeek));
echo("<br>");
echo("Last week ended on: ".date("d.m.Y",$lastDayOfLastWeek));
This should do the trick
$startWeek = date('Y-m-d',strtotime("Sunday Last Week"));
$endWeek = date('Y-m-d',strtotime("Sunday This Week"));
this would not work if ran on a Monday. It would get last Sunday (the day before) to the next Sunday. So using Abhik Chakraborty's method with the above:
$startTime = strtotime("last sunday midnight",$previous_week);
$endTime = strtotime("next sunday midnight",$startTime);
$startDate = date('Y-m-d 00:00:00',$startTime);
$endDate = date('Y-m-d 23:59:59',$endTime);
This will now give
start = 2014-08-10 00:00:00
endDate = 2014-08-17 23:59:59
I know this is old but here's a much more succinct way of doing it:
$startDate = date("m/d/y", strtotime(date("w") ? "2 sundays ago" : "last sunday"));
$endDate = date("m/d/y", strtotime("last saturday"));
echo $startDate . " - " . $endDate
This one will produce the proper result and handles the Monday issue
<?php
$monday = strtotime("last monday");
$monday = date('W', $monday)==date('W') ? $monday-7*86400 : $monday;
$sunday = strtotime(date("Y-m-d",$monday)." +6 days");
$this_week_sd = date("Y-m-d",$monday);
$this_week_ed = date("Y-m-d",$sunday);
echo "Last week range from $this_week_sd to $this_week_ed ";
?>
Most of those other solutions offered were off by one day.
If you want Sunday to Saturday for last week, this is the way to do it.
$start = date("Y-m-d",strtotime("last sunday",strtotime("-1 week")));
$end = date("Y-m-d",strtotime("saturday",strtotime("-1 week")));
echo $start. " to ".$end;
Carbon
$startOfTheWeek = Carbon::now()->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::now()->subWeek(1)->endOfWeek();
From a specific date
$startOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->endOfWeek();
Considering the week starts at Monday and ends at Sunday.
You can do this way.
First get the current timestamp and subtract the no.of days you want.
$curTime = time();
echo date("Y-m-d",$curTime);
echo "<br />";
echo date("Y-m-d",($curTime-(60*60*24*7)));
$lastWeekStartTime = strtotime("last sunday",strtotime("-1 week"));
$lastWeekEndTime = strtotime("this sunday",strtotime("-1 week"));
$lastWeekStart = date("Y-m-d",$lastWeekStartTime);
$lastWeekEnd = date("Y-m-d",$lastWeekEndTime);
In order to find the last week start date and end date you can follow up this code for doing it so.
It works on all intervals to find the date interval.
$Current = Date('N');
$DaysToSunday = 7 - $Current;
$DaysFromMonday = $Current - 1;
$Sunday = Date('d/m/y', strtotime("+ {$DaysToSunday} Days"));
$Monday = Date('d/m/y', strtotime("- {$DaysFromMonday} Days"));
If so you need to change it with the datatime() you can perform this function.
$date = new DateTime();
$weekday = $date->format('w');
$diff = 7 + ($weekday == 0 ? 6 : $weekday - 1); // Monday=0, Sunday=6
$date->modify("-$diff day");
echo $date->format('Y-m-d') . ' - ';
$date->modify('+6 day');
echo $date->format('Y-m-d');
Using Functions:
If you want to find the last week range with the help of the functions you can preform like this.
Function:
// returns last week's range
function last_week_range($date) {
$ts = strtotime("$date - 7 days");
$start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
return array(
date('Y-m-d', $start),
date('Y-m-d', strtotime('next saturday', $start))
);
}
Usage:
$today=date();
print_r(last_week_range($today));
All the above functions that has been given will return the last week range irrespective of the start day of the week..

How to find get week duration or week range from sunday to friday in php

How to find get week duration or week range from monday to friday for the given date in php.
for example i have date
$date = "2013-02-24";
Now i want range of date from monday to friday for the month
Just Try Out this answer.
$date = "2013-02-24";
$week = date('W', strtotime($date));
$year = date('o', strtotime($date));
echo "first day of week". $from = date("Y-m-d", strtotime("{$year}-W{$week}-1"));
echo "end day of week". $to = date("Y-m-d", strtotime("{$year}-W{$week}-5"));
function week_range($date) {
$ts = strtotime($date);
$start = (date('w', $ts) == 0) ? $ts : strtotime('last monday', $ts);
return array(date('Y-m-d', $start),
date('Y-m-d', strtotime('next friday', $start)));
}
And call it like this:
list($start_date, $end_date) = week_range('2009-05-10');

Get first day of week in PHP?

Given a date MM-dd-yyyy format, can someone help me get the first day of the week?
Here is what I am using...
$day = date('w');
$week_start = date('m-d-Y', strtotime('-'.$day.' days'));
$week_end = date('m-d-Y', strtotime('+'.(6-$day).' days'));
$day contains a number from 0 to 6 representing the day of the week (Sunday = 0, Monday = 1, etc.).
$week_start contains the date for Sunday of the current week as mm-dd-yyyy.
$week_end contains the date for the Saturday of the current week as mm-dd-yyyy.
Very simple to use strtotime function:
echo date("Y-m-d", strtotime('monday this week')), "\n";
echo date("Y-m-d", strtotime('sunday this week')), "\n";
It differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
Output for 4.3.5 - 5.2.17
2015-03-23
2015-03-22
Output for 4.3.0 - 4.3.4
2015-03-30
2015-03-29
Comparing at Edge-Cases
Relative descriptions like this week have their own context. The following shows the output for this week monday and sunday when it's a monday or a sunday:
$date = '2015-03-16'; // monday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
$date = '2015-03-22'; // sunday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
Againt it differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.5 - 5.0.5, 5.2.0 - 5.2.17
2015-03-16
2015-03-22
2015-03-23
2015-03-22
Output for 5.1.0 - 5.1.6
2015-03-23
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.0 - 4.3.4
2015-03-23
2015-03-29
2015-03-30
2015-03-29
strtotime('this week', time());
Replace time(). Next sunday/last monday methods won't work when the current day is sunday/monday.
Keep it simple :
<?php
$dateTime = new \DateTime('2020-04-01');
$monday = clone $dateTime->modify(('Sunday' == $dateTime->format('l')) ? 'Monday last week' : 'Monday this week');
$sunday = clone $dateTime->modify('Sunday this week');
?>
Source : PHP manual
NB: as some user commented the $dateTime value will be modified.
$givenday = date("w", mktime(0, 0, 0, MM, dd, yyyy));
This gives you the day of the week of the given date itself where 0 = Sunday and 6 = Saturday. From there you can simply calculate backwards to the day you want.
This question needs a good DateTime answer:-
function firstDayOfWeek($date)
{
$day = DateTime::createFromFormat('m-d-Y', $date);
$day->setISODate((int)$day->format('o'), (int)$day->format('W'), 1);
return $day->format('m-d-Y');
}
var_dump(firstDayOfWeek('06-13-2013'));
Output:-
string '06-10-2013' (length=10)
This will deal with year boundaries and leap years.
EDIT: the below link is no longer running on the version of PHP stated. It is running on PHP 5.6 which improves the reliability of strtotime, but isn't perfect! The results in the table are live results from PHP 5.6.
For what it's worth, here is a breakdown of the wonky behavior of strtotime when determining a consistent frame of reference:
http://gamereplays.org/reference/strtotime.php
Basically only these strings will reliably give you the same date, no matter what day of the week you're currently on when you call them:
strtotime("next monday");
strtotime("this sunday");
strtotime("last sunday");
Assuming Monday as the first day of the week, this works:
echo date("M-d-y", strtotime('last monday', strtotime('next week', time())));
The following code should work with any custom date, just uses the desired date format.
$custom_date = strtotime( date('d-m-Y', strtotime('31-07-2012')) );
$week_start = date('d-m-Y', strtotime('this week last monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week next sunday', $custom_date));
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
I tested the code with PHP 5.2.17 Results:
Start: 30-07-2012
End: 05-08-2012
How about this?
$first_day_of_week = date('m-d-Y', strtotime('Last Monday', time()));
$last_day_of_week = date('m-d-Y', strtotime('Next Sunday', time()));
This is what I am using to get the first and last day of the week from any date.
In this case, monday is the first day of the week...
$date = date('Y-m-d') // you can put any date you want
$nbDay = date('N', strtotime($date));
$monday = new DateTime($date);
$sunday = new DateTime($date);
$monday->modify('-'.($nbDay-1).' days');
$sunday->modify('+'.(7-$nbDay).' days');
Here I am considering Sunday as first & Saturday as last day of the week.
$m = strtotime('06-08-2012');
$today = date('l', $m);
$custom_date = strtotime( date('d-m-Y', $m) );
if ($today == 'Sunday') {
$week_start = date("d-m-Y", $m);
} else {
$week_start = date('d-m-Y', strtotime('this week last sunday', $custom_date));
}
if ($today == 'Saturday') {
$week_end = date("d-m-Y", $m);
} else {
$week_end = date('d-m-Y', strtotime('this week next saturday', $custom_date));
}
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
Output :
Start: 05-08-2012
End: 11-08-2012
How about this?
$day_of_week = date('N', strtotime($string_date));
$week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
$week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Just use date($format, strtotime($date,' LAST SUNDAY + 1 DAY'));
Try this:
function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
$wk_ts = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
$mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
return date($format, $mon_ts);
}
$sStartDate = week_start_date($week_number, $year);
$sEndDate = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));
(from this forum thread)
This is the shortest and most readable solution I found:
<?php
$weekstart = strtotime('monday this week');
$weekstop = strtotime('sunday this week 23:59:59');
//echo date('d.m.Y H:i:s', $weekstart) .' - '. date('d.m.Y H:i:s', $weekstop);
?>
strtotime is faster than new DateTime()->getTimestamp().
$monday = date('d-m-Y',strtotime('last monday',strtotime('next monday',strtotime($date))));
You have to get next monday first then get the 'last monday' of next monday. So if the given date is monday it will return the same date not last week monday.
$string_date = '2019-07-31';
echo $day_of_week = date('N', strtotime($string_date));
echo $week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
echo $week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Given PHP version pre 5.3 following function gives you a first day of the week of given date (in this case - Sunday, 2013-02-03):
<?php
function startOfWeek($aDate){
$d=strtotime($aDate);
return strtotime(date('Y-m-d',$d).' - '.date("w",$d).' days');
}
echo(date('Y-m-d',startOfWeek("2013-02-07")).'
');
?>
$today_day = date('D'); //Or add your own date
$start_of_week = date('Ymd');
$end_of_week = date('Ymd');
if($today_day != "Mon")
$start_of_week = date('Ymd', strtotime("last monday"));
if($today_day != "Sun")
$end_of_week = date('Ymd', strtotime("next sunday"));
If you want Monday as the start of your week, do this:
$date = '2015-10-12';
$day = date('N', strtotime($date));
$week_start = date('Y-m-d', strtotime('-'.($day-1).' days', strtotime($date)));
$week_end = date('Y-m-d', strtotime('+'.(7-$day).' days', strtotime($date)));
A smart way of doing this is to let PHP handle timezone differences and Daylight Savings Time (DST). Let me show you how to do this.
This function will generate all days from Monday until Friday, inclusive (handy for generating work week days):
class DateTimeUtilities {
public static function getPeriodFromMondayUntilFriday($offset = 'now') {
$now = new \DateTimeImmutable($offset, new \DateTimeZone('UTC'));
$today = $now->setTime(0, 0, 1);
$daysFromMonday = $today->format('N') - 1;
$monday = $today->sub(new \DateInterval(sprintf('P%dD', $daysFromMonday)));
$saturday = $monday->add(new \DateInterval('P5D'));
return new \DatePeriod($monday, new \DateInterval('P1D'), $saturday);
}
}
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday() as $day) {
print $day->format('c');
print PHP_EOL;
}
This will return datetimes Monday-Friday for current week. To do the same for an arbitrary date, pass a date as a parameter to DateTimeUtilities ::getPeriodFromMondayUntilFriday, thus:
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00') as $day) {
print $day->format('c');
print PHP_EOL;
}
//prints
//2017-01-02T00:00:01+00:00
//2017-01-03T00:00:01+00:00
//2017-01-04T00:00:01+00:00
//2017-01-05T00:00:01+00:00
//2017-01-06T00:00:01+00:00
Only interested in Monday, as the OP asked?
$monday = DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00')->getStartDate()->format('c');
print $monday;
// prints
//2017-01-02T00:00:01+00:00
You parse the date using strptime() and use date() on the result:
date('N', strptime('%m-%d-%g', $dateString));
<?php
/* PHP 5.3.0 */
date_default_timezone_set('America/Denver'); //Set apprpriate timezone
$start_date = strtotime('2009-12-15'); //Set start date
//Today's date if $start_date is a Sunday, otherwise date of previous Sunday
$today_or_previous_sunday = mktime(0, 0, 0, date('m', $start_date), date('d', $start_date), date('Y', $start_date)) - ((date("w", $start_date) ==0) ? 0 : (86400 * date("w", $start_date)));
//prints 12-13-2009 (month-day-year)
echo date('m-d-Y', $today_or_previous_sunday);
?>
(Note: MM, dd and yyyy in the Question are not standard php date format syntax - I can't be sure what is meant, so I set the $start_date with ISO year-month-day)
I've come against this question a few times and always surprised the date functions don't make this easier or clearer. Here's my solution for PHP5 that uses the DateTime class:
/**
* #param DateTime $date A given date
* #param int $firstDay 0-6, Sun-Sat respectively
* #return DateTime
*/
function getFirstDayOfWeek(DateTime $date, $firstDay = 0) {
$offset = 7 - $firstDay;
$ret = clone $date;
$ret->modify(-(($date->format('w') + $offset) % 7) . 'days');
return $ret;
}
Necessary to clone to avoid altering the original date.
Another way to do it....
$year = '2014';
$month = '02';
$day = '26';
$date = DateTime::createFromFormat('Y-m-d H:i:s', $year . '-' . $month . '-' . $day . '00:00:00');
$day = date('w', $date->getTimestamp());
// 0=Sunday 6=Saturday
if($day!=0){
$newdate = $date->getTimestamp() - $day * 86400; //86400 seconds in a day
// Look for DST change
if($old = date('I', $date->getTimestamp()) != $new = date('I', $newdate)){
if($old == 0){
$newdate -= 3600; //3600 seconds in an hour
} else {
$newdate += 3600;
}
}
$date->setTimestamp($newdate);
}
echo $date->format('D Y-m-d H:i:s');
The easiest way to get first day(Monday) of current week is:
strtotime("next Monday") - 604800;
where 604800 - is count of seconds in 1 week(60*60*24*7).
This code get next Monday and decrease it for 1 week. This code will work well in any day of week. Even if today is Monday.
I found this quite frustrating given that my timezone is Australian and that strtotime() hates UK dates.
If the current day is a Sunday, then strtotime("monday this week") will return the day after.
To overcome this:
Caution: This is only valid for Australian/UK dates
$startOfWeek = (date('l') == 'Monday') ? date('d/m/Y 00:00') : date('d/m/Y', strtotime("last monday 00:00"));
$endOfWeek = (date('l') == 'Sunday') ? date('d/m/Y 23:59:59') : date('d/m/Y', strtotime("sunday 23:59:59"));
Here's a one liner for the first day of last week, and the last day of last week as a DateTime object.
$firstDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 7))
->setTime(0, 0, 0);
$lastDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 1))
->setTime(23, 59, 59);
Just to note that timestamp math can also be a solution. If you have in mind that 01.jan 1970 was a Thursday, then start of a week for any given date can be calculated with:
function weekStart($dts)
{ $res = $dts - ($dts+date('Z',$dts)+259200)%604800;
return $res + 3600*(date('I',$dts)-date('I',$res));
}
It is predictable for any timestamp and php version, using date-func ('Z', 'I') only for timezone and daylight-saving offsets. And it produces same results as:
strtotime(date('Y-m-d', $dts).' - '.(date('N', $dts)-1.' days');
and with (the best and the most elegant) mentioned:
strtotime('monday this week', $dts);

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